Analysis of Ribena Using Titration Essay Example

Title: Analysis of Vitamin C in Ribena Using Titration
Aim:
The objectives of this experiment were to gain knowledge on how to titrate solution and determine amount of Vitamin C in Ribena.
Results
Table 1: Mass of Ascorbic Acid in Volumetric Flask
Mass of empty bottle (g) 21.5922
Mass of empty bottle with ascorbic acid (g) 21.6954
Mass of empty bottle (g) 21.5924
Mass of ascorbic acid used (g) 0.1002
Number of moles: (mass of ascorbic acid used)/(molecular mass of ascorbic acid) = 0.1002g/(176.10gmol-1) = 5.69 x10-4 moles
M1: concentration of stock ascorbic acid V1: volume in volumetric flask with stock solution
M2: concentration of diluted ascorbic acid V2: volume in volumetric flask with diluted solution
(M1 x 100)/1000 = 5.69 x10-4 moles M1: 5.69 x10-3 mol/L
M1V1 = M2V2
5.69 x10-3 mol/L x (10/1000) = M2 x (100/1000) M2: 5.69 x10-4 mol/L
Table 2: Standardization of NBS
Titration number Rough 1 2 3
Final burette reading (ml) 16.80 27.00 37.20 47.30 ±0.10
Initial burette reading (ml) 5.40 16.80 27.20 37.20 ±0.10
Titre (ml) 11.40 10.80 10.00 10.10
Number of OK titres, N
Sum of OK titres 2.00
Average (ml) 10.05
Calculation:
(10.00+10.10)/2 = 10.05
M1V1 = M2V2
M1: concentration of diluted ascorbic acid V1: volume of diluted solution in conical flask
M2: concentration of NBS V2: volume needed for titration
5.69 x10-4 mol/L x (10/1000) = M2 x (10.05/1000) M2: 5.66 x 10-4 mol/L
Table 3: Quantity of Vitamin C in Ribena
Titration number Rough 1 2
Final burette reading (ml) 12.20 18.60 25.00 ±0.00
Initial burette reading (ml) 5.70 12.20 18.60 ±0.00
Titre (ml) 6.50 6.40 6.40
Number of OK titres, N
Sum of OK titres 2.00
Average (ml) 6.40

Moles of NBS: MV
5.66 x 10-4 mol/L x (6.40/1000) = 3.62 x 10-6 moles
M1V1 = M2V2
M1: concentration of NBS solution V1: volume of NBS needed for titration
M2: concentration of Vitamin C in ribena V2: volume of ribena added
5.66 x 10-4 mol/L x (6.40/1000) = M2 x (2/1000)