Write the equation of a line parallel to the given line but passing through the given point.
y=1/2x+1; (4,2)
Locate the parallel Line by using the ordered pair (4,2)
Multiply ½ by x to come up with x/2
Now we have y = x/2 + 1
Let’s use the formula y = mx + b
whereas m equals slope and equals the yintercept.
Right now we know that m = ½ when using the above formula
So in order to find the equation which is parallel to y + 1/2(x + 1) the slopes will have to be equal. We must incorporate the slope of the equation to find the parallel lines by using the point slope formula. (4, 2) and m = ½
Use formula for equation of a line:
m = mx + b
Substitute the value of m into the equation
y = 1/2 (x + b)
Add the value for x into the equation
y = (1/2)(4) + b
Now put value of y in the equation
2 = (1/2)*(4) + b
Now switch b so it can be on the opposite side of the equation (1/2) *(4) + b = 2
Multiply ½ by 4 to come up with 2
2 + b = 2
Reorder polynomials
b + 2 = 2
Find be value:
b = 22
b = 0
Finally, to get the equation of the line use the values of the slope (m) and yintercept (b) in the formula y = mx + b to find the equation of the line. So the end result is y = x/2
Here is a graph displaying the origin of the parallel lines.
[pic]
Write the equation of a line perpendicular to the given line but passing through the given point. y=3x6; (1,5)
Let’s use the formula y = mx + b
slope = m and y – intercept = b
Here m = 3
The negative reciprocal right now is equal to 0.
m = 1/3
Find the equation of the line by using the point – slope formula Use the ordered pair (1, 5)
m = 1/3
Use equation of a line formula:
y = mx + b
Put the value of m into the equation:
y = 1/3x + b
Put the value of x into the equation:
y = 1/3 * 1 + b
Put the value of y into the equation:
5 = 1/3* 1 + b
Place b on the leftside of the equation:
1/3 * 1 + b = 5
Multiply 1/3 by 1 to get 1/3
1/3 + b = 5
Reorder the...
...a factor of 15 from the numerator and denominator.
c≤200−12m/15
Cancel the common factor of 15 in 3000/15. Reduce the expression 3000/15 by removing a factor of 15 from the numerator and denominator.
c≤200−4m/5
Cancel the common factor of 3 in −12m/15 since −12m/15=(−4m⋅3)/(5⋅3). Reduce the expression −12m/15 by removing a factor of 3 from the numerator and denominator.
c200
The cintercept is (200,0).
The mintercept is found when c=0. To find the mintercept:
12m≤−15c+3000
Since 15c does not contain the variable to solve for, move it to the righthand side of the inequality by subtracting 15c from both sides.
12m≤3000−15c
Reorder the polynomial −15c+3000 alphabetically from left to right, starting with the highest order term.
12m/12≤3000/12−15c/12
Divide each term in the inequality by 12.
m≤3000/12−15c/12
Cancel the common factor of 12 in 12m/12. Reduce the expression 12m/12 by removing a factor of 12 from the numerator and denominator.
m≤250−15c/12
Cancel the common factor of 12 in 3000/12. Reduce the expression 3000/12 by removing a factor of 12 from the numerator and denominator.
m≤250−5c/4
Cancel the common factor of 3 in −15c/12 since −15c/12=(−5c⋅3)/(4⋅3). Reduce the expression −15c12 by removing a factor of 3 from the numerator and denominator.
m250
The mintercept is (0,250).
Because this is a “less than equal to” inequality,...
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MAT540 Week3 Homework
Chapter 14
1. The Hoylake Rescue Squad receives an emergency call every 1, 2, 3, 4, 5, or 6 hours, according to the following probability distribution. The squad is on duty 24 hours per day, 7 days per week:
Time Between
Emergency Calls (hr.)
Probability
1
0.05
2
0.10
3
0.30
4
0.30
5
0.20
6
0.05
1.00
a. Simulate the emergency calls for 3 days (note that this will require a “running”, or cumulative, hourly clock), using the random number table.
b. Compute the average time between calls and compare this value with the expected value of the time between calls from the probability distribution. Why are the results different?
2. The time between arrivals of cars at the Petroco Service Station is defined by the following probability distribution:
Time Between
Arrivals (min.)
Probability
1
0.15
2
0.30
3
0.40
4
0.15
1.00
a. Simulate the arrival of cars at the service station for 20 arrivals and compute the average time between arrivals.
b. Simulate the arrival of cars at the service station for 1 hour, using a different stream of random numbers from those used in (a) and compute the average time between arrivals.
c. Compare the results obtained in (a) and (b).
3. The Dynaco Manufacturing Company produces a product in a process consisting of operations...
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EDU 390 Week 1 to 3WEEK ONE
Individual: Reflection Paper on Becoming a Teacher
Write a 700 to 1,050word reflection paper on becoming a teacher that includes the following:
Reasons for wanting to become a teacher
Personal characteristics that may make you an effective teacher
How you will stay current in the field of education
How you will maintain your passion about teaching
Your educational philosophy
Learning Team: Section Summary
The Learning Team will review the sections of the Learning Team Toolkit. Each member of the team will choose one of the following sections and post a summary in the Learning Team forum. Team members should comment as appropriate to ensure smooth and efficient operation of the team. Sections to summarize:
Getting Started
Getting to Results
Project Planning
Decisions/Conflict Resolution
Team Learning
NOTE: This is an individual assignment NOT a group summary. Each member will post their section to a thread in the Learning Team for all other members to reference. The sooner this is posted, the sooner the team can move forward with the other Learning Team activities.
WEEK TWO:
Individual Program Progression Requirement: Personal Assessment Interview
Complete the Personal Assessment Interview activity posted in the Main forum (available after Wednesday of Week 1). The purpose of this interview is to determine your disposition...
...assignments. Below I will show a few examples of Algebra simplifying some expressions using the distribution properties with like terms and coefficients.
2a (a – 5) + 4(a – 5) we were given this expression to simplify.
Simplifying this expression will first involve using the distribution property to remove the parenthesis
2a *a + 2a * 5 + 4 * a + 4 *5 Now we will take our new expression and combine like terms by adding the coefficients
2a^2 +6a 20 We now have the original expression show in simplest terms. The ‘^’ symbol is being used to show the exponent for the variable a.
2w – 3 + 3(w – 4) – 5(w – 6) We were given this expression to simplify.
2w – 3 + 3w – 12 – 5w + 30 our first step to simplify is to remove the parenthesis and do the multiplication.
2w + 3w – 5 w – 3 – 12 + 30 Now we will need to take our new expression and combine our like terms by adding our coefficients.
15 15 represents our original expression in its simplest terms.
0.05(0.3m + 35n) – 0.8(0.09n – 22m) our final expression is given to the left.
Simplifying this expression by using the distribution
property first to remove the parenthesis.
0.3m * 0.05 + 35n * 0.05 + 0.8 *0.09n + 0.8 * 22m
Once we have removed the entire parenthesis we will complete the needed multiplication properties for this...
...CARLA IQBAL CACHE LEVEL 5 PIN:
3.1 Analyse the importance of early identification of developmental delay.
3.2 Explain the potential risks of late recognition of developmental delay.
When a child is not doing what other children his or her age usually we say they have a developmental delay. These children develop more slowly or differently from what we expect. This can be physical, cognitive, communicative, social, or emotional. For example, a child who is delayed may not begin to talk when others do or may have some other difficulties which cause concern. In some cases there may be an obvious reason but in other cases the reason may be unclear. Some children can catch up to other children his or her age with no assistance, many will not. For example, a child who has a hearing loss will eventually learn to speak, but he or she may learn incorrect pronunciations of words, miss out socially and become frustrated and angry. When hearing loss is diagnosed early, a child can be fitted with a hearing aid and work with a speech therapist to avoid falling behind. Therefore, it is a good idea to get an early intervention team to examine a child experiencing learning difficulties and determine if special assistance is needed. Small problems are then contained and with the correct support will remain small and not escalate into bigger issues if left unattended.
However if intervention is too soon this can be detrimental to the child. There could be a...
...

Refining Solutions
It is essential to refine ideas and solutions to find the highest quality solution to a problem. The creative thinking process is used to produce ideas but the critical thinking process is used to evaluate and refine ideas and solutions. Applying criticism to ideas and solutions reduces the risk for error and makes good ideas even better (Ruggiero, 2009). In this paper Arguments will be evaluated and revised resulting in a refined and final solution to the problem.
Original Issue
How do I express an issue with laziness towards employees without being disrespectful or appear as if I’m attacking them?
Through close observation of my coworkers I realized that they do slack off from time to time and that’s either because they had a bad morning or they just have something on their mind that makes them inattentive to the work that is coming their way. That is why they end up falling behind on their side and of course I have to jump in and help them out a bit because customers are waiting for their glasses and it doesn’t help the business when we have to keep refunding the sales due to tardiness.
Initial Solutions
With the importance of having the respect towards other individuals in the work place I put my imagination to work and brainstormed for solutions. Initial solutions included:
▪ accept my position at work and help an individual out when they are down
▪ Let them take out the work on their own
▪ Help the teammates out a little with...
...Student Exam
1/16/12 9:14 AM
Week3 : Managing Assets and Resources in the Digital Firm  Homework
Save Answers Submit for Grading
1. A characteristic or quality describing an entity is called a(n) (Points : 1)
field. tuple. key field. attribute.
2. The confusion created by _____ makes it difficult for companies to create customer relationship management, supply chain management, or enterprise systems that integrate data from different sources. (Points : 1)
batch processing data redundancy data independence online processing
3. Duplicate data in multiple data files is called (Points : 1)
data redundancy. data multiplication. data independence. data backups.
4. A DBMS (Points : 1)
makes the physical database available for different logical views. makes the logical database available for different analytical views. makes the physical database available for different analytical views. makes the relational database available for different analytical views.
5. The logical view (Points : 1)
shows how data are organized and structured on the storage media. presents an entry screen to the user. allows the creation of supplementary reports. presents data as they would be perceived by end users.
6. The type of logical database model that treats data as if they were stored in twodimensional tables is the (Points : 1)
OODBMS. predigital DBMS. relational DBMS. hierarchical DBMS.
7. A field identified in a...
...between a victim and the offender. Most time the offender will default on their agreement, and this will cause them to go unpunished. When this happens, a criminal will continue to commit criminal acts because he or she believes that nothing will be done. Prisons will continue to be overcrowded with prisons because restorative justice does not eliminate the criminal acts by criminals (Mantle, Fox, & Dhami, 2008).
Concept of restorative justice
For many years, the goal for sentencing was restoration. Today’s notion of restorative justice has several concepts that identify needs. Three of the concepts are as follow (1) the need to compensate victims, (2) the need to place appropriate responsibility on the criminal offender,
and (3) the need to attempt reintegration of the offender with the community. (Criminal Law Today: Frank Schmalleger, Ph.D.). The U.S Department of Justice did a report on restorative justice explaining it by saying “Crime was once defined as a ‘violation of the state.’ This remains the case today, but we now recognize that crime is far more. It is—among other things—a violation of one person by another. While retributive justice may address the first type of violation adequately, restorative justice is required to effectively address the latter. . . . Thus, [through restorative justice] we seek to attain a balance between the legitimate needs of the community, the . . . offender, and the victim.” (Criminal Law Today: Frank...