In part A of the experiment the two values obtained for the specific heat capacity of the metal were about .0500 J/mol. This is a large deviation‚ with both of these values identifying very different metals. The average heat capacity identified the metal used as brass. The average heat capacity calculated was .3776 J/mol and the actual heat capacity of brass is .375 J/mol. The second run displayed the closest value to the actual value. A source of error that may have caused a large divide in the
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Caloric Content of Food Peter Jeschofnig‚ Ph.D. Version 42-0143-00-01 Lab Report Assistant This document is not meant to be a substitute for a formal laboratory report. The Lab Report Assistant is simply a summary of the experiment’s questions‚ diagrams if needed‚ and data tables that should be addressed in a formal lab report. The intent is to facilitate students’ writing of lab reports by providing
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Lab14: Heat Capacity Lab #14 – Heat Capacity OBJECTIVES In this lab you will: Use your code from the previous week to calculate the specific heat capacity per atom of a block of aluminum containing 35 atoms. Compare your theoretical curve with experimental data‚ and explain any discrepancies. Add code to your program to calculate the heat capacity of a block of lead containing 35 atoms‚ compare the theoretical curve with experimental data‚ and explain any discrepancies. Heat capacity is a measure
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Calculate the energy change (q) of the surroundings (water) using the enthalpy equation qwater = m × c × ΔT. We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL. The water has absorbed the heat of the metal. So‚ qwater = qmetal Using the formula qmetal = m × c × ΔT‚ calculate the specific heat of the metal. Use the data from your experiment for the metal in your calculation. Aluminum: q=26*4.18*6.3=684.684‚ c=q/(m*^T)=3.913
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Report | Specific Heat Capacity of Brass | | Jin Jin Shi | 2012/12/6 | Instructor: Mr. Nailer | I. Introduction The amount of heat required to raise the temperature of a solid body depends on its change in temperature (ΔT)‚ its mass (m)‚ and an intrinsic characteristic of the material forming the body called specific heat (cp). The heat is calculated from the equation II. Purpose The purpose of this laboratory is to determine the experimental quantities of heat transfer
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The heat equation Specific heat capacity: The specific heat capacity of a substance is the heat required to produce a rise in 1 Kg Specific heat capacity of water ( ) ( ) ( ) Thermal capacity: It’s the quantity of heat needed to raise the temperature of the whole body by . Specific latent heat of fusion: The specific latent heat of fusion of a substance is the quantity of heat needed to change unit mass from solid to liquid without temperature change. Specific latent heat of fusion
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Latent heat is a science term used to describe the amount of energy that has been absorbed or released when a substance goes through the process of changing states. | Latent Heat of Fusion - heat absorbed by a unit mass of a solid at its melting point in order to convert the solid into a liquid at the same temperature The heat absorbed as a substance changes phase from liquid to solid‚ a process called fusion or solidification. For water‚ Latent Heat of Solidification - heat liberated
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specific heat of solids 1. Introduction Heat capacity of a body is the quantity of heat required to raise the temperature of the body by 1oC. The specific heat of a substance is the heat capacity per unit mass. Thus‚ heat capacity = mass x specific heat. The specific heat is essentially a measure of how thermally insensitive a substance is to the addition of energy. Heat and temperature are really different quantities. Heat is a quantity of thermal energy‚ while temperature determines the
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Calorimetry Chemistry 1412 Spring 2013 Objective: Determine the calorimeter constants in a coffee cup calorimeter‚ then the calorimeter will used to determine the quantity of heat that flows in a few physical and chemical processes. Materials used: Choice I: Choice II: * Safety Goggles Safety Goggles * Distilled water Distilled water * 150 mL beaker 600 mL beaker * 50 mL graduated cylinder 50 ml graduated cylinder * Calorimeter Calorimeter
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Waris Butt PHY 112 Mr. Fasciano Class #18336 06/08/14 Purpose: Heat flow will occur between objects in contact until no more heat flow is detectable. Using calorimetry to analyze heat flow quantitatively and the equation: Q = mc ΔT‚ to determine the specific heat capacity of an object and heat flow from or to an object; respectively. Materials: Circle K 44 oz Styrofoam cup with lid Large Plastic Harkins Theater cup Thermometer
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