QUADRATIC FUNCTIONS (WORD PROBLEMS) 1. The area of a rectangle is 560 square inches. The length is 3 more than twice the width. Find the length and the width. Representation: Let L be the length and let W be the width. The length is 3 more than twice the width‚ so The area is 560‚ so Equation: Plug in and solve for W: Solution: Use the Quadratic Formula: Since the width can’t be negative‚ I get . The length is 2. The hypotenuse of a right triangle is 4 times the smallest side. The third
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the 0 a) M-3=0 Step 3. 2m+5=0 Divide each term in A by “2” Solve: a) m=-5/2 For the second problem the quadratic formula will be used to solve the equation. Since a=2y^2 b=3y c=6 and we know these are integers and two terms complete the square‚ we can also see in our equation we have the discriminant so we determine if we have a prime polynomial. Using the quadratic formula: Original equation: 2y^2-3y-6=0 Step 1: y=-b± b^2-4ac/(2a) so we will have our equation of ay^2+by+c=c
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• A quadratic function (f) is a function that has the form as f(x) = ax2 + bx + c where a‚ b and c are real numbers and a not equal to zero (or a ≠ 0). • The graph of the quadratic function is called a parabola. It is a "U" or “n” shaped curve that may open up or down depending on the sign of coefficient a. Any equation that has 2 as the largest exponent of x is a quadratic function. ☺Forms of Quadratic functions: * Quadratic functions can be expressed in 3 forms: 1. General form: f (x) = ax2
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REAL WORLD RADICAL FORMULAS Trisha Kelly MAT 222 Week 3 Assignment Jerry Bilbrey January 19‚ 2014 SOLVING REAL WORLD RADICAL FORMULAS As complicated as radical formulas appear‚ the concept actually just extends past our knowledge of exponents and orders of operations. In fact‚ solving formulas that contain radicals is the same as those without‚ given the rues of operations are followed. Finding the cubed and square roots of these numbers is part of those rules.
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This paperwork MAT 222 Week 3 Discussion Questions 1 comprises solutions on the following tasks: Find the rational exponent problems assigned to you in the table below. Simplify each expression using the rules of exponents and examine the steps you are taking. Incorporate the following five math vocabulary words into your discussion. Use bold font to emphasize the words in your writing (Do not write definitions for the words; use them appropriately in sentences describing the thought behind your
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MCR3U0: Unit 2 – Equivalent Expressions and Quadratic Functions Radical Expressions 1) Express as a mixed radical in simplest form. a) c) b) e) d) f) 2) Simplify. a) b) d) e) c) f) 3) Simplify. a) b) c) d) e) f) 4) Simplify. a) d) b) e) f) c) For questions 5 to 9‚ calculate the exact values and express your answers in simplest radical form. 5) Calculate the length of the diagonal of a square with side length 4 cm. 6) A square has an area of 450 cm2. Calculate the side length. 7) Determine
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school curriculum is just not enough to prepare students for the real world. Our schools have become too old-fashioned. Today‚ success in the real world is not about memorizing the periodic table or the quadratic equation. It’s not about studying for hours the night before a test to get a 100 percent‚ then forget it all the next week. School should be about how to apply these sciences and arts to the real world. In the real world‚ if you need to know something for your job‚ you look it up online
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MAT 222: Intermediate Algebra Title Page Solving a proportion as we learned this week‚ means that you are missing an import number in your equation or fraction‚ and you need to solve for that missing value. As in my example‚ I did not know what percentage of bills we each should pay. We knew each other’s salaries; but we really had to sit down‚ crunch numbers‚ and figure it out. For this week’s assignment we were asked to work through two proportions. For the first proportion‚ number
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Introduction The aim of this investigation is to identify the nature of the roots of quadratics and cubic functions. Part One Case One For Case One‚ the discriminant of the quadratic will always be equal to zero. This will result in the parabola cutting the axis once‚ or twice in the same place‚ creating a distinct root or two of the same root. For PROOF 1‚ the equation y=a(x-b)2 is used. PROOF 1 y = 3 (x – 2)2 = y = 3 (x2 – 4x + 4) = y = 3x2 – 12x + 12 ^ = b2 – 4ac = (-12)2 – 4 x 3 x
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Two- Variable Inequalities Lynwood Wright MAT 222 Week 2 Assignment Instructor: Dr. Stacie Williams December 14‚ 2013 In Elementary Algebra we have learned how to solve systems of equations. The solution to a system of linear equations is the point where the graphs of the lines intersect. The solution to a system of linear inequalities is every point in a region of the graph where the inequalities overlap‚ rather than the point of intersection of the lines (Slavin‚ 2001)
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