This week concepts were of function problems which may include exponentials and logarithms within the functions. With these types of function we can find out information for breaking-even and profit analysis, compound interest, continuous compound interest and doubling time for an investment. Out of these concepts from this week lesson plan, currently understanding and using doubling time for an investment would be the most important.

In this world we live in today, the economy has taken a huge down turn due to major banks making their own share of poor investments. With this down turn in the global economy, many people had their Saving Accounts, 401Ks, and Pensions nearly wiped out. All these may be different types of investments we use to help pay for retirement, but they are essential to being able to retire at an early enough age. Otherwise a person would only have to look forward to working during their own golden years instead of taking it easy.

With the concept of doubling time for an investment, we can with some calculation figure out how long it would take for a certain sum of money, known as the principal, would take to double its value in a certain given time period at a certain given fix interest rate all at a certain interval. This is done with the equation A=P( 1+r/m)^mt. With this equation, to figure out t which is time for the principal to double, we can sub in 2P for A since the other known value are r the interest rate and m equals 1. Once we solve the equation for t we find the amount of time needed to double the investment made.

With the concept of this function, doubling time for an investment in use, a person can now safely and accurately predict the amount of time for growth in their investments. Within this global economic down turn, knowing and planning a financially secure future has become important for anyone in the general society. If more people were able to use this concept of doubling time for an investment, the...

...Week Two Exercise Assignment
Revenue and Expenses
1. Recognition of concepts. Jim Armstrong operates a small company that books entertainers for theaters, parties, conventions, and so forth. The company’s fiscal year ends on June 30. Consider the following items and classify each as either (1) prepaid expense, (2) unearned revenue, (3) accrued expense, (4) accrued revenue, or (5) none of the foregoing.
a. Interest owed on the company's bank loan, to be paid in early July
Prepaid expense
b. Professional fees earned but not billed as of June 30
Accrued revenue
c. Office supplies on hand at year-end
Prepaid expense
d. An advance payment from a client for a performance next month at a convention
Unearned revenue
e. The payment in part (d) from the client's point of view
Prepaid expense
f. Amounts paid on June 30 for a 1-year insurance policy
Prepaid expense
g. The bank loan payable in part (a)
None of the foregoing
h. Repairs to the firm's copy machine, incurred and paid in June
None of the foregoing
2. Understanding the closing process. Examine the following list of accounts:
Note Payable | Accumulated Depreciation: Building |
Alex Kenzy, Drawing | Accounts Payable |
Product Revenue | Cash |
Accounts Receivable | Supplies Expense |
Utility Expense |
Which of the preceding accounts
a. Appear on a post-closing trial balance?
Note Payable, Accounts Payable, Cash, Accounts...

... Andrew Smith
3 Copperfield close,
Malton,
North Yorkshire.
YO17 7YN
Dear John,
Hi it’s Andy here,
I am writing to you today following our recent conversation, with regards to you becoming a Support Worker.
If you do decide to work within the industry you will have a duty of care to the clients in your care, and this is a legal requirement.
All companies have to follow these policies and procedures ,as this ensures that you have your clients best interests at heart.
These procedures are put in place to ensure that the clients are not hurt in any way,or treated unfairly.This could include the client been discriminated against, neglected or taken advantage of in a number of ways.
You must always ensure that the care you give your client, is given in a safe manor, and according to National standards.
You should always treat your client as an individual, with individual needs. And their privacy should be respected at all...

...CLICK TO DOWNLOAD
MAT 540 Week2 Quiz
Question 1
If variable costs increase, but price and fixed costs are held constant, the break even point will decrease.
Question 2
Parameters are known, constant values that are usually coefficients of variables in equations.
Question 3
Probabilistic techniques assume that no uncertainty exists in model parameters.
Question 4
In general, an increase in price increases the break even point if all costs are held constant.
Question 5
P(A | B) is the probability of event A, if we already know that event B has occurred.
Question 6
A continuous random variable may assume only integer values within a given interval.
Question 7
The events in an experiment are mutually exclusive if only one can occur at a time.
Question 8
A bed and breakfast breaks even every month if they book 30 rooms over the course of a month. Their fixed cost is $4200 per month and the revenue they receive from each booked room is $180. What their variable cost per occupied room?
Question 9
The indicator that results in total revenues being equal to total cost is called the
Question 10
If the price increases but fixed and variable costs do not change, the break even point
Question 11
A university is planning a seminar. It costs $3000 to reserve a room, hire an instructor, and bring in the equipment. Assume it costs $25 per student for the administrators to provide the course materials. If...

...Mass
Index
By: Lashell Marrow
Instr: Shenita Talton
MAT 221: Introduction to Algebra
Date : April 7, 2013
The Body Mass Index (BMI) is an indicator to help people to determine if they might have a longer life span than average, are probably not overweight, are probably overweight, or are obese. The intervals for each are from 17 to 22, 23 to 24.999, 25 to 29.9, and over 30 respectively. Notice that it is between 17 and 22. That is not inclusive but rather a compound inequality statement which is 17 < BMI < 22. Moreover, over 30 is an inequality statement with a positive infinity which is any BMI that is greater than 30, or BMI > 30 which will be written as (30, +∞). Anyway, my BMI will be calculated, and I will explain how I arrived at the results. Sometimes, a person’s BMI can be misleading, so reasons will be provided about why. Finally, there is an evaluation of the regions outside of the “probably not overweight” range by using the set and interval notations along with a simple graph of the regions.
Now, I am five feet and eleven inches tall, and I weigh 180 pounds. Remember that one foot is equivalent to twelve inches. Since I am five feet tall, we will multiply five with twelve to get sixty. Now, I am an additional eleven inches taller than five feet, that is, sixty inches. Hence, we will add eleven inches to sixty inches to make that seventy one inches. The formula is:
BMI = (703W)/(H^2) where BMI is the Body Mass...

...
Two- Variable Inequalities
Lynwood Wright
MAT 222 Week2Assignment
Instructor: Dr. Stacie Williams
December 14, 2013
In Elementary Algebra we have learned how to solve systems of equations. The solution to a system of linear equations is the point where the graphs of the lines intersect. The solution to a system of linear inequalities is every point in a region of the graph where the inequalities overlap, rather than the point of intersection of the lines (Slavin, 2001).
This weekassignment required to solve problem 68 on page 539 (Dugopolski, 2012). I will be giving a detailed presentation on math required for the solution to this problem; the accompanying graph shows all of the possibilities for the number of refrigerators and the number of TVs that will fit into an 18-wheeler. The point-slope form of a linear equation to write the equation itself can now be used. These are the steps we take to solve our linear inequality. I will start with the point-slope form. Substitute slope form with (300, 0) for the x and y. Next we are going to use the distributive property and then add 330 to both sides and divided both sides by -3 and cancel out like terms.
The graph has a solid line rather than a dashed line indicating that points on the line itself are part of the solution set. This will be true anytime the inequality...

...119. Explain how to solve an exponential equation when both sides can be written as a power of the same base.
When an exponential equation has both sides of the equation as the same base one needs to rewrite the equation in the form of bM=bN. For instance, 24x-3=8. To make this the same base we need to make 8 a base of two by writing it as 2^3. Then we have 24x-3=23. Then we get rid of the base and get 4x-3=3. Finally we solve for x.
4x-3=3
4x=6
x=23
120. Explain how to solve an exponential equation when both sides cannot be written as a power of the same base. Use 3x = 140 in your explanation.
To solve this equation one needs to use a natural logarithm or ln.
First take the ln of both sides, ln 3x= ln 140
Then using bx= x ln b, move the variable to the front, x ln 3 = ln 140
Solve for x, x= ln3ln140= 1.0986122887/4.9416424226 = 0.22231723680404.
121. Explain the differences between solving log31x - 12 = 4 and log31x - 12 = log3 4.
When solving log31x - 12 = 4 one needs to write it in the form of bc=M. To do this we do the following; logbM=c means bc=M.
1) log31x - 12 = 4
2) 34=x-12
3) 81=x-12
4) x=93
In the case of log31x - 12 = log3 4, since the log is the same on both sides of the equation the will be omitted. The new equation would be; 1x-12=4. Then solve as normal. Add 12 to 4 to get 16, leaving 1x, which is just x and you have x=16.
122. In many states, a 17% risk of a car accident with a blood alcohol...

...Focus on Application: Week Two
Student’s Name
MAT/205
Due Date
Instructor’s Name
For the example of a ball being thrown up into the sky and then landing on the ground, we can model a quadratic equation to show the path of the projectile at various points in time (projectile motion). That is to say, each point plotted on the graph (parabola) will be a measurement to this effect:
Suppose a ball is thrown into the sky at a velocity of 64ft/sec from an initial height of 100ft. We would set the quadratic equation as (s)0=-gt^2+v0t+h0 and substitue values for gravity, velocity, and initial height to equal 0=-16t^2+64t+100. If we want to find out after how many seconds the ball will land, we can leave the equation set to zero and solve for t, using the quadratic formula. This will give us a solutions for t = SQRT(41)/2 (approximately 3.2 seconds) or t = -SQRT(41)/2 (approximately -3.2 seconds). Because we are only interested in positive values and negative values would not make any sense in this application, the ball will land after 3.2 seconds have passed, meaning that t = +3.2 seconds when the postion is at 0 or ground level; Position (3.2,0) on the Cartesian plane.
Also, knowing how to quickly calculate the vertex of such models as these comes in handy. It can give us the projectile’s (ball’s) maximum height value in this equation before it begins to descend. This is...

...REAL WORLD RADICAL FORMULAS
Krissel Aromin
MAT222 Week 3 Assignment
5/20/2014
Introduction
In this paper I will be discussing on radical formulas and how to solve for the formula that is given as C = 4d^-1/3b where d is the displacement in pounds and b is the beam width in feet. The exponent of -1/3 means that the cube root of d will be taken and then the reciprocal of the number will be used in the multiplication. These rules include accurately finding the cube and square root for numbers and understanding the application of the solution in sailboat stability (Example, 2013).
Sailboat Stability
In this paper we will need to solve problem #103 on page 605 Sailboat Stability (Dugopolski, 2012). In order to consider safe for ocean sailing the capsize screening value C should be less than 2. For a boat with a beam (width) b in feet and displacement d in pounds, C is determined by the function C=4d-1/3b (Dugopolski, 2012). In the beginning of the problem radicals look difficult at first, but the idea ranges through exponents and order of operations. To start out the problem we have to solve a, b, and c.
a) Find the capsize screening value for the Tartan 4100, which has a displacement of 23,245 pounds and a beam of 13.5.
C=4d-1/3b
C= 4(23245)-1/3(13.5) I have plugged in the values into the formula. Allowing the order of operations, the exponents are solved first (exponent computed by calculator)....

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