Physical properties of organic compound Low boiling point group: alkane‚ alkene‚ alkyne and ether Boiling point is the exact temperature that the state of compound change from liquid to gas‚ which need to break the intermolecular forces. The stronger the intermolecular forces‚ the higher the boiling point. Since straight chain alkane‚ alkene and alkyne only experience dispersion forces‚ the compound with more carbons have higher boiling point as more carbons contribute more forces. Branched
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3/5/2011 EXPERIMENT EXPERIMENT 8 OBJECTIVES CONCEPTS REAGENTS PROCEDURE RESULTS DISCUSSION IR ANALYSIS 8 Objectives to differentiate various types of oxygen-bearing organic compounds to device a scheme to distinguish each functional group Analysis of Oxygen-bearing Organic Compounds alanx3@yahoo.com OBJECTIVES CONCEPTS REAGENTS PROCEDURE RESULTS DISCUSSION IR ANALYSIS to characterize an unknown sample through parallel chemical tests ARMSALCEDO ARMSALCEDO alanx3@yahoo
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Bonifacio‚ Prince Zero P.Date Performed: October 00‚ 2014 Group No. 1Date Submitted: October 00‚ 2014 Experiment No. 7 Unknown: 2 Compound: Table 6.1Physical Examination State Liquid Odor Smells like adhesive paste Color Pink-orange Flammability Flammable Table 6.2Physical Constant: Melting Point Parameter Experimental Theoretical (From Literature) Melting Point (oC) Trial 1 Trial 2 Average 88 88 86 86 Table 6.3Solubility Test Sample Solubility Solubility Class Water Ether 5% NaOH5%
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alcohol which contains a hydroxyl group (OH-) has a partial negative charge compared to the alkyl group bound to it which is Isopropyl in this lab. The reason is that oxygen has higher electronegativity compared to carbon. So‚ there is more attraction to the lone pair electrons around oxygen which makes the hydroxyl group partially negative. Analyzing the structure of the glacial acetic acid‚ we notice that the hydroxyl group and the oxygen on the carbonyl group will draw electrons towards themselves
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Preliminary Tests and Solubility Classification of Organic Compounds Lirio‚ Stephen1‚ Tayag‚ Carlo A.2 1Professor‚ School of Chemical Engineering‚ Chemistry and Biotechnology‚ Mapua Institute of Technology; 2Student ‚ CHM146L/C11‚ School of Chemical Engineering‚ Chemistry and Biotechnology‚ Mapua Institute of Technology ABSTRACT In this experiment‚ solubility class of various organic compounds are to be determined. The main objective of the experiment is to identify an unknown compound through
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Identification of an Unknown Organic Compound The objective of this lab was straightforward. We were given an unknown compound and we were to perform an IR spectroscopy and as well as NMR spectroscopy. With the IR spectroscopy‚ I was able to name the functional groups I have on my compound and further confirmed my assumptions by looking at the NMR spectroscopy after. The unknown number I was given was number 203. The molecular weight of the compound was 121. From the molecular weight‚ I calculated the molecular
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1 Haloalkanes and Haloarenes IIT-JEE Chemistry Siddhivinayaka Educational Academy Rajendra Nagar Chowk Link Road Bilaspur Ph-07752- 237799/238799 Website : www.bajpaigroup.com. e-mail - info@bajpaigroup.com CHAPTER 23 LEARNINg OBJECTIvES (i) Name haloalkanes and haloarenes according to the IUPAC system of nomenclature from their given structures. (ii) Describe the reactions involved in the preparation of haloalkanes and haloarenes and understand various reactions that they undergo.
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PID#_________________________ 1. Amine Basicity (5 points). Place the following compounds in order of their basicity with #1 being the most basic and #4 being the least basic. Work carefully. There will be no partial credit or regrades on this problem. 2. Functional Group Preparations (15 points). Give chemical equations for five methods for synthesizing 2-methyl-1-propanamine in a single synthetic step‚ not counting any workups. 3. Reactions of Amines (15 points). Draw the organic products of the following
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thionyl chloride as a nucleophile1. Thionyl chloride then undergoes a loss of a leaving group as chlorine will leave1. The compound is then deprotonated from the free chlorine and SO2 is expelled as a gas as it is an excellent leaving group (Figure 2)1. Diethyl amine can then be reacted with the compound via a nucleophilic attack. Once the amine is attached chlorine will leave as a leaving group as the carbonyl group reforms (Figure 3)1. This provides a simple two-step process to attach a diethyl amine
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words: diazo compounds‚ boron‚ hydrazine‚ transition-metalfree reactions‚ 1‚2-migration 1 Introduction Diazo compounds are useful building blocks in organic synthesis as a result of their diverse reactivity in various reactions and functional group transformations.1‚2 In most cases‚ diazo compounds are used as the precursors of free carbene or metal carbene species C (Scheme 1). Typical reactions of metal carbenes include X–H insertions (X = C‚ N‚ O‚ S‚ etc.)‚ cyclopropanation‚ ylide
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