# Tension Lab

The three graphs were plotted using data collected during the experiment, Figure 1, 2 and 3 Figure 1

Figure 2

Figure 3

2. Determine the proportional limit of the test specimen:

Proportional limits are approximately as follows-

* copper is 8,888 psi

* Aluminum is 6,666 psi

* Polyester is 9,696 psi

3. Determine the Elastic Modulus of the specimens:

* The Modulus of Elasticity for copper specimen is 16,687 ksi., figure 4. * The Modulus of Elasticity for Aluminum specimen is 89,991 ksi, figure 5. * The Modulus of Elasticity for Polyester specimen is 136,532 ksi, figure 6. Figure 4

Figure 5

Figure 6

4. Determine the Modulus of resilience and toughness of samples: * Copper: resilience=2304.30 psi, toughness=73468.13 in*ib/in^3 * Aluminum: resilience= 987.53 psi, toughness =5360.80in*ib/in^3 * Polyester: resilience=125.69 psi, toughness =12353.05 in*lb/in^3 *The resilience was calculated using 1/2b*h at the point of proportional limit *The toughness was approximated by using total area under curve and applying Riemann Sum 5. Determine Engineering Ultimate and Breaking Strength of the samples tested: Copper UTS 22,222 & Breaking Strength 25,770 psi

Aluminum UTS 13,333 and Breaking Strength 18,933 psi

Polyester UTS 15,555 and Breaking Strength 20,266 psi

6. Percent Elongation at break: [Lf-lo/lo]*100

Copper =17%

Aluminum=4.44%

Polyester=18.76%

7. Compare published values including % differences and discuss the accuracy of the results: | MATERIAL TYPE| PUBLISHED | EXPERIMENTAL | Modulus Of Elasticity| Copper C110| 16,700 ksi| 16,687 ksi| | Aluminum Alloy 1000 series| 6.96-107,00 ksi| 89,991 ksi| | Polyester (Thermoplastic)| .377-1920 ksi| 136,522 ksi| Tensile, Ultimate| Copper C110| 36300 psi| 22,222 psi| | Aluminum Alloy 1000 series| 102-232,000 psi| 13,333 psi| | Polyester...

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