General Chemistry II Lab (CHEM 1106) Determination of the Solubility Product Constant of a Salt Date Performed: March 1‚ 2011 INTRODUCTION If solid KHC4H4O6 is added to a beaker of water‚ the salt will begin to dissolve. The amount of solid diminishes‚ and the concentrations of K+(aq) and HC4H4O6-(aq) in the solution increase. When no KHC4H4O6 dissolves‚ the concentrations of K+(aq) and HC4H4O6-(aq) will not increase further and any additional KHC4H4O6 added after this point will remain
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DETERMINATION OF THE SOLUBILITY PRODUCT CONSTANT OF CALCIUM HYDROXIDE ABSTRACT This experiment aimed to determine the solubility product constant (Ksp) of Ca(OH)2 as well as to evaluate the effects of common and non-common ions on its solubility. Ca(OH)2 solids were dissolved in eight various media: distilled water‚ 1.0 M KCl‚ 0.5 M KCl‚ 0.1 M KCl‚ 0.05 M KCl‚ 0.005 M KCl‚ 0.001 M KCl‚ and 0.1 M Ca(NO3)2. The concentration of dissociated OH- concentrations was determined by means of titrimetric
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Solubility Product Determination Purpose • To determine the solubility product constant‚ Ksp‚ of an ionic compound. Introduction The solubility product constant‚ Ksp‚ is a particular type of equilibrium constant. The equilibrium is formed when an ionic solid dissolves in water to form a saturated solution. The equilibrium exists between the aqueous ions and the undissolved solid. A saturated solution contains the maximum concentration of ions of the substance that can dissolve at
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Topic : Solubility product of Constant (Ksp) Grade : XI Semester : 2 Time Allocated : 30 minutes I. Competency Standard Understanding properties‚ measuring method and applying of acid base solutions. II. Basic Competency Predicting precipitation from a reaction based on solubility and solubility product constant principle III. Indicator 1. Explain the meaning of Solubility Product Constant (Ksp) 2. Write down the Solubility Product Constant’s Formula
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Determination of the Solubility Product Constant of Calcium Hydroxide Introduction The equilibrium constant for the solubility equilibrium between an ionic solid and its ions is called solubility constant [1] ‚ Ksp of the solute. For example‚ the solubility product is defined by MxAy(s) ⇋xM(aq)y++ yA(aq)x- (1) Where M is the metal cation‚ A is the anion‚ x and y are the corresponding charges of the ions. The equilibrium expression is Ksp=[MY+]x[AX-]Y (2)
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Solubility Product Constant Q: Write the equilibrium equation for a saturated solution of the following salts and the corresponding solubility product expressions. a) BaSO4 (s) b) MgF2 (s) c) Ag2S (s) d) Cu(IO3)2 (s) [ ][ [ [ A: [ ( Q: ) ] ][ ][ ] ] What is the equilibrium concentration of Cd2+ ions in a saturated solution made by shaking CdS(s) with water? Ksp = 6.0x10-27 for CdS. [ A: [ Q: ][ ] ][ ] ; ][ ] √ √ A solution in equilibrium with a precipitate of AgCl was found to contain
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Measuring the Solubility Product of Ca(OH)2 Purpose: The purpose of this investigation is to find the solubility product (Ksp) of Ca(OH)2 by titrating the hydrochloric acid with calcium hydroxide and using their entities to find the concentration of Ca2+ and OH- ions. Materials: Refer to lab sheet “Measuring the Solubility of Ca(OH)2” (handout) Method (Procedure): Refer to lab sheet “Measuring the Solubility of Ca(OH)2” (handout) Observations Trial 1 Trial 2 Initial burette reading 0mL 17.75mL
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Experiment 10: Solubility Product for Calcium Hydroxide GOAL AND OVERVIEW A saturated solution of Ca(OH)2 will be made by reacting calcium metal with water‚ then filtering off the solids: Ca(s) + H2O → Ca(OH)2(s) Ca2+(aq) + 2OH-(aq) The concentration of dissolved hydroxide will be determined by acid-base titration with standardized HCl solution. The Ksp for Ca(OH)2 will be calculated from the experimentally determined saturation concentration of hydroxide. Objectives of the data analysis understand
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| [Solubility Product Constant] | Experiment 11 | | Molly McCabe | 4/18/2013 | | Data Tables: Part 1 and Part 2 Experimental Data: Standard | Calculated volume of copper sulfate in standards | Absorbance values | Blank | 0.0 mL | 0.0 | 1 | 1.25 mL | 0.094 | 2 | 3.75 mL | 0.065 | 3 | 2.50 mL | 0.099 | 4 | 3.50 mL | 0.129 | 5 | 5.00 mL | 0.187 | Collected Data | Test tube 1 | Test tube 2 | Test tube 3 | Test tube 4 | Test Tube 5 | Initial volume (mL) | 0.05
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Separation of the Components of a Mixture General Chemistry 1 (Chem 101)‚ ISP SCUHS Report 2 January 26‚ 2014 Abstract The analyses of mixture were to distinguish and identify homogeneous mixture by using the techniques of decantation and sublimation. By performing these techniques‚ we examined our solutions such as SiO2 (sand)‚ NH4Cl (ammonium chloride)‚ and NaCl (sodium chloride) and mixed H2O (water) with each solution after being heated. After examining our solutions‚ we made calculations
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