Treasure Hunt: Finding the Values of Right Angle Triangles
This final weeks course asks us to find a treasure with two pieces of a map. Now this may not be a common use of the Pythagorean Theorem to solve the distances for a right angled triangle but it is a fun exercise to find the values of the right angle triangle.

Buried treasure: Ahmed has half of a treasure map,which indicates that the treasure is buried in the desert 2x + 6 paces from Castle Rock. Vanessa has the other half of the map. Her half indicates that to find the treasure, one must get to Castle Rock, walk x paces to the north, and then walk 2x + 4 paces to the east. If they share their information, then they can find x and save a lot of digging. What is x?

So, if you walk x paces north, then 2x+4 paces east, you have moved roughly east northeast to a distance of 2x+6 paces. This is a right angle, with 2x+6 on the hypotenuse or line c, so we must solve using the Pythagorean Theorem:

a² + b² = c²add in the values
(x)² + (2x+4)² = (2x+6)²multiply inside the parenthesis x² + 4x² + 16x + 16 = 4x² + 24x + 36subtract 4x² + 24x + 36 from both sides x² - 8x - 20 = 0factor the quadratic equation
(x -10)(x + 2) = 0use zero factor property to solve
X – 10 = 0 or x + 2 = 0creating a compound equation
x = 10 or x = -2the answer cannot be – 2
x = 10
Now we will plug in the value and solve: x paces north and 2x + 4 paces east or 10 paces north and 2(10) + 4 = 24 paces east of Leaning Rock. Or 2x + 6 paces northeast or 2(10) + 6 = 26 paces northeast from the rock to reach the buried treasure.

In this exercise we learned how to find the value of a right angle triangle with one given point and two variables based off that point. I personally learned to take my time with a written out problem like this, as at first was a bit frustrated and confused with it. Overall this course MAT 221 has helped me quite a bit to refresh on my Algebra skills. Thank you for...

...Article Review 1
DeGeorge, B., Santoro, A. (2004). “Manipulatives: A Hands-On Approach to Math.” Principal, 84 (2), (28-28).
This article speaks about the importance and significance of the use of manipulatives in the classroom, specifically in the subject of math. Manipulatives have proven to be valuable when used in a math class and are even more valuable to the children when they are young, and are learning new math concepts. Students are able to physically visualize the math concepts and gain knowledge because they understand what they’re learning a whole lot better and they also are able to gain insights on those concepts. Different examples of manipulatives may include counting with beans or M&M’s, using pattern blocks, puzzles, tangrams, and flash cards, just to name a few.
Using manipulatives in a math class are beneficial to both the student and the teacher because the teacher is able to explain the concepts to the students in a much easier manner using the hands-on technique, rather than explaining it verbally. It’s especially beneficial to the student because by incorporating these manipulatives into their learning process, they are able to pick up the concepts much quicker and in a way that they better understand, yet are having fun while doing it. When they have the concepts down, the students’ self-esteem goes up and they feel encouraged to keep on going.
After...

...Formulas
Read the following instructions in order to complete this discussion, and review the example of how to complete the math required for this assignment:
• Read about Cowling’s Rule for child sized doses of medication (number 92 on page 119 of Elementary and Intermediate Algebra).
• Solve parts (a) and (b) of the problem using the following details indicated for the first letter of your last name:
|If your last |For part (a) of problem 92 use this information to calculate the child’s |For part (b) of problem 92 use this |
|name starts with letter|dose. |information to calculate the child’s |
| | |age. |
|A or Z |adult dose 400mg ibuprofen; 5 year old child |800mg adult, 233mg child |
|C or X |adult dose 500mg amoxicillin; 11 year old child |250mg adult, 52mg child |
|E or V |adult dose 1000mg acetaminophen; 8 year old child |600mg adult, 250mg child |
|G or T |adult dose 75mg Tamiflu; 6 year old child |500mg adult, 187mg child |
|I or R |adult dose 400mg ibuprofen; 7 year old child...

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Working with algebra you must understand why the properties of real numbers are so important. I will demonstrate my solutions to three problems and I will include my mathematical work. Also I will use five vocabulary words that help me find solutions to the problems. Properties of real numbers are useful for simplifying algebraic expression because a lot of thing we do in life are equations. We use a lot of mathematical terms in the real world. Lastly I will show every step I took to simplify and identify each property of real numbers.
The properties of algebra are important to know and understand. “Algebra is useful because it can be used to solve problems. Since problems are often communicated verbally, we must be able to translate verbal expressions into algebraic expressions and translate algebraic expressions into verbal expressions.” (Dugopolski, 2012, Chapter 1.6, ) Each expression has properties that must be simplified and solving methods. You have to know how to follow the order of operation and simplify the equations, variables and like terms in order to complete the mathematical work. Simplify is very important in all expression, must be in simplest form when completely an equations. Also you have to move and combine like terms. The coefficient of a number is in front of a variable. The coefficient is a factor that can produce a result. The distributive property is a step that multiples a term to be followed in order for the equation to be...

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ANALYSIS
Physics has a lot of topics to cover. In the previous experiments, we discussed Forces, Kinematics, and Motions. In this experiment, the focus is all about Friction. Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction like fluid friction which describes the friction between layers of a viscous fluid that are moving relative to each other; dry friction which resists relative lateral motion of two solid surfaces in contact and is subdivided into static friction between non-moving surfaces, and kinetic friction between moving surfaces; lubricated friction which is a case of fluid friction where a fluid separates two solid surfaces; skin friction which is a component of drag, the force resisting the motion of a fluid across the surface of a body; internal friction is the force resisting motion between the elements making up a solid material while it undergoes deformation and sliding friction.
When surfaces in contact move relative to each other, the friction between the two surfaces converts kinetic energy into heat. This property can have dramatic consequences, as illustrated by the use of friction created by rubbing pieces of wood together to start a fire. Kinetic energy is converted to heat whenever motion with friction occurs, for example when a viscous fluid is stirred. Another important consequence of many types of friction can be wear,...

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The case between Beauty and Stylish involves concept of a valid contract, pre-contractual statements, express term and misrepresentation.
A valid contract is established between Beauty and Stylish when an offer is accepted and there is intention for both parties to create legal relations. An offer refers to the expression of willingness of the offerer to be contractually bound by an agreement if his or her offer is properly accepted. It has to be clear and certain in terms. It must also be communicated to the offeree before it is being accepted. In addition, the acceptance has to be unqualified, unconditional and made by a positive act. In the case of Beauty and Stylish, a positive act refers to the signing of the contract. All terms of the offer must be accepted without any changes and cannot be subjected to any condition, taking effect only upon fulfillment of that condition. When Beauty and Stylish enter into the agreement, they must intend to bind and bound legally to each other by their agreement. This is the intention to create legal relations between two parties. In the meanwhile, this contract must possess consideration. A contract must therefore be a two-sided affair, with each side providing or promising to provide something of value in exchange for what the other is to provide.
Every contract, whether oral or written, contain terms. The terms of a contract set out the rights and duties of the parties. Terms are the promises and undertakings given by each...

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Buried Treasure
Ashford University
MAT 221
Buried Treasure
For this week’s Assignment we are given a word problem involving buried treasure and the use of the Pythagorean Theorem. We will use many different ways to attempt to factor down the three quadratic expressions which is in this problem. The problem is as, ““Ahmed has half of a treasure map, which indicates that the treasure is buried in the desert 2x + 6 paces from Castle Rock. Vanessa has the other half of the map. Her half indicates that to find the treasure, one must get to Castle Rock, walk x paces to the north, and then walk 2x + 4 paces to the east. If they share their information, then they can find x and save a lot of digging. What is x?”
First we will look at the equation so we know how far Ahmed will have to walk which is 2x + 6 paces from Castle Rock. If Ahmed used string and tied it to the Castle Rock point and labeled it as point “A” on paper it would be basically 2x + 6 paces. With this being the radius you will know that it is the same anyway you fit this from the circle. So to find the Treasure we will use “C”. Vanessa will use her compass to find north from Castle Rock. From there she will walk “X” paces in a straight line northward. At the end of her distance she will call this point “B”. Vanessa will now turn 90 degrees to the right and will walk 2x+4 paces east until she is at point “C”. We have now acquired a line segment...

...Math221
Week 2 Lab
Part 1. Random Sampling
1. To perform random sampling, I used the Data Analysis function under the Data tab. Once I clicked on Data Analysis I chose the Sampling function. I then chose the Input Range of data to be random sampled. I checked the Random Sampling Method and input the number of random samples to be selected, 20. I then chose Output Range in the Output Options area of the Sampling box and selected an area on my Excel document to display the output. I clicked OK and the random samples were automatically chosen and displayed in the appropriate chosen location on my Excel document. The Sampling method in the Data Analysis add-on pack is very important to use when truly random samples need to be taken from a group of data for analysis.
2.
Part 2. Cereal and Fiber Type
Fiber Type | Frequency | % fiber |
High Fiber | 22 | 26% |
Medium Fiber | 29 | 35% |
Low Fiber | 33 | 39% |
Total | 84 | 100% |
Part 3. Milk Production
1. The sample mean of the data is 2270.54 lbs. of milk production.
2. The sample standard deviation of the milk production is 653.1822.
3.
Milk Production |
Class Limits | | | Cumulative |
Lower | Upper | Midpoint | Frequency | Frequency |
1147 | 1646 | 1396.5 | 7 | 7 |
1647 | 2146 | 1896.5 | 15 | 22 |
2147 | 2646 | 2396.5 | 13 | 35 |
2647 | 3146 | 2896.5 | 11 | 46 |
3147 |...

...Assignment: Inequalities
Math221: Introduction to Algebra
Instructor Jonah Mutua
June 16, 2013
Inequalities
This assignment involves the use of inequalities in mathematical equations. The formula for finding Body Mass Index (BMI) is BMI =703W/H^2.
In this formula W = weight in pounds
In this formula H = height in inches.
For this assignment four intervals based on our own personal heights must be calculated. I am 6 feet 4 inches tall. My height in inches (or H) equals 76. These intervals include inequalities that are categorized as between or compound inequalities. One interval in this assignment will be a regular inequality. Wherever “BMI” appears in the inequalities, we will exchange the formula and solve the inequality for W to find the weight ranges that fit each category for my height.
The first interval calculates those who might have a longer than average life span. The compound inequality for this follows:
17<BMI<22
17<703W/76^2<22
17<703W/5776<22
17*5776<703W<22*5776
98192<703W<127072 (Dividing all by 703)
139.6756<W<180.7567
140<W<181
People with a height of 76 inches may have a longer lifespan if they weigh between 140 and 181 pounds (after rounding up).
Now we will do something a little different from the previous problem. Below we will solve the 2nd inequality for the formula for W prior to entering the...