Archives Des Sciences Vol 66‚ No. 5;May 2013 Title: New Toll to Predict Chronic Hepatitis C Treatment Result for Each Patient Ieva Tolmane (Corresponding author) Latvian University‚ Riga‚ Latvia Riga East university hospital‚ Infectology Center of Latvia‚ Riga‚ Latvia Address: Linezera Street 3‚ Riga‚ Latvia‚ LV 1006 Phone: +371 29266740‚ Fax: +371 67014568 E-mail: ieva.tolmane@inbox.lv‚ ieva.tolmane@aslimnica.lv Baiba Rozentale Riga Stradin’s University‚ Infectology and Dermatology
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the ratios of the genotypes and phenotypes of the offspring in the F1 generation. Answer: Genotypes: FF ¼‚ Ff ½‚ ff ¼ Phenotypes: Freckles ¾‚ No freckles ¼ Part 2: Dihybrid Cross—Predicting Flower Color and Seed Shape Imagine that you are crossing two plants that are heterozygous for flower color and seed shape. The dominant and recessive alleles for these traits are as follows: purple flowers: P white flowers: p round seeds: R wrinkled seeds: r (2 points) 1. Determine the genotype of each parent
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offspring with genotype AA __27__ X 2 = ___54___ A alleles Number of offspring with genotype Aa __42__ X 1 = ___42___ A alleles Total = ___96___ A alleles p = Total number of A alleles / Total number of alleles in the population = 96/160 = _0.60_ Number of a alleles present at the Fifth Generation Number of offspring with genotype aa __11__ X 2 = ___22___ A alleles Number of offspring with genotype Aa __42__ X 1 =
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column labeled with one of the possible genotypes of sperm and eggs‚ respectively. (The fractions of these genotypes are included with each label.) 4. Fill in the genotype of the offspring in each box by combining the genotype of sperm in its row with the genotype of the egg in its column. (Multiply the fraction of sperm of each type in the row headers by the fraction of eggs of each type in the column headers.) 5. Count the number of offspring with each genotype. (Note that Pp is the same as pP.)
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occurs at the level of a. the individual genotype b. the individual phenotype c. environmentally based phenotypic variation d. the population 2. What does natural selection act upon? a. The gene pool of the species b. The genotype c. The phenotype d. Multiple gene inheritance systems 3. Suppose a particular species of flowering plant that lives only one year can produce red‚ white‚ or pink blossoms‚ depending on its genotype. Biologists studying a population of this
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The two techniques that were used to create a DNA profile in this experiment were PCR and gel electrophoresis. The PCR is used to amplify the several DNA samples and gel electrophoresis is performed to separate the DNA fragments according to their size. [6] In the first part of the experiment‚ PCR amplification of the DNA templates was performed and the products obtained were used to perform gel electrophoresis. The process of PCR allows for the amplification of the DNA samples and the components
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for the color of a flower in a gene‚ with P for purple and p for white‚ the three possible combinations which might exist in any one plant are PP making a purple plant‚ pp to make a white plant‚ or Pp resulting in a ‘hybrid’ plant. 2.) Out of the genotypes PP‚ Pp‚ pp‚ the resultant flower colors are (as described above in exercise 1) are purple (for PP‚) purple or purplish-white (for Pp- likely purple as it is dominant‚ or a mixture of the colors‚) or white (for the case of pp.) PP and pp‚ the purple
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and meiotic drive. Frequency is the proportion of individuals in a certain category relative to the total number of individuals considered. The frequency of an allele or genotype is expressed as a decimal proportion of the total alleles or genotypes in a population. For example‚ if 4 individuals in a population of 16 are genotype Bb‚ the frequency of Bb is 0.25 (calculated by dividing 4 by 16). If 75 out of 100 alleles in a population are B then the frequency of allele B in the population is 0.75
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and his wife can both roll their tongues and are surprised to find that their son cannot! Explain this by showing the genotypes of all three persons. 3. In rabbits‚ spotted coat (S) is dominant to solid‚ and black (B) is dominant to brown. In a large population‚ brown spotted rabbits are mated to solid black ones and all the offspring are black spotted. What are the genotypes of the parents? What would be the appearance of the F2 if two of these F1 black spotted rabbits were mated? 4. In pea
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parent generation. Create a Punnett square to show their offspring‚ the F1 generation. Answer: Part 1 Punnett Square GENOTYPES: FF Ff
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