Discovering the equilibrium constant for a reaction is very helpful for understanding that reaction. Knowing the equilibrium constant of a reaction is important because it allows you to calculate how much product will ultimately be formed during a reaction. Moreover‚ it also tells you how a particular mixture of chemicals will react. This is because chemical reactions always occur in the direction which will make the ratio of their products to reactants equal to the equilibrium constant.
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Temperature to the reaction C. Effect of Concentration to the Reaction Rate D. Effect of Catalyst to the Reaction Rate E. Chromate-Dichromate Equilibrium F. Thiocyanatoiron (III) Complex Ion Equilibrium G. Weak Acid Equilibrium (Ionization of Acetic Acid) H. Weak Base Equilibrium Ionization of Ammonia I. Saturated Salt (Sodium Chloride) Equilibrium On part (A) we are to observe which reaction rate is faster‚ and doing the experiment. We have concluded that: “Aluminum had faster rate of reaction
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and cooled then mixed with an amount of ice that was also weighed. The temperature before and after mixing was recorded and included in tables. When the experiments were completed analysis was performed using the laws of thermodynamics. The data collected was used in equations to find theoretical values for final equilibrium temperature. The theoretical values were compared with those measured during the experiment. The total average percent difference between the measured final temperature and the
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and answer these questions: A. Which way should the equilibrium shift when HCl is added? How do your results support your answer? It should shift to the left because adding any component causes the equilibrium to shift to the opposite side. B. Which way should the equilibrium shift when Na2EDTA is added? How do your results support your answer? It should shift to the right because the removal of a component causes the equilibrium to shift to the side from which the component was removed
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Stephany Matos Chem Lab: Chemical Equilibrium Lab 52 Synopsis Iron (III) ions react with thiocyanate ions (SCN-) to form iron (III) thiocyanate‚ FeSCN2+. It is represented in the equation below: Fe3+ (aq) + SCN- (aq) FeSCN2+ (aq) Therefor the equilibrium constant for this reaction is: KC = [FeSCN2+]/([Fe3+]•[SCN-] For this experiment we were able to determine the equilibrium constant KC for this reaction. First we prepared five different mixtures with known initial concentrations of
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LONG-RUN EQUILIBRIUM OF A FIRM UNDER PERFECT COMPETITION In the long run‚ a firm in the perfectly competitive market can earn only normal profit. So‚ the profit maximization under long run is: (1)Necessary condition P=LMR=LAR=LMC=LAC (2)Sufficient condition Slope of MC > Slope of MR We can establish this condition from the following analysis. In the above diagram for any market price OP1 the existing firms can earn supernormal profit as for the equilibrium output level OQ1. The average
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single or multivalued mappings is obtained as a corollary of Nash equilibrium existence in finitely many players games. ı Copyright © 2006 Juan Pablo Torres-Mart´nez. This is an open access article distributed under the Creative Commons Attribution License‚ which permits unrestricted use‚ distribution‚ and reproduction in any medium‚ provided the original work is properly cited. 1. Introduction In game theory‚ the existence of equilibrium was uniformly obtained by the application of a fixed point theorem
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Determination of an Equilibrium Constant Abstract: In this experiment‚ two reactions were run to determine the molar absorptivity and the equilibrium constant of FeSCN2+. The main principles used in this lab are equilibrium‚ LeChatlier’s Principle‚ Beer’s Law and Spectrocopy. The first reaction was run to completion using LeChatier’s Principle and the second reaction was run to equilibrium. A spectrophotometer was used to measure absorbances. Using a graph of absorbance versus concentration
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Determination of Equilibrium Constants Introduction Bromothymol blue is an indicator for many acid-base titrations. When adding different solutions within the indicator it is to react and change colors‚ in this experiment the different colors were blue‚ green‚ and yellow. In the following experiment‚ obtaining the absorbance levels for each one makes it possible to calculate the equilibrium constant. Materials and Methods For this specific experiment there are a few materials that are crucial
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CHM 096 TUTORIAL 2 (Chemical Equilibrium) Jan 2013 1. Write the equilibrium constant expression‚ Kc‚ for each of the following reactions: a) b) c) d) e) f) 2NO(g) + O2(g) ⇄ 2NO2(g) The decomposition of solid potassium chlorate to solid potassium chloride and oxygen gas. 4HCl(g) + O2(g) ⇄ 2H2O(g) + 2Cl2(g) 2NO2(g) + 7H2(g) ⇄ 4H2O(l) + 2NH3(g) H2O(g) + C(s) ⇄ CO(g) + H2(g) The reduction of solid copper (II) oxide with hydrogen gas to produce copper metal and water at o 500 C. 2H2(g) + O2(g)
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