Unknown Mixture
Analysis of an Unknown Mixture
Performed: 2/13/14
Submitted: 3/3/14
Abstract: The purpose of this experiment was to separate and identify the two unknown compounds. The sample used was 105 and it contain 2-propanol and 2-heptanone. IR spectrums were taken of the contents of the second and sixth test tubes and showed the presence of an OH functional group and a small amount of ketone in test tube two and a large presence of ketone in test tube six. The average boiling points of the test tubes, 73°C and 162°C respectively, were compared to the boiling points in the tables of alcohols and ketones found in the back of the lab manual. Test tube two was comparable to methanol, ethanol, 2-propanol, and 2-methyl-2-propanol. Upon inspection of the IR spectrums, 2-propanol was a match. …show more content…
Test tube two was 73°C and test tube five was 162°C. The boiling point for test tube five was applied to test tube six because the substance is the same, so the boiling point should be the same as well. Any time the fume hood was opened during the distillation period, there were fluctuations in the temperature; the longer the fume hood remained open, the larger the fluctuation would be. The temperature fluctuations may have contributed to the presence of ketone in the first substance. Vapor of 2-heptanone would have gone up and condensed through with the 2-propanol vapor if it reheated too quickly. Test tube two was used because the compounds start mixing during the collection of the third test tube, as can be seen by the increasing temperature readings, and there’s more possibility of getting impurities in the first test tube while it is starting out. By the time the solution gets to the last 5mL that goes into the sixth test tube, everything that is not the second compound has boiled off and been collected, so the sixth test tube is the most pure for the second
Performed: 2/13/14
Submitted: 3/3/14
Abstract: The purpose of this experiment was to separate and identify the two unknown compounds. The sample used was 105 and it contain 2-propanol and 2-heptanone. IR spectrums were taken of the contents of the second and sixth test tubes and showed the presence of an OH functional group and a small amount of ketone in test tube two and a large presence of ketone in test tube six. The average boiling points of the test tubes, 73°C and 162°C respectively, were compared to the boiling points in the tables of alcohols and ketones found in the back of the lab manual. Test tube two was comparable to methanol, ethanol, 2-propanol, and 2-methyl-2-propanol. Upon inspection of the IR spectrums, 2-propanol was a match. …show more content…
Test tube two was 73°C and test tube five was 162°C. The boiling point for test tube five was applied to test tube six because the substance is the same, so the boiling point should be the same as well. Any time the fume hood was opened during the distillation period, there were fluctuations in the temperature; the longer the fume hood remained open, the larger the fluctuation would be. The temperature fluctuations may have contributed to the presence of ketone in the first substance. Vapor of 2-heptanone would have gone up and condensed through with the 2-propanol vapor if it reheated too quickly. Test tube two was used because the compounds start mixing during the collection of the third test tube, as can be seen by the increasing temperature readings, and there’s more possibility of getting impurities in the first test tube while it is starting out. By the time the solution gets to the last 5mL that goes into the sixth test tube, everything that is not the second compound has boiled off and been collected, so the sixth test tube is the most pure for the second