Common Name: Pearl Scientific Name: Calcium Carbonate Formula: CaCO3 Fundamental particles: Pearls are comprised of a positive Calcium ion (Ca+) and a negative Carbonate polyatomic ion (CO3+) Usage: Jewelry Properties: Pearls are good jewelry because they are hard and lustrous. Pearls are hard because of the strong Intermolecular forces created between the Calcium and the Carbonate ions. The pearls luster is dependent on the amount of nacre excreted. The Oyster produces nacre when
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The purpose of this lab was to use gas chromatography to determine the relative amounts of the three components of gas products from the dehydration reaction of 1- and 2-Butanol with sulfuric acid and the dehydrobromination reaction of 1- and 2-Bromobutane with potassium tert-butoxide. E1 reactions are two-step unimolecular reactions. The first step of an E1 reaction occurs when a leaving group‚ which consists of a weak base‚ leaves an organic compound‚ leaving an intermediate carbocation. In the
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Ideal Gas Law: The ideal gas law is the equation of state of a hypothetical ideal gas. It obeys Boyle’s Law and Charles Law. Ideal Gas Law Formula : General Gas Equation: PV = nRT Pressure(P) = nRT / V Volume(V) = nRT / P Temperature(T) = PV / nR Moles of Gas(n) = PV / RT where‚ P = pressure‚ V = volume‚ n = moles of gas‚ T = temperature‚ R = 8.314 J K-1 mol-1‚ ideal gas constant. Ideal Gas Law Example: Case 1: Find the volume from the 0.250 moles gas at 200kpa and 300K temperature
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Safe drinking water interventions for home and outside use Contents The LifeStraw® Concept Drinking Water Crisis The Link between Diarrhoea and HIV The Health Impact of Water Filtration LifeStraw® Family – Product Features LifeStraw® Family – Functioning LifeStraw® Family – Usage LifeStraw® Family – Comparison to other Point-of-Use Interventions for Safe Drinking Water LifeStraw® Family – Microbiological Performance LifeStraw® Family – Health Impact LifeStraw® Family – Durability LifeStraw®
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Gas Law Problems Boyles Law 1. A gas occupies 12.3 litres at a pressure of 40.0 mm Hg. What is the volume when the pressure is increased to 60.0 mm Hg? 2. If a gas at 25.0 °C occupies 3.60 litres at a pressure of 1.00 atm‚ what will be its volume at a pressure of 2.50 atm? 3. To what pressure must a gas be compressed in order to get into a 3.00 cubic foot tank the entire weight of a gas that occupies 400.0 cu. ft. at standard pressure? 4. A gas occupies 1.56 L at 1.00 atm. What will be the volume
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A THESIS ON ENERGY LAW THAT CRITICALLY EXAMINES THE LEGAL ISSUES IN THE DEREGULATION OF THE DOWNSTREAM SECTOR OF THE NIGERIA INDUSTRY: CONSIDERING THE ARGUMENTS IN FAVOUR AND AGAINST DEREGULATION INCLUDING ISSUES PERTAINING TO OPERATION OF THE REFINERY ‚WITHDRAWAL OF OIL SUBSIDIES AND APPROPRIATE PRICING IN A LIBERALISED ECONOMY. . INTRODUCTION. Nigeria is blessed with vast quantity of oil making it the 6th largest oil exporter in the organization of petroleum exporting country. Oil
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Gas Laws Gases exhibit many qualities that are very different from those of liquids or solids. Gases have particles that are farther apart when compared to liquids and solids. The particles in gases move at different speeds in random directions and they are constantly moving. These particles collide with each other and with whatever container or area they are in. Gases are also very easy to compress. They expand to fill their containers and they occupy far more space than the liquids and solids
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Name of the Experiment: Avogadro’s Law Type Your Name: Date: 11/17/13 Experiment 1 ________________________________________ 1. For each gas‚ record the following: Propane Butane Methane a Name and formula C3H8 C4H10 CH4 b Mass of 100 mL gas (g) 0.274g 0.361g 0.100g c Molecular weight of the gas (g/mole) 44.10g/mol 58.12g/mol 16.04g/mol d Number of moles in the 100 mL sample 0.0062mol 0.0062mol 0.0062mol Average of all 3 gases: (0.0062+0.0062+0.0062)
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Ideal Gas Law Packet Name ______________________________ 12.3 Date __________________ Period _______ Given: Ideal Gas Law = then P = n = V = T = R = 1. What pressure is required to contain 0.023 moles of nitrogen gas in a 4.2 L container at a temperature of 20.(C? 2. Oxygen gas is collected at a pressure of 123 kPa in a container which has a volume of 10.0 L. What temperature must be maintained on 0.500 moles of this gas in order
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Ch 10 Gas Laws Sample Questions 1) A sample of gas (24.2 g) initially at 4.00 atm was compressed from 8.00 L to 2.00 L at constant temperature. After the compression‚ the gas pressure was __________ atm. A) 4.00 B) 2.00 C) 1.00 D) 8.00 E) 16.0 2) A balloon originally had a volume of 4.39 L at 44 °C and a pressure of 729 torr. The balloon must be cooled to __________°C to reduce its volume to 3.78 L (at constant pressure). A) 38 B) 0 C) 72.9 D) 273 E) 546 3) If 50
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