The oldest of four siblings‚ Loren has been attending Veritas since the 8th grade and completed her last year of high school as a Dual Enrollment student at Georgia Perimeter College. Prior to this‚ she had been homeschooled‚ with the exception of one semester in the fourth grade‚ where she attended Public “real” school in hopes of experiencing recess‚ riding the school bus‚ and cafeteria food fights. As Cumming New Life Church’s present youngest musician on the worship team‚ Loren is honored
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D = 702 144 = 180(n-2)n -36 n = -360 D= 102(10-3) D = 35 144n = 180 (n-2) n = 10 2D = 10(7) Answer: D = 35 #21. The ratio of areas between two similar triangles is 1:4. If one side of the smaller triangle is 2 units‚ find the measure of the corresponding side of the other triangle. Given: 2
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ANSWER = -a^3b^5 80. Write a simplified expression for the area of the given figure. 4y2=height 7y3=base ½ base * height = area ½ * 7y^3 *4y^2 5.3 66. (5x + 4)(x2 - 3x + 2) 5x^3-15x^2+10x 4x^2-12x+8 5x^3-11x^2-2x+8 82. Rectangular Garden A rectangular garden has a perimeter of 500 feet. (a) If one side of the garden has length x‚ then write a polynomial expression that gives its area. Multiply this expression completely. (b) Evaluate the expression
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downtown area rapidly enough. In several recent cases‚ alarms had sounded for break-ins‚ but by the time the police car arrived‚ the perpetrators had left‚ and in one instance a store owner had been shot. Sergeant Davies had been assigned by the chief to find a way to determine the optimal patrol area (dimensions) for their cars that would minimize the average time it took to respond to a call in the downtown area. Sergeant Davies solicited help from Ms. Maris‚ an analyst in the operations area for the
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curves up‚ with a flat side underneath. The opposite end is stable on the floor‚ going upward supporting a flat circular area. In the middle of that area is a hole‚ which can be described as a tunnel. Between the two ends‚ there is a loop that’s connected to both sides. The perimeter of the entire piece is a ruffle like surface. The sculpture is silver‚ with some dual and shiny areas. If you look close enough at a picture of the piece you can see circles or little dots that may be the screws. The overall
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Why Are So Many Students Still Failing Online In “Why Are So Many Students Still Failing Online‚” Rob Jenkins‚ professor of English at Georgia Perimeter College‚ brings online courses and their cons out into the open. Professor Jenkins argues in his article whether every course should be available to be taken online or if every student should be allowed to take courses online. Are the advantages that the school receives from online classes worth the failure of their students? Jenkins uses a
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population‚ retail and industry moves from urban CBD’s to the outer city. An out of town shopping centre is a group of shops and facilities that are located away from a town’s CBD. This movement will have positive and negative impacts on both the urban area and the outer city‚ where the out of town centres are built. The decentralisation of retailing and other services is happening because In order to sell goods‚ shops need to be located where people can get to them easily and its seen as easier to go
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Dan Ramirez 6/18/2013 English Professor Jenkings Final Draft Hard Work Does Pay Off When I was born my father had to leave Peru. He left my mother and I to go to the United States. He didn’t leave my mother and I because he didn’t love us anymore. He left us so that he could go work his butt off. He wanted his wife and his son to have a better life. He wanted me to have opportunities that he couldn’t have for
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OF NIGER DELTA GOAL PROGRAMMING AND ITS APPLICATION THE IMPACT OF MUSIC ADVERTISING ON SMALL SCALE BUSINESS: A CASE STUDY OF KAROFY FOOD NIGERIA LIMITED ANALYSIS OF INDISCIPLINARY PROBLEMS IN PRIMARY SCHOOLS IN BURUTU LOCAL GOVERNMENT AREA OF
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whose base angles are 55 each. If the lateral edge is 200 cm‚ find the lateral area and volume of the pyramid. 2 2 2 l – slant height h =(163.83) – (114.72) l o sin55 =200 h=116.96 cm o l=200sin55 l=163.83 cm e o cos55 =200 o 200cos55 =e e=114.72 2e=229.4 cm (163.83)(229.4) 2 2 S = 75‚175.2 cm S= 2 (229.4 )(116.96) 3 3 V= 2‚051‚181.2cm V= 4. Find the volume and total surface area of a frustum of a regular hexagonal pyramid if the base edges are 8 cm and 6 cm
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