search- specific latent heat Q. Value for the specific latent heat of fusion of water: Specific latent heat is where the amount of energy (in joules) needed to change the state of 1Kg of a substance is called its specific latent of heat. You can calculate the amount of energy needed using the equation: energy (J) = specific latent heat (J/Kg) X mass (Kg) Material Specific heat of fusion (J/Kg) Specific latent heat of vaporisation (J/Kg) Water 334000 2260000 Lead 24500 871000 Ethanol
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In part A of the experiment the two values obtained for the specific heat capacity of the metal were about .0500 J/mol. This is a large deviation‚ with both of these values identifying very different metals. The average heat capacity identified the metal used as brass. The average heat capacity calculated was .3776 J/mol and the actual heat capacity of brass is .375 J/mol. The second run displayed the closest value to the actual value. A source of error that may have caused a large divide in the
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C=-43.0 C 3. Determine the mass of the water by using the water’s density (specific to the initial temperature) and the volume of the water. Remember‚ density = mass/volume. You can look up the density of the water at your specific temperature at http://www.ncsu.edu/chemistry/resource/H2Odensity_vp.htmﾧl. (5 points) Mass=density*volume=0.9987779*75=75g 4. Use the equation: q = m(SH)ΔT to solve for the amount of heat gained by the
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aluminum from the final temperature of the aluminum. ΔT = Tf - Ti (5 points) ΔT= 99°C – 28°C = 71°C 3. Determine the mass of the water by using the water’s density (specific to the initial temperature) and the volume of the water. Remember‚ density =mass/volume. You can look up the density of the water at your specific temperature at http://www.ncsu.edu/chemistry/resource/H2Odensity_vp.html. (5 points) Density =mass/volume. Density of water according to NCSU: 0.9972995 g/mL Volume of water:
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Calculate the energy change (q) of the surroundings (water) using the enthalpy equation qwater = m × c × ΔT. We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL. The water has absorbed the heat of the metal. So‚ qwater = qmetal Using the formula qmetal = m × c × ΔT‚ calculate the specific heat of the metal. Use the data from your experiment for the metal in your calculation. Aluminum: q=26*4.18*6.3=684.684‚ c=q/(m*^T)=3.913
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Report | Specific Heat Capacity of Brass | | Jin Jin Shi | 2012/12/6 | Instructor: Mr. Nailer | I. Introduction The amount of heat required to raise the temperature of a solid body depends on its change in temperature (ΔT)‚ its mass (m)‚ and an intrinsic characteristic of the material forming the body called specific heat (cp). The heat is calculated from the equation II. Purpose The purpose of this laboratory is to determine the experimental quantities of heat transfer
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Physics172Lab Lab14: Heat Capacity Lab #14 – Heat Capacity OBJECTIVES In this lab you will: Use your code from the previous week to calculate the specific heat capacity per atom of a block of aluminum containing 35 atoms. Compare your theoretical curve with experimental data‚ and explain any discrepancies. Add code to your program to calculate the heat capacity of a block of lead containing 35 atoms‚ compare the theoretical curve with experimental data‚ and explain any discrepancies. Heat capacity is
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Calorimetry Chemistry 1412 Spring 2013 Objective: Determine the calorimeter constants in a coffee cup calorimeter‚ then the calorimeter will used to determine the quantity of heat that flows in a few physical and chemical processes. Materials used: Choice I: Choice II: * Safety Goggles Safety Goggles * Distilled water Distilled water * 150 mL beaker 600 mL beaker * 50 mL graduated cylinder 50 ml graduated cylinder * Calorimeter Calorimeter
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The heat equation Specific heat capacity: The specific heat capacity of a substance is the heat required to produce a rise in 1 Kg Specific heat capacity of water ( ) ( ) ( ) Thermal capacity: It’s the quantity of heat needed to raise the temperature of the whole body by . Specific latent heat of fusion: The specific latent heat of fusion of a substance is the quantity of heat needed to change unit mass from solid to liquid without temperature change. Specific latent heat of fusion
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from the final temperature of the aluminum. ΔT = Tf - Ti (5 points) Determine the mass of the water by using the water’s density (specific to the initial temperature) and the volume of the water. Remember‚ density = mass/volume. You can look up the density of the water at your specific temperature. (5 points) Use the equation: q = m(SH)ΔT to solve for the amount of heat gained by the water from metal. You have the mass of water from
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