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single phase uncontrolled half wave rec

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single phase uncontrolled half wave rec
Experiment 1:
Simulation of 1 – φ half wave uncontrolled rectifier with R, RL and RLE load.
Aim of the Experiment:
To simulate 1 – φ half wave uncontrolled rectifier with
a) R load
b) RL load
c) RLE load.
And plot input voltage waveform, output current waveform, output voltage waveform and voltage across the diode.
Software Required:
(a) Windows Xp or above
(b) Matlab 7.0 or above
(c) Simulink 2.0 or above
Theory:
This is the simplest type of uncontrolled rectifier. It is never used in industrial applications because of its poor performance. In a single-phase half-wave rectifier, for one cycle of supply voltage, there is one half-cycle of output, or load, voltage. As such, it is also called single-phase one-pulse rectifier. Simulation is performed using R, RL and RLE load on the output side of the rectifier.
(a) R load :
The circuit diagram of a single-phase half-wave rectifier is shown in Fig.1.
During the positive half cycle, diode is forward biased, it therefore conducts from ωt = 00 to ωt = π. During the positive half cycle, output voltage v0 =source voltage vs and load current i0 = v0 /R.
At ωt = π, v0 = 0 and for R load, I0 is also zero. As soon as vs tends to become negative after ωt = π, diode D is reverse biased, it is therefore turned off and goes into blocking state. Output voltage, as well as output current, are zero from ωt = π to ωt =2π. After ωt = 2π, diode is again forward biased and conduction begins.

Figure 1 Diode rectifier with R Load

Average Value of output (or load) Voltage, v0= Rms value of output voltage, vor= =
(b) RL Load:
A single-phase one-pulse diode rectifier feeding RL load is shown in Fig 2. Current io continues to flow-even after source voltage vs has become negative. This is because of the presence of inductance L in the load circuit. After positive half cycle of source voltage, diode remains on, so the negative half cycle of source voltage appears across load until load current io decays to zero at ωt =β. Voltage vR

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