show that the area of a segment of a parabola is 4/3 the area of a triangle with the same base and vertex and 2/3 of the area of the circumscribed parallelogram. Archimedes also “invented” the volume and surface area of a sphere‚ the volume and area of a cone‚ the surface area of an ellipse‚ and the volume of any segment of a parabolic. No progress or advancements were made in calculus until the 17th century. One great mathematician that was born in Barsa‚ Persia is Abu Ali-Hasan ibn al-Haytham.
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Record your info. Use the displacement method to find the volume of the lead. Get a graduated cylinder‚ then fill it up half-full with sink water and record your info. Be very careful when adding your metal sample‚ try not splashing or losing anything out of the graduated cylinder. If you mess up‚ start over from step 2 with fresh samples. Also if the water does not cover the metal by now start all over with clean samples. Record your final volume. Repeat steps 2 and 3 for the other metals. Dry both samples
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CPR (MATH13- B10) Members: C06 Wrenbria Ngo C07 Julie – Ann Parañal C08 Dani Patalinghog C09 Marino Penuliar C10 Michael Sadsad CPR (MATH13- B10) Members: C06 Wrenbria Ngo C07 Julie – Ann Parañal C08 Dani Patalinghog C09 Marino Penuliar C10 Michael Sadsad
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Volumetric Flask Total Volume (L) Molarity (mol/L) Sugar (C12H22O11) 8 331.23 0.02415 25 0.9961 *As a side note‚ upon researching the molecular weight of sugar‚ I found it to be 342.30 g‚ not 331.23 g‚ however‚ in my calculation I used 15.00 g as the molecular weight of O2‚ whereas online 16.00 g was used. Eight8 g of sugar were placed on the scale‚ and then transferred into the volumetric flask (Table 8 shows the calculations of the molecular weight‚ moles‚ mass‚ volume and molarity recorded
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Objective To prove Distance formula = by experimentally Pre-knowledge We know Pythagoras Theorem Area of triangle Some Knowledge about coordinate Rules for signs of Co-ordinates Axes of Co-ordinates Geometrical Representation of quadratic polynomials Material Required Coloured Glazed paper Pair of scissors Geometry box Graph paper Drawing sheet Colour stick Pencil colour Fevistick/ Gum Procedure Let two points P(x1‚y1) and Q(x2‚y2) on graph sheet. And draw a set of perpendicular
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water. In order to investigate the principles of mass‚ you have to find the volume and density for four different types of candy bars. My question is‚ which candy bar will have the least amount of density? Hypothesis: If a Twix has cookie inside‚ then it will have the least amount of density. Materials: 4 candy bars( Snickers‚ Twix‚ 3 Musketeers‚ Milky way) Balance Ruler Procedures: First‚ you try to find the volume measure by using L x W x H. You then measure the width using a ruler. Finally
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Guidelines for Mathematics Laboratory in Schools Class X Central Board of Secondary Education Preet Vihar‚ Delhi – 110092. 1 2 1 . Introduction Taking into consideration the national aspirations and expectations reflected in the recommendations of the National Curriculum Framework developed by NCERT‚ the Central Board of Secondary Education had initiated a number of steps to make teaching and learning of mathematics at school stage activity-based and experimentation oriented
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cylinders‚ prisms‚ pyramids and spheres. In his writings Heron put together all the geometric rules and formulas from ancient times. Some of them went as far back as Babylon. In his theory’s and writings her explains how to come up with the area and or volumes of different plane and solid figures. In book one their is also an iterative method to approximating the square root of a dumber to arbitrary accuracy. It is an interesting fact that computers today use a very similar method. Heron’s formula of a
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Performance Task in GEOMETRY * Computation of the surface area‚ amount and type of needed material and the volume of the package. Volume V= L x H x W = (23 cm) (4 cm) (12cm) = (276) (4) = 1 104 cm Area A= L x W = (23cm) (12cm) = 276cm Surface Area A= 2(Lh) + 2(Lw) + 2(Wh) / 2( lh + lw + wh) = 2(23*4) + 2(23*12) + 2(12*4) = 2(92) + 2(276) + 2(48)
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HIGHER TIER Pythagoras’ Theorem c Volume of cone = 1 3 r 2h Curved surface area of cone = b rl r3 Surface area of sphere = 4 r 2 r l a a + b2 = c2 4 3 Volume of sphere = h 2 hyp r opp adj adj = hyp cos opp = hyp sin opp = adj tan or sin opp hyp cos adj hyp tan opp adj In any triangle ABC C b a A Sine rule: B c a sin A b sin B c sin C Cosine rule: a2 b2 + c 2 2bc cos A 1 2 Area of triangle ab sin C cross section h lengt Volume of prism = area of cross section
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