movement of water in the cell. Independent variable is the factor that affects the value of variables dependent to it. In osmosis lab‚ the independent variables are the potato and onions. The dependent variable is the variable whose value is measured to determine the extent of the effect of another variable to it‚ as in an experiment. In osmosis lab‚ the dependent variable is the length of the potato. The controlled variables are the amount of water‚ amount of salt‚ and the size of the potato. If the
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potatoes have faster water movement depending on the concentration of sucrose it was placed in. We had two sized potatoes‚ 6g and 10g‚ and placed each in three different dilutions of sucrose at 0.5M‚ 0.1M‚ and 0.05M. We also placed a 6g and 10g potato piece in water to act as a control. Based on the weight percent change over 60 minutes‚ the 6g potato piece had faster water movement than the 10g. This confirms out hypothesis that smaller potato pieces will have a faster rate of water movement. Introduction
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INTRODUCTION: In biology‚ osmosis is defined as the diffusion of solvent molecules (usually water molecules) across a semi-permeable membrane from a region of lower solute concentration to a region of higher solute concentration. Osmosis is of great importance in biological processes where the solvent is water. The transport of water and other molecules across biological membranes is essential to many processes in living organisms. The pressure exerted
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concentration of sucrose solution on osmosis in a potato. Preliminary Experiments One preliminary experiment was done before the main experiment. From the preliminary‚ we were trying to find out how osmosis actually occurred in potatoes‚ and gave us a vague idea on what the main experiment would be like. This preliminary will aid my prediction‚ which is stated below. The following apparatus was used for the preliminary: * 1 large potato (skin intact) * 3 boiling tubes * Set
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activity‚ between the solution and a potato tuber of a given size. The purpose of this experiment is to demonstrate how living cells rely on osmosis‚ the diffusion of water. Osmosis is the movement of water molecules (H20) from a region in which they are highly concentrated to a region in which they are less concentrated. This movement must take place across a partially permeable membrane such as a cell wall‚ which lets smaller molecules‚ such as water‚ through but does not allow bigger molecules
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Potato Enzyme Lab Enzymes are protein catalysts that speed up chemical reaction in living organisms. The purpose of this lab was to; observe the breakdown of hydrogen peroxide toxin by potato’s enzyme catalase‚ determine factors that influence how quickly the reaction takes place‚ and determine factors that influence how well enzymes function. The first test‚ we were supposed to see what would happen when we add sand in hydrogen peroxide. We filled a test tube with 5mL hydrogen peroxide and we added
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The formation of an action potential can be divided into five steps. (1) A stimulus from a sensory cell or another neuron causes the target cell to depolarize toward the threshold potential. (2) If the threshold of excitation is reached‚ all Na+ channels open and the membrane depolarizes. (3) At the peak action potential‚ K+ channels open and K+ begins to leave the cell. At the same time‚ Na+ channels close. (4) The membrane becomes hyperpolarized as K+ ions continue to leave the cell. The
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Redox potential – CV Acetonitrile Adjusted sensitivity Each ;line represents diff scan rates all been overlayed on one digarm Scan rates ranged from 0 .1 s-1 to 1 Peak due to iodide oxidation is read from +peak to – peak bottom line. Iodide to triiodide Glycol Didn’t work Using equation ip = 2.69 ×105 n3/2 A D1/2 C ν1/2 compare to linear equation y = mx+c y = peak current x = V1/2 c = zero Therefore m is = everything else C = concentration 0.05 M ethylene glycol (acetonitrile
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THE WORK DONE BY A CONSERVATIVE FORCE ALWAYS HAS FOUR PROPERTIES: 1. It can be expressed as the difference between the initial and final values of a potential-energy function. 3. It is independent of the path of the body and depends only on the starting and ending points. 2. It is reversible. 4. When the starting and ending points are the same‚ the total work is zero. The total mechanical energy ME = K + U is constant. Object moving in a uniform gravitational field gravitational a
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which cell has the larger resting membrane potential? Explain. If the permeability to K is higher in A than in B‚ then the resting membrane potential (rmp) will be closer to the equilibrium potential in cell A‚ which means the rmp will be more negative in cell A than in cell B; or in other words‚ the potential difference will be LARGER in cell A. 2. Predict the effect of a reduced extracellular concentration of Na+ on the magnitude of the action potential in an electrically excitable cell. If there
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