Write the equation of a line parallel to the given line but passing through the given point.
y=1/2x+1; (4,2)
Locate the parallel Line by using the ordered pair (4,2)
Multiply ½ by x to come up with x/2
Now we have y = x/2 + 1
Let’s use the formula y = mx + b
whereas m equals slope and equals the yintercept.
Right now we know that m = ½ when using the above formula
So in order to find the equation which is parallel to y + 1/2(x + 1) the slopes will have to be equal. We must incorporate the slope of the equation to find the parallel lines by using the point slope formula. (4, 2) and m = ½
Use formula for equation of a line:
m = mx + b
Substitute the value of m into the equation
y = 1/2 (x + b)
Add the value for x into the equation
y = (1/2)(4) + b
Now put value of y in the equation
2 = (1/2)*(4) + b
Now switch b so it can be on the opposite side of the equation (1/2) *(4) + b = 2
Multiply ½ by 4 to come up with 2
2 + b = 2
Reorder polynomials
b + 2 = 2
Find be value:
b = 22
b = 0
Finally, to get the equation of the line use the values of the slope (m) and yintercept (b) in the formula y = mx + b to find the equation of the line. So the end result is y = x/2
Here is a graph displaying the origin of the parallel lines.
[pic]
Write the equation of a line perpendicular to the given line but passing through the given point. y=3x6; (1,5)
Let’s use the formula y = mx + b
slope = m and y – intercept = b
Here m = 3
The negative reciprocal right now is equal to 0.
m = 1/3
Find the equation of the line by using the point – slope formula Use the ordered pair (1, 5)
m = 1/3
Use equation of a line formula:
y = mx + b
Put the value of m into the equation:
y = 1/3x + b
Put the value of x into the equation:
y = 1/3 * 1 + b
Put the value of y into the equation:
5 = 1/3* 1 + b
Place b on the leftside of the equation:
1/3 * 1 + b = 5
Multiply 1/3 by 1 to get 1/3
1/3 + b = 5
Reorder the...
...denominator.
c≤200−12m/15
Cancel the common factor of 15 in 3000/15. Reduce the expression 3000/15 by removing a factor of 15 from the numerator and denominator.
c≤200−4m/5
Cancel the common factor of 3 in −12m/15 since −12m/15=(−4m⋅3)/(5⋅3). Reduce the expression −12m/15 by removing a factor of 3 from the numerator and denominator.
c200
The cintercept is (200,0).
The mintercept is found when c=0. To find the mintercept:...
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MAT540 Week3 Homework
Chapter 14
1. The Hoylake Rescue Squad receives an emergency call every 1, 2, 3, 4, 5, or 6 hours, according to the following probability distribution. The squad is on duty 24 hours per day, 7 days per week:
Time Between
Emergency Calls (hr.)
Probability
1
0.05
2
0.10
3
0.30
4
0.30
5
0.20
6
0.05
1.00
a. Simulate the emergency calls for...
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EDU 390 Week 1 to 3WEEK ONE
Individual: Reflection Paper on Becoming a Teacher
Write a 700 to 1,050word reflection paper on becoming a teacher that includes the following:
Reasons for wanting to become a teacher
Personal characteristics that may make you an effective teacher
How you will stay current in the field of education
How you will maintain your passion about teaching
Your educational philosophy
Learning...
...have the original expression show in simplest terms. The ‘^’ symbol is being used to show the exponent for the variable a.
2w – 3 + 3(w – 4) – 5(w – 6) We were given this expression to simplify.
2w – 3 + 3w – 12 – 5w + 30 our first step to simplify is to remove the parenthesis and do the multiplication.
2w + 3w – 5 w – 3 – 12 + 30 Now we will need to take our new expression and combine our like terms...
...CARLA IQBAL CACHE LEVEL 5 PIN:
3.1 Analyse the importance of early identification of developmental delay.
3.2 Explain the potential risks of late recognition of developmental delay.
When a child is not doing what other children his or her age usually we say they have a developmental delay. These children develop more slowly or differently from what we expect. This can be physical, cognitive, communicative, social, or emotional. For example, a child who is delayed may not...
...

Refining Solutions
It is essential to refine ideas and solutions to find the highest quality solution to a problem. The creative thinking process is used to produce ideas but the critical thinking process is used to evaluate and refine ideas and solutions. Applying criticism to ideas and solutions reduces the risk for error and makes good ideas even better (Ruggiero, 2009). In this paper Arguments will be evaluated and revised resulting in a refined and final solution to the...
...Student Exam
1/16/12 9:14 AM
Week3 : Managing Assets and Resources in the Digital Firm  Homework
Save Answers Submit for Grading
1. A characteristic or quality describing an entity is called a(n) (Points : 1)
field. tuple. key field. attribute.
2. The confusion created by _____ makes it difficult for companies to create customer relationship management, supply chain management, or enterprise systems that integrate data from different sources....
...was restoration. Today’s notion of restorative justice has several concepts that identify needs. Three of the concepts are as follow (1) the need to compensate victims, (2) the need to place appropriate responsibility on the criminal offender,
and (3) the need to attempt reintegration of the offender with the community. (Criminal Law Today: Frank Schmalleger, Ph.D.). The U.S Department of Justice did a report on restorative justice explaining it by saying “Crime was once...