Km on both sides cancel out because we are dividing the same unit which leaves 57,783 multiplying to 1000m. This gives us 57,783,000m, but we have to turn it into scientific notation to make calculations easier. There is a decimal point in 57,783,000. and we move it 7 times to the left which automatically becomes 5.778 * 107. The exponent is 7 because we moved the decimal 7 times to the left producing a smaller number and is multiplied by 10 because it is a base (system of decimals). Now we have to convert 32.17 days to seconds.
(32.17days/24hours/ 60minutes /60seconds)/(days/hours/minutes) → s = 2,779,488s or 2.779 * 106
There are twenty four hours in a day, sixty minutes in an hours, and sixty seconds in a minute. We divide to cancel the units leaving us seconds and multiplying all the numbers. The answer in seconds is 2,779,488 seconds, and scientific notation of that is 2.779 * 106. Now that we have our numbers in meters and seconds, we can plug the number in the equation to evaluate the mass of Planet X.
Step 3
M =((4π^2 r^3 ))/(GP^2 ) G = 6.673*〖10〗^(-11) m^3 kg^(-1) s^(-2) r = 5.778*107 P = 2.779 * …show more content…
We still have to see if Planet X’s mass is enough to be considered a planet, so we have to divide the mass of planet x and the mass of earth which is 5.980 * 1024.
(1.478*〖10〗^22 kg)/(5.980*〖10〗^24 ) = .2472 * 10-2 kg
We divide the numbers and we get .2472 * 10-2. Now we simplify the scientific notation so we end with:
2.472 * 10-3
We multiply this scientific notation to 100 so we can find a percentage of the mass. The Scientific notation will convert to an actual decimal in order to find an accurate percentage of the mass of Planet X.
.002472 * 100 =
.247%
Conclusion
The mass of Planet X is .247% meaning it is less than 1% of mass. This is an unusually small number for a planet. Planet X has similar qualities to a planet, but its mass is too small. Even if Planet X is not a planet, there are many undiscovered planets waiting to be observed. It may seem a waste of time, but we learn new things through every calculation we make for every existent body in the galaxy.
Reference "International Astronomical Union | IAU." International Astronomical Union | IAU. Web. 21 Sept.