# Incline Motion Lab

Purpose – The purpose of this experiment was to find how position and time are related to a ball on an incline. Data –

7 Books

X (cm)| Trial 1 (s)| Trial 2 (s)| Trial 3 (s)| Average (s)| 10| 0.336| 0.3654| 0.3434| 0.3479|

15| 0.3952| 0.4262| 0.43| 0.4171|

50| 0.9127| 0.8846| 0.8936| 0.8971|

75| 1.1257| 1.1178| 1.1322| 1.1252|

100| 1.320| 1.2788| 1.2979| 1.2989|

125| 1.4924| 1.4966| 1.4766| 1.4885|

4 Books

X (cm)| Trial 1 (s)| Trial 2 (s)| Trial 3 (s)| Average (s)| 10| 0.4663| 0.4540| 0.4664| 0.4622|

15| 0.5559| 0.5716| 0.5838| 0.5715|

50| 1.1117| 1.1721| 1.1337| 1.1391|

75| 1.4165| 1.4153| 1.4231| 1.4183|

100| 1.6859| 1.6683| 1.6509| 1.6682|

125| 1.9305| 1.9851| 1.9604| 1.9587|

We found the average by using the formula (Trial 1 +Trial 2 + Trial 3)/3, and example would be (0.4663+0.454+0.4664)/3 = (1.3867)/3 = 0.4622 seconds. Graphs - The graphs (stapled on the back) all display that the ball moves at a constant acceleration. 4 book x-t graph: P= 32.38cm/s2 (t) + 6.012cm

7 book v-t graph: V= 52.19cm/s2 (t) + 54.74s

7 book x-t graph: P= 55.09cm/s2 (t) + 4.948cm

4 book v-t graph:

The position vs. time graphs’ (x-t) slopes represent velocity. Obviously, 7 books will have a higher velocity than 4 books, thus having a larger slope (32.38cm/s2 vs. 55.09cm/s2). The y-intercept represents the place where we started the ball on the ramp. The velocity vs time graphs’ (v-t) slopes represent acceleration. To find instantaneous velocity, you have to find the slope of all the points on the v-t graph and use the slopes of all the points as the points in the acceleration vs. time graph. Conclusion – In this lab I have learned that an object going down an incline will accelerate at a constant rate and moves faster every second. The position vs. time squared graphs’ equation is ½ the slope of the acceleration vs. time graph because you have to use time...

Please join StudyMode to read the full document