Mechanism 4 shows the debromination of 2α-bromocholestan-3-one to give 4. This mechanism which is similar to a Favoskii rearrangement, is likely to go via this path as other research has shown that there is often a by-product with this reaction. The by-product is cholest-4-en-3-one which requires the intermediate seen in the third molecule in the above mechanism. The intermediate is highly strained and with the presence of base a proton will be extracted which aids the collapse of the three membered ring. To gain the major product, 4, the H1 proton is removed, however it is very possible that the H4 proton is removed instead which would leave the minor product of cholest-4-en-3-one. Both products result in conjugation which will stabilise the molecule. The mechanism for this step is unlikely to go via a simple elimination as for an elimination the eliminated products must be trans to each other for facile leaving. As the bromine is equatorial in both the chair and the boat conformation the bromine is trans with neither of the hydrogens which shows this type of elimination is unlikely to occur. The other possibility is that the acidic hydrogen that is removed in the first step is not H4, but H2. This…