# Math 133 Unit2

Unit 2 IP2

1. X^2-10x-24

a) X=4 x= -6

Show my work:

X^2-10x-24=0

A) 1

B) -10

C) -24

X^2-10x-24=0

(X-4) (x+6)

X-4=0 x=4

x+6=0 x= -6

B) 3x^2+7x-20=0

Answer: x=7+4=5.5 x= 7-4=1.5

Show my work:

X= -b±b2-4ac2a

X= (-7) ±(-7)2-4(3)(20)2a

X= 7±64-802a

X=7 ±-16

X=7+4/2=5.5

X=7-4/2=1.5

c.10x^2+x-3=0

x=-b±b2-4ac2a

x=-1±(1)2-4(10)(-3)2(10)

x=1±1-12020

x=1±10

x=1+320 = 5

x=1-320= 10

There are two types of solutions to this problem which are x=1+320 = 5 and x=1-320= 10

2.

a. The solution for this equation just by looking at the graph is (-2.3,0) and (0,6.3) b. This is a maximum function. The reason how I obtain my answer is because it is at the peak of the parabola c. (2, 9)

d. the equation is x=2

3.

a. s= -16t^2+64t+25

b. 73 Feet

Show my work:

S= -16◦(1)^2+64◦(1)+25

S= -16+64+25

S=73 feet

C Answer is 2 seconds

Show my work:

.-b2a= -642(-16)= -64/-32=2 seconds

d. Answer is 89 feet

Show my work

S= -16*(2)^2+64*(2)+25

S= 64+128+25= 89 feet

4. a.

x| y|

-2| 4|

-1| 0|

0| -2|

1| -2|

2| 0|

3| 4|

Show my work

Y=x^2-x-2 X=-2 x= -1 x=0 x=1 Y=-2^2-(-2)-2 y= -1^2-(-1)-2 y= 0^2-0-2 y=1^2-1-2 Y=4+2-2 y= 1+1 -2 y= -2 y= 1-1-2 Y=6-2 y= 2-2 y= 0-2 Y=4 y=0 y= -2

X=2 x=3

Y=2^2-2-2 y=3^2-3-2

Y=4-2-2 y=9-3-2

Y=2-2 y=6-2...

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