Functional English Code No. 101 Class XII (2012-13) One Paper Unitwise Allocation Unit Areas of Learning 1. 2. 3. 4. Advanced Reading Skills (Unseen Passages-two)* Effective Writing Skills Applied Grammar Literature + Value Based Question 3 Hours Annexure E -’E’E ’ Annexure ‘ Marks: 100 Marks 20 25 20 30+05 = 35 The Question Paper will include value based question(s) to the extent of 5 marks. SECTION A ADVANCED READING SKILLS 20 Marks 60 Periods Two unseen passages (including poems) with a variety
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Downloaded from WWW.STUDIESTODAY.COM Downloaded from WWW.STUDIESTODAY.COM English Core Code No. 301 Class XI Sample Question Paper Time : 3 hrs. M. Marks 80 General Instructions : This question paper is divided into five sections : Section A Reading Comprehension 15 Marks m 10 Marks o c y. Section D Text Books 20 Marks a d Section E Long Reading Text - Novelo 15 Marks t s e All questions are compulsory marks are indicated against each question :i d A - Reading u Section t .s (15 Marks) w w
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Sing Yin Secondary School First Term Examination‚ 2009 – 2010 Mathematics 1 Form 3 Full marks: 100 Answer ALL questions. Unless otherwise specified‚ all working must be clearly shown. The diagrams in this paper are not necessarily drawn to scale. Unless otherwise specified‚ numerical answers should either be exact or correct to 3 significant figures. 1. 2. Time allowed: 1.5 hours Simplify 2 8 + 24 . x 2 − 5x − 6 ‚ x 3 − 27 . ( ) (4 marks) Factorize (a) (b) (4 marks) (4
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q‚w are not state function. 82 But U is state function. 8. Enthalpy (H): At constant volume V = 0‚ qv = U So H = U + p. V‚ qp = H2 H1 = H H = U + P. V. 9. Relationship between qp‚ qv i.e. H& U It is H = U+ ng.RT or qp = qv + 10. ng.RT Exothermic and Endothermic reactions: H = –Ve for exothermic and H = +Ve for endothermic reaction i.e. evolution and absorption of heat. Eg C+O2 N2 + O 2 11. CO2 + 393.5 KJ‚ H = –393.5 KJ (exothermic) 2NO – 180.7 KJ‚ H
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Week 3 Ratio and Proportion |Q# |Problem |Show Your Work |Answer |Instructor Comments | |1. |Solve the proportion: | |.667 | | | |x/2 = 5/15 | | | | | |x
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Sc Science test KEY STAGE 3 TIER 5–7 Paper 1 First name ________________________________________________ Last name ________________________________________________ School ________________________________________________ 2009 Remember I The test is 1 hour long. I You will need: pen‚ pencil‚ rubber‚ ruler‚ protractor and calculator. I The test starts with easier questions. I Try to answer all of the questions. I The number of marks available
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CBSE TEST PAPER-03 CLASS - IX Science (Motion) 1. What does the slope of velocity – time graph give? (a) Distance (c) Acceleration (b) displacement (d) Change in velocity. [1] 2. The displacement of the body can be(a) Positive (c) Zero (b) negative (d) All of these. [1] 3. Which of the following gives both direction and magnitude(a) scalar (c) Both (b) vector (d) None. [1] 4. If a moving body comes to rest‚ then its acceleration is(a) Positive (c) Zero (b) negative
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AND AIMS 8 Overall Objective 8 Specific Aims 8 BACKGROUND AND SIGNIFICANCE 9 research design and methods 10 Overview 10 Population and Study Sample 10 Sample Size and Selection of Sample 10 Sources of Data 10 Collection of Data 10 Exposure Assessment 10 Data Management 10 Data Analysis Strategies 10 Ethics and Human Subjects Issues 10 Timeframes 10 Strengths and Weaknesses of the Study 11 Public Health Significance 12 Budget and Motivation 13 references 14
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in Systems Analysis Page 1 of 4 SA Semester 2 Examination 2013/2014 Sample Paper 1 : Object Oriented Analysis and Design Appendix B Matriculation Number : (fill in your matriculation number here) SA Semester 2 Examination 2013/2014 (Sample Paper 1 – Appendix B) Graduate Diploma in Systems Analysis Page 2 of 4 This page is intentionally left blank. SA Semester 2 Examination 2013/2014 (Sample Paper 1 – Appendix B) Graduate Diploma in Systems Analysis Page 3 of 4
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(v) − 15‚ 15 (ii) 3 x2 − 3 2 x + 1 (v) 4x2 + x + 1 (vi) –1‚ 4 3 (iii) x2 + 5 (vi) x2 – 4x + 1 EXERCISE 2.3 1. (i) Quotient = x – 3 and remainder = 7x – 9 (ii) Quotient = x2 + x – 3 and remainder = 8 (iii) Quotient = – x2 – 2 and remainder = – 5x + 10 2. 5. (i) Yes (ii) Yes (iii) No 3. –1‚ 1 4. g(x) = x2 – x + 1 (i) p(x) = 2x2 – 2x + 14‚ g(x) = 2‚ q(x) = x2 – x + 7‚ r(x) = 0 (ii) p(x) = x3 + x2 + x + 1‚ g(x) = x2 – 1‚ q(x) = x + 1‚ r(x) = 2x + 2 (iii) p(x) = x3 + 2x2 – x + 2‚ g(x) = x2 – 1‚ q(x)
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