Five Unlabeled Bottles Lab Report
Lab chemisty
03/27/2011
Five unlabeled bottles
Set 1:
A) colorless B) colorless C) blue D) blue E) colorless
A: Ba(NO3)2 B: AgNO3 C: CuSO4 D) CuCl2 E) KCl
Description how to identify solution:
_ We have two blue solution which are CuSO4 and CuCl2 or C and D, according to chemical reaction experiment, C didn’t have any reaction with other solution like B and D beside A, so if we look at the solubility chart, SO2- have only one precipitation with Ba2-. So we come to conclusion that C is CuSO4 and A is Ba(NO3)2
_ So now that we know C is CuSO4, other blue solution must be CuCl2 which is D, so according to chemical reaction experiment, D didn’t have any reaction with other solution beside B, if we look at solubility chart CuCl3 only have one precipitation with AgNO3. So we come to conclusion that B is AgNO3 …show more content…
So we come to conclusion that E is
03/27/2011
Five unlabeled bottles
Set 1:
A) colorless B) colorless C) blue D) blue E) colorless
A: Ba(NO3)2 B: AgNO3 C: CuSO4 D) CuCl2 E) KCl
Description how to identify solution:
_ We have two blue solution which are CuSO4 and CuCl2 or C and D, according to chemical reaction experiment, C didn’t have any reaction with other solution like B and D beside A, so if we look at the solubility chart, SO2- have only one precipitation with Ba2-. So we come to conclusion that C is CuSO4 and A is Ba(NO3)2
_ So now that we know C is CuSO4, other blue solution must be CuCl2 which is D, so according to chemical reaction experiment, D didn’t have any reaction with other solution beside B, if we look at solubility chart CuCl3 only have one precipitation with AgNO3. So we come to conclusion that B is AgNO3 …show more content…
So we come to conclusion that E is