Does asymptotic mean that the normal curve gets closer and closer to the X-axis but never actually touches it?

Yes, asymptotic means that the curve of a line will approach 0 (the x-axis), but it will not touch 0 and instead will extend to infinity. In this class, this applies to the normal continuous distribution and is one of the 4 key characteristics of a normal continuous distribution that our text book discusses. This means that the curve of the line will extend infinitely in both the negative and positive direction in exact mirror image patterns on either side of the mean.

For a normal probability distribution, is about 95 percent of the area under normal curve within plus and minus two standard deviations of the mean and practically all (99.73 percent) of the area under the normal curve is within three standard deviations of the mean?

Yes. According to the Empirical Rule:
-68% of the area under the curve is within +/- 1 standard deviation of the mean -95% of the area under the curve is within +/- 2 standard deviations of the mean -Virtually all, 99.7% of the area under the curve is within +/- 3 standard deviations of the mean

Is a z-score the distance between a selected value (X) and the population mean (u) divided by the population standard deviation(s)? Yes. We use z-scores to change normal probability distributions into standard normal probability distributions, which are unique because they have a mean of 0 and standard deviation of 1. To convert to a standard normal probability distribution we must find the z-scores for each observation. These are found by subtracting the mean value from the selected value and dividing by the standard deviation.

The Normal Probability Distribution
Find an example of application of probability theory in your workplace or business. Show that the reasons that your workplace uses probability analysis, such as probability of risk calculations or percent defects or percent for pass or fail of a...

...Chapters 1-3:In order to control costs, a company wishes to study the amount of money its sales force spends entertaining clients. The following is a random sample of six entertainment expenses (dinner costs for four people) from expense reports submitted by members of the sales force. $157, $132, $109, $145, $125, $139. Calculate the mean and sample variance(s^2) and standard deviation. Mean = 807/6 = 134.5. Sample Variance = (109925 – (807^2/6)/6-1 = (109925 – 108541)/5 = 1384/5 = 276.8. Standard Deviation = √276.8 = 16.6373. ***the 109925 is all values of x individually squared and then summed together. ***the 6-1 is because it is a sample, if this were a population it would just be 6. ***the 807 is the sum off all x. Coefficient of Variation = (16.63/134.5)*100 = 12.3643. Calculate estimates of tolerance intervals containing 68.26, 95.44, and 99.73 percents. Mean ± 1 SD (68.26%) = 134.5 ± 16.63 = [117.87, 151.13]. Mean ± 2 SD (95.44%) = 134.5 ± 33.26 = [101.24, 167.76]. Mean ± 3 SD (99.73%) = 134.5 ± 49.89 = [84.61, 184.39]. Compute and interpret some of the Z-scores. (157-134.5)/16.63 = 1.35 standard deviations above the mean. (109-134.5)/16.63 = -1.53 standard deviations below the mean.
Mean is the average of all the data. Mode is the number that occurs most frequently in the data set. Median is the middle value or average of the two middle values when the data is arranged in order from smallest to larges.
Chapter 4: Basic Probability...

...Department of statisticsStatistics for Business, Stat 130
Midterm exam
November 15, 2011
Form B
Name: | I.D. Number: |
Instructions:
* Write your name and student ID.
* You have one hour and thirty minutes to complete the exam.
* You may use a formula sheet and a calculator. No other outside materials are allowed.
* There are seven problems in the exam.
* Total score of points is 20.
Problem 1:(5 points) Multiple-choice questions:
Question 1: If A and B are mutually exclusive events, with P(A) = 0.6 and P(B) =0 .4, then P(A and B) is:
a. 0.50
b. 0.00
c. 0.24
d. 1.00
Question 2: As the sample size, n, increases, what happens to the shape of the sampling distribution of the means?
a. approaches the uniform distribution
b. positively skewed
c. approaches a normal distribution
d. negatively skewed
Question 3: Which of the following statements is correct?
a. A point estimate is an calculated from the population
b. A point estimate is an estimate of the range of a population parameter
c. A point estimate is a single value estimate of the value of a population parameter
d. All of the above
Question 4: Sampling distributions describe the distribution of
a. sample statistics
b. population parameters
c. neither parameters nor statistics
d. both parameters and...

...of 1000 flights and proportions of three routes in the sample. He divides them into different sub-groups such as satisfaction, refreshments and departure time and then selects proportionally to highlight specific subgroup within the population. The reasons why Mr Kwok used this sampling method are that the cost per observation in the survey may be reduced and it also enables to increase the accuracy at a given cost.
TABLE 1: Data Summaries of Three Routes
Route 1
Route 2
Route 3
Normal(88.532,5.07943)
Normal(97.1033,5.04488)
Normal(107.15,5.15367)
Summary Statistics
Mean
88.532
Std Dev
5.0794269
Std Err Mean
0.2271589
Upper 95% Mean
88.978306
Lower 95% Mean
88.085694
N
500
Sum
44266
Summary Statistics
Mean
97.103333
Std Dev
5.0448811
Std Err Mean
0.2912663
Upper 95% Mean
97.676525
Lower 95% Mean
96.530142
N
300
Sum
29131
Summary Statistics
Mean
107.15
Std Dev
5.1536687
Std Err Mean
0.3644194
Upper 95% Mean
107.86862
Lower 95% Mean
106.43138
N
200
Sum
21430
From the table above, the total number of passengers for route 1 is 44,266, route 2 is 29,131 and route 3 is 21,430 and the total numbers of passengers for 3 routes are 94,827.
Although route 1 has the highest number of passengers and flights but it has the lowest means of passengers among the 3 routes. From...

...
Business Analytics: Unit 1: Descriptive Statistics and Mathematical Foundations
Kaplan University
March 23, 2014
Descriptive Statistics and Mathematical Foundations
Part I: Pie Chart & Bar Graph
This information regards T-100 Domestic Market’s boarding information during the previous year for the top seven airlines in the United Sates. According to the data Southwest Airlines boarded 81.1 million; Delta Airlines, 79.4 million; American Airlines, 72.6 million; United Airlines, 56.3 million; Northwest Airlines, 43.3 million; U.S. Airways, 37.8 million, and Continental Airlines, 31.5 million (KU, 2014).
This is ungrouped data that needs to be grouped into a pie chart and a bar graph. The bar graph and pie chart both lists nonmetric (qualitative) descriptive statistics. The descriptive statistics are called, ordinal statistics which rank each airline from highest to lowest or lowest to highest annual boarding information (Black, 2012). The pie chart and bar graph summarizes the top seven airlines previous years boarding data. First, I will discuss the pie chart. The pie chart below shows the percentage breakdown of each airline’s annual boarding information. Each of the breakdowns represents the magnitude of the whole pie chart in percentages (Black, 2012). As you will notice that the leaders in the airline industry is Southwest and Delta Airlines with 20 percent...

...
Group Assignment
BusinessStatistics
CBEB1109
Tutorial : Tuesday 11.00am – 12.00pm
Instructor : Dr. Sharifah Latifah Binti Syed A Kadir
Group : Group 2
Group Members :
1.
Kao Wei Jian
CEA 130028
2.
Lim Kin Chun
CEA 130041
3.
Amirul Asyraaf bin Azhar
CEA 130002
4.
Nur Hasfaiza bt Mohd Zaid
CEA 130063
5.
Muhammad Hamdin Zarif Bin Mohd Zaidi
CEA 100062
6.
Lim Sin Pei
CEA 130043
7.
Wong Siew Yen
CEA 130097
1. Of 100 individuals who applied for systems analyst positions with a large firm during the past year, 40 had some prior work experience, 30 had a professional certificate and 20 of them had both work experience and a certificate.
a Determine if work experience and certification are independent events.
Let A = Prior Work experience
B = Professional Certificate
A
A’
Total
B
20
30
50
B’
40
10
50
Total
60
40
100
=
= 0.4
P(A) =
= 0.6
, so it is not an independent event.
b What is the probability that a randomly chosen applicant,
i had either work experience or a certificate?
) =
=
= 0.9
ii has neither work experience nor a certificate?
iii has a certificate if he has some previous work experience?
= 0.33
2. Because of economic conditions, a firm reports that 30 percent if its accounts receivable from other business firms are overdue. If an accountant takes a random sample of 10 such accounts, determine the probability that
p=30% @ 0.3
n=10
X~B(10,0.3)
a. none of the account is overdue
By...

...
BusinessStatistics II: Research Paper
Robert Franjieh
April 19, 2015
Introduction
This research paper will be designed to answer a couple questions regarding statistics about the Buena School District school bus data. The questions I will be discussing and answering will be based on maintenance of the school busses. The question prepared is; is it cheaper or more expensive to run Thompson, Bluebird, or Keiser busses? I will also be addressing another question based on other variables by removing the gas types and making it just one gas type instead of two; does gas type have anything to do with the maintenance of the Thompson, Bluebird and Keiser busses when removed from the regression? In order to answer these questions, both regressions and data sets do not contain the 6 passenger busses, being there are only very few and that they might skew the regression.
To explain a little about maintenance on busses, a routine oil change can run anywhere between $150-$250. Diesel engines can go 6,000 to 10,000 miles between oil changes depending on idling time and driving time. If you buy a used bus, one of the first major components that may fail you is the turbocharger. Expect to pay $1,700-$2,000 for a replacement. A tire for a bus can easily cost anywhere between $400-$600. This does not include the price of installation. If your bus should break down, you will need a heavy-duty...

...Omkar & Yaying
Wednesday 5-6pm
WEEK 3 BES PASS
Descriptive Statistics Population - a set of all possible observations. Sample - a portion of a population. We often use information concerning a sample to
make an inference (conclusion) about the population.
Parameter - describes a characteristic of the population, eg: the population variance Statistic- describes a characteristic of a sample, eg: the sample variance
Frequency Distribution and Histograms Class - a collection of data which are mutually exclusive Frequency distribution - a grouping of data into classes Relative frequency distribution - calculates the number of data in a class as a percentage
of the total data
Shapes of Distributions and Histograms
A histogram is symmetrical if one half of the histogram is a mirror reflection of the other Non-symmetrical distributions are said to be “skewed”
a) Skewed to the right (Positively skewed) Mode < Median < Mean
b) Skewed to the left (Negatively skewed) Mode > Median > Mean
c) Symmetric Distribution Mode = Median = Mean
Measures of Central Tendency: The Mean, Mode and Median The mean is the average of scores: Population mean: μ = Σ xi/N
Sample mean: x = Σ xi/n
The mode is the value that has the highest frequency The median is the middle value of data ordered from lowest to highest The median and the mode are relatively less sensitive to outliers.
Quartiles and Percentiles,...

...balances by branch. Does it appear that account balances are related to the branch?
|Branch |Smallest third |Middle third |Largest third |
|Ohio |8 |6 |2 |
|Georgia |1 |6 |10 |
|Kentucky |5 |5 |4 |
|Pensylvania |6 |3 |4 |
Ho: Account balances are independent of branch.
H1: Account balances are independent of branch
Test Statistic:
Chi square is given by (Oi – Ei)^2 / Ei ~ χ2 with 2*3= 6 degrees of freedom
The calculated value of chi-square is 11.89625
Critical value for 5% level of significance is 12.5916
Since the calculated value is less than critical value we accept null hypothesis and conclude that account balances are not related to the branch
g. Cite some examples and comment on your findings.
If we wish to know if any distinction is made in appointment on the basis of sex for the following data
| |Employed |Not Employed |Total |
|Male |1480 |5720 |7200 |
|Female |120...

453 Words |
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