Calculations:
H = 0.97 m
θ = 0°
a = 9.81 m/s2
Time: t=2yat= 2(0.97m)9.81m/s2 t= 0.44 s
Davg= (D1+D2+D3+D4+D5)/n
= (2.146m+2.235m+2.234m+2.222m+2.225m)/5
= 2.212 m

Vox= Davgt Vy = Vosinθ-gt Vo = gxsinθcosθ
= 2.214m0.44s = 0-(9.81m/s2)(0.44s) = 9.81(2.62)sin45(cos45)
= 5.032 m/s = 4.312 m/ = 7.17 m/s

Discussion:
The two pictures below demonstrate the calculations from Trial 1 at 0° and Trial 1 at 45°. In this experiment we did five separate shots from the cannon at 0°, and 3 separate shots at 45°. We determined the average distance of the shots from each angle by using a meter stick. We were then able to calculate the velocity of the shots by dividing the time from distance. After getting the results, the distance from the shots fired at 45° had a greater distance from the shots fired at 0° horizontally. This is because as the ball which is fired increases, the height increases. As the height increases, the time it takes for the ball to hit the ground increases and the range (distance) is greater.

Conclusion:
One source of error comes from when we shot the cannon from the ground at a...

...Keith Beachy
College Physics 1 Lab - Section 001
CP1 LabReport - ProjectileMotion
October 12, 2009
The purpose of Lab Assignment 1 was to analyze projectilemotion. In doing so, we determined the initial velocity of the ball shot horizontally from the spring loaded projectile launcher. Also, we verified the angle at which the projection of the ball would produce a maximum range. Lastly, we predicted the range that a ball would travel at a certain angle, theta.
Projectilemotion is the motion of objects that are initially launched, or projected, and then continue moving with only the force of gravity acting upon it. The forces involved in projectilemotion are the initial velocity of the projected object at a certain angle and gravity acting downward on the object. The vector nature of forces can be used to determine how far an object launched can go and its initial velocity at an angle of 0 by finding its x and y components separately. The components of velocity are found by taking the initial velocity multiplied by sin for the y component, and cos for the x component. To find the initial velocity, we had to plug in specific values into the equation, v=0.5g(x/y), all raised to the one-half power, which was equal to 2.5 m/s. This equation is derived from the...

...Abstract
In this lab experiment the range equation will be used to calculate range of the launched rocket, initial velocity and distance traveled. Various projectiles will be tested at various angles and table heights for experiment one. Results will be compared to initial calculations. Despite human error and calculation error, the results still correlated with the hypothesis.
Introduction
Background
Acceleration is constant at 9.8 m/s2 because of the force of gravity. For experiment 1 the velocity will be calculated by measuring “x” and “y” and using the combined x & y equations to solve for Vo. Vo= x⌠g/2y. For experiment 2 the range equation for distance x=R is applicable since the launch and landing elevations are the same. R=(Vo2sin2ᶿ)/g
Objective
The objective of experiment one is to determine the distance a falling object will travel when the launch height is changed. The objective of experiment two is to observe the distance, x=R, a projectile will travel when the launch angle is changed. Acceleration is constant at 9.8 m/s2 in all the experiments due to gravity.
Hypothesis
Experiment 1: When the height is raised, the marble will have more time to continue traveling at its initial velocity while the gravitational force is acting upon it, increasing the distance the marble travels while falling.
Experiment 2: The range of the rocket will decrease as the angle launched moves away from 45 degrees.
Experiment...

...ProjectileMotion
Purpose:
An object in a projectilemotion move horizontally with no acceleration and vertically with the gravitational acceleration at the same time. This experiment is to investigate projectilemotion using experiments, equations and comparing the expected and experimental data.
Procedure:
Case I:
Use formulas to find equation of horizontal Range (R) in aprojectilemotion.
Rearrange equation for Rmax, and find the angle
Adjust the launches angle to angle
Launch the ball, measure Rmax
Use the equation to solve for initial speed
Case II:
Calculate new R=80/100Rmax
Use to calculate ()
Find out another expected angle , and find its relation with
Adjust the launch angle to , launch the ball and measure R
Adjust the launch angle to , launch the ball and measure R
Compare R1 and R2 with R
More Calculation:
Calculate components of velocity for both cases using expected value
Calculate maximum height for case I only
Data and Calculations:
In ProjectileMotion:
Horizontally (x-direction)：
a=0, v=V, X=vt,
Vertically (y-direction):
a=-g, y=vt-1/2gt
Also, v=vcos, v=vsin
We can get R=
Case I:
As -1≤sin2≤1, so sin(2)max=1, so Rmax=v/g, and =45
When the launch angle is 45， Rmax from experiment we get was 1.75m
Using equation, we can calculate for V==4.14m/s
Case II:...

...ProjectileMotion
You have probably watched a ball roll off a table and strike the floor. What determines where it will land? Could you predict where it will land? In this experiment, you will roll a ball down a ramp and determine the ball’s velocity with a pair of Photogates. You will use this information and your knowledge of physics to predict where the ball will land when it hits the floor.
[pic]
Figure 1
objectives
* MEASURE THE VELOCITY OF A BALL USING TWO PHOTOGATES AND COMPUTER SOFTWARE FOR TIMING.
* Apply concepts from two-dimensional kinematics to predict the impact point of a ball in projectilemotion.
* Take into account trial-to-trial variations in the velocity measurement when calculating the impact point.
Materials
|POWER MACINTOSH OR WINDOWS PC |PLUMB BOB |
|LABPRO OR UNIVERSAL LAB INTERFACE |RAMP |
|LOGGER PRO |TWO RING STANDS |
|TWO VERNIER PHOTOGATES |TWO RIGHT-ANGLE CLAMPS |
|BALL (1- TO 5-CM DIAMETER) |METER STICK OR METRIC...

...Title
ProjectileMotion
Abstract
A projectile was fired from atop an elevation and an angle. The initial velocity for each
firing was likely to be the same. The distance traveled in the horizontal direction was measured
for multiple firings of each trial, and the values were averaged. When the initial velocity for
each of these averages was calculated it was proved that the initial velocity was relatively
constant. These measurements had many possible sources of error including air resistance and
firing position. This lab increased understanding of projectilemotion.
Introduction
Projectilemotion occurs when an object in a two dimensional plane experiences motion
only due to gravity. Kinematic equations can be used to describe the components of projectilemotion. This allows us to analyze the motion. In this lab measurements will be taken to
determine the initial velocity of objects experiencing projectilemotion. This will first be done
for objects that are starting from a set elevation above the landing area. Then the initial velocity
will be found for objects that are launched from the floor at an angle to a landing area of the ...

...Name __ ProjectileMotion
Go to http://phet.colorado.edu/simulations/sims.php?sim=Projectile_Motion
and click on Run Now.
Pre Lab Reflections:
What are the
What forces are at play on a body under fall? Gravity plays a part in force on the weight of your body.
Make a prediction of which angle results in maximum range. I predict that the 45 degrees will result in max range.
Activity:
Open the sim, projectilemotion.
Familiarize yourself with the variables shown there.
Ensure the air resistance check box remains unchecked.
Using the mouse set the angle of projection(i) to 5 deg.
Alternatively enter the value in directly.
Set the initial speed to a value U=15m/s .
Click on Fire to start the projectile and record the corresponding value of the range R.
Repeat with values
i= 10,15,20,25,30,35,40,45,50,60,70,75,80,85.
Draw a graph of Range (R) against Angle of projection (i)
You may want your lay out to appear like in the table.
U=………
Angle (i)
Range(m)
5
9.7
10
12.2
15
14.9
20
17.5
30
21.8
35
23.2
40
24
45
24.1
50
23.6
55
22.4
60
20.6
65
18.1
70
15.2
75
11.8
80
8.1
85
4.1
From your graph,
Describe the shape of the graph obtained. Comment.
In a parabola -unimodal, bell-shaped distribution
Determine using the graph the angle for maximum range.
Looking at the graph it is 45 degrees
Post activity discussion:...

...ProjectileMotion
PHYS111
Formal Report 2
University of Canterbury
Campbell Moulder
Abstract
The force of gravity is said to be a constant of 9.81 ms-2 (3). This can be proved by measuring the projectilemotion of a bouncy ball and plotting a ∆Vertical Velocity vs. Time graph, the gradient of which should equal the constant force (acceleration due to) of gravity. Our gradient value of 10.26±0.49 ms-2 is consistent with the actual value of 9.81 ms-2.
Introduction
A projectile is an object that has been launched into the air. Once a projectile has been launched, the only forces acting are:
Air friction (this is considered negligible in our experiment)
Lift force, if the object is behaving like a wing (this is also negligible as our object is a ball)
Gravity, the weight force which acts downwards (this is the value we will be calculating in our experiment)
In our experiment we will measure the projectilemotion of a bouncy ball using the computer programme Motion Tracker. The results of this experiment will allow us to plot a ∆Vertical Velocity vs. Time graph. The only force that is affecting the ball that we are taking into account is the force due to gravity; therefore the gradient of this graph will give us the value of the force or acceleration due to gravity. The horizontal component is negligible because once the...

...Sir. In this report, we will talk about the concept of ProjectileMotion. Now, for you to have a clearer concept of what you had in mind about this and before I give you the definition, I want to start with giving you an example. So, I want you guys to help me in this. (Draws on the board as she tells the story) So imagine that there is this tall, crazy guy on jersey no. (insert no. here) who has a ball with him and he happened to be boarded with all of you on a plane which is now on almost half-way to your destination. So he made a scene by opening the door as you guys are flying and he is freaking out, almost screaming, (Changes voice) “Yo pilot! If you’re not gonna let me drop this ball, I’m gonna freak you all out!” and the pilot says, “Wooow, hold it right there. Okay, do whatever you want man, just please don’t threaten my physics-class passengers and hijack my plane.” Then the crazy man throws the ball. (Draws a curve path of the ball). Then the ball falls here after a second (draws a dot on the line), then here after a minute (another dot) and here after quite other minutes (another dot). The ball did not fall straight forward on the ground but it followed a curved path. This is because of the forces acting on it, like for one, gravity. So back in the story, the crazy man settled down on his seat and everyone on the plane went back to their businesses as if nothing happened. That my friends, the thing that happened with...