Week Two Assignment
BUS308: Statistics for Managers
Tiffany Aldridge
January 9, 2012

Week Two Assignment

Chapter 4: 4.4, 4.20

4.4
Suppose that a couple will have three children. Letting B denote a boy and G denote a girl:

a. Draw a tree diagram depicting the sample space outcomes for this experiment

b. List the sample space outcomes that correspond to each of the following events: 1) All three children will have the same gender. BBB, GGG 2) Exactly two of the three children will be girls. BGG, GBG, GGB 3) Exactly one of the three children will be a girl. BBG, BGB, GBB 4) None of the three children will be a girl. BBB

c. Assuming that all sample space outcomes are equally likely, find the probability of each of the events given in part b.

1) Probability of all three children having the same gender:

P(BBB)= 1/8

P(GGG)= 1/8

P(BBB) + P(GGG)= 1/8 + 1/8 = 2/8 = 1/4 = .25

2) Probability of exactly two of the three children will be girls:

3) Probability of exactly one of the three children will be a girl:

P(BBG) + P(BGB) + P(GBB) = 1/8 + 1/8 + 1/8 = 3/8 = .375
4) Probability that none of the three children will be a girl:

P(BBB) = 1/8 = .125

4.20

John and Jane are married. The probability that John watches a certain television show is .4. The probability that Jane watches the show is .5. The probability that John watches the show, given that Jane does is .7.

a. Find the probability that both John and Jane watch the show.

b. Find the probability that Jane watches the show, given that John does.

c. Do John and Jane watch the show independently of each other? Justify your answer. No, John and Jane do not watch the show independently of each other. If John watched independently, then= this is not the situation as .7 ≠ .4. If Jane watched independently, then = this is not the situation as .875 ≠ .5.

...Gas Prices
Nathaniel Peters
BUS 308: Statistics for Managers
Instructor: Ali Choudhry
August 8, 2011
Gas Prices
Delivery service is a way of life. Each day, people get packages sent to them by way of this service. But few people think of the costs the delivery company has to deal with. One of the main operating costs that we as a delivery company have is gasoline. We use gasoline daily in massive quantities. The cost of gas affects American’s daily, and people can be heard complaining about the high prices. What about delivery companies? In this paper, we will be discussing the effect of rising gas prices on our company throughout the next ten years.
Gas prices change daily, and throughout the year it is amazing to look at the monthly averages changing. In 2008 these averages varied from a low of 1.689 to a high of 4.09. That is a difference of 2.401, a huge difference within one year. So what is it that makes gas prices change so drastically? There is a formula of sorts to consider regarding why we pay what we pay for gasoline. The formula is: crude oil + refining process + retail sales/distribution + taxes = gasoline price. A good example of a sudden price change can be found in Hurricane Katrina. Many oil refineries and drilling operations were wiped out because of the hurricane, causing a spike in the gasoline prices because of the sudden decrease in supply. (Roy, 2010)
We at the delivery company have put together a data set to...

...Week 4 Assignment
BUS 308 Statistics for Managers
January 28, 2013
9.13) Recall that “very satisfied” customers give XYZ-Box video game system a ratting at least 42. Suppose that the manufacturer of XYZ-Box wishes to use the random sample of 65 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42.
a. Letting u represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis H0 and the alternative hypothesis Ha needed if we wish to attempt to provide evidence supporting the claim that µ exceeds 42.
H0: mu 42
b. The random sample of 65 satisfaction rating yields a sample mean of x = 42.954. Assuming that s equals 2.64, use critical values to test H0 versus Ha at each of a = .10, .05, .01, and .001.
z-statistic:
z = (xbar - µ)/(σ/√n)
z = (42.954 - 42 )/(2.64/√65)
z = 0.954 / (2.64/8.0623)
z = 2.9134
alpha z-crit result
0.10 1.282 significant
0.05 1.645 significant
0.01 2.326 significant
0.001 3.09 not significant
c. Using the information in part b, calculate the p-value and use it to test H0 versus Ha at each of a = .10, .05, .01, and .001.
Upper tail p- value for z = 2.9134 is 00018
Since 0.0018 < 0.10, 0.05 and 0.01, we reject Ho and accpt Ha at a = 0.10,
0.05 and 0.01, and conclude that the mean rating exceeds 42
Since 0.0018 > 0.001, we fail to reject Ho...

...Running head: WEEK 4 ASSIGNMENT 1
Week 4 Assignment
Sarah Doppelmayr
Statistics for ManagersBUS308
Edward Kaplan
January 28, 2013
WEEK 4 ASSIGNMENT 2
Week 4 Assignment
Chapter 9: 9.13 Recall that “very satisfied” customers give the XYZ-Box video game system a rating that is at least 42. Suppose that the manufacturer of the XYZ-Box wishes to use the random sample of 65 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42. A. Letting mew represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis H0 and the alternative hypothesis Ha needed if we wish to attempt to provide evidence supporting the claim that mew exceeds 42. H0: mu 42 B. The random sample of 65 satisfaction ratings yields a sample mean of x bar = 42.954. Assuming that sigma equals 2.64, use critical values to test H0 versus Ha at each of .10, .05, .01 and .001. z-statistic: z = (xbar - μ)/(σ/√n) z = (42.954 - 42 )/(2.64/√65) z = 0.954 / (2.64/8.0623) z = 2.9134 alpha z-crit result 0.10 1.282 significant 0.05 1.645 significant
WEEK 4 ASSIGNMENT 3
0.01 2.326 significant 0.001 3.09 not significant C. Using the information in part b, calculate the p-value and use it to test H0 versus Ha at each of...

...but I didn’t finish and then I decided to go back to school. I finally decided to start taking classes for information technology at Axia College Univ of Phoenix. I love working with computers and hope to make a career of it. I enjoy computers and have used them since 1996. I would love be in the online gaming industry one day and want to create something that millions of people see every day or be a part of something that will revolutionize the computer world.
My girlfriend had a baby girl on April 12th. She is such a beautiful girl and I love her very much. I am looking forward to this semester and speaking with everyone in class, I wish you all the best and hope that we can all learn from each other.
WeekTwo Individual Assignment
Daryl Christopher Yost
August 10, 2008
COMPUTERS AND INFORMATION PROCESSING CIS/319
Matthew Mancani
Accuracy of data input is important. What method of data input would be best for each of the following situations and explain why:
• Printed questionnaires
• Telephone survey
• Bank checks
• Retail tags
• Long documents
Printed Questionnaires
Printed questionnaires are a good method for data input but they will use up a lot of paper in the long run. Online questionnaires would be a better choice since people can type out their answers and store the information electronically. An online questionnaire...

...Library Search Worksheet
Use this worksheet to take notes about the articles you find when researching for Week 2 Assignment 1: University Library Search. Fill out each section of the tables for Article 1 and Article 2. You can also save a blank copy of this worksheet and use it to properly cite your sources when you write research papers for your future courses.
Article 1:
|Career Explored |Health Administration |
|Author | Arnold Mary |
|Year published | 71 |
|Title of article | Education for Administration of Health services |
|Title of Publication/Journal/ | Academic Journal, public Administration review |
|Magazine | |
|Volume/month of publication (if |Volume 31, Sept,Oct |
|available) | |
|Date you retrieved...

...
Week Five Assignment Questions
Sharnez Lipscomb
PSY/315
July 18, 2013
Dennis Outcalt
Week Five Assignment Questions
Chapter 7
14. | | | Evolutionary theories often emphasize that humans have adapted to their physical environment. One such theory hypothesizes that people should spontaneously follow a 24-hour cycle of sleeping and waking—even if they are not exposed to the usual pattern of sunlight. To test this notion, eight paid volunteers were placed (individually) in a room in which there was no light from the outside and no clocks or other indications of time. They could turn the lights on and off as they wished. After a month in the room, each individual tended to develop a steady cycle. Their cycles at the end of the study were as follows: 25, 27, 25, 23, 24, 25, 26, and 25.Using the .05 level of significance, what should we conclude about the theory that 24 hours is the natural cycle? (That is, does the average cycle length under these conditions differ significantly from 24 hours?) (a) Use the steps of hypothesis testing. (b) Sketch the distributions involved, (c) Explain your answer to someone who has never taken a course in statistics. x | | | |
| | | | | | |
25 | 0 | 0 | | | | | | | |
27 | 2 | 4 | | | | | | | |
25 | 0 | 0 | | | | | | | |
23 | -2 | 4 | | | | | | | |
24 | -1 | 1 | | | | | | | |
25 | 0 | 0 | | | | | | | |
26...

...however, vary in it interpretation of the Fourth Amendment and the protection it provides. In the case, Weeks v. United States (1914), the Supreme Court examines the Fourth Amendment protection against warrantless searches. In the case of Mapp v. Ohio (1961), the Supreme Court examined the Fourth Amendment protection against illegal search and seizure. In the case of Silverthorne Lumber Company, Inc., et al. v. United States (1920), the Supreme Court examined using of evidences collected from a business in a criminal case against individual. Additionally it also examines to limit the government knowledge obtained by the illegal search. These three cases pointed out the protection under the Fourth Amendment and it will continue to do so in our legal system.
Standards of Constitutional Searches and Seizures in the United States
The Fourth Amendment to the Constitution provides the protection for individual against unreasonable search and seizure by a government law enforcement entity. It outlines what a law enforcement officer or agency must do in order to search an individual’s home and/or person. However, this does always happen, we will discuss few court cases that have expanded and redefined the Fourth Amendment and the protection it affords all individuals.
Weeks v. United States. 232 U.S. 383 (1914)
In the case of Weeks v. United States, the defendant, Mr. Fremont Weeks was arrested by police at his work for...

...
1 - Produce the relevant descriptive graph and table to summarise the MODE variable (labelled Control: Completes by phone/mail/web). The MODE variable summarises the different ways that each institution completed the survey. Write a paragraph explaining the key features of the data observed through the output.
The distribution of the surveyance mode which was conducted for a sample of 2000. The mode is displayed in the above chart. The most common primary mode was the web (53.9%) it was above the average. The second and third in common was the Mail and the Phone – Full mode at 24% and 16.3% respectively, very few people uses the Phone – Short method (5.9%)
2 - Produce the relevant descriptive graph and table to summarise the OPSEXTOTM variable (labelled QB5b_num_mal. Male outpatients – Total). This variable measures the total number of male outpatients at each institution. Write a paragraph explaining the key features of the data observed through the output
The distribution of male outpatients at each institution in a sample of 2000 is displayed in the above histogram. The distribution is positively skewed with 50% below 96 cases or less. Typically male outpatient cases were between 30 and 223 with mean at 191.62 and standard deviation of 349.62. However there were quite a number of outliers with 3 significant outliers above 4000 cases in ID 2926, 7251 and 6751 and there were a number of institutions with 0 cases as...

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