Jordan Hunt P.3
POW Write Up; Just Count the Pegs
Problem Statement:
For the POW: Just Count the Pegs, I had to try and find the best formula possible for finding the area of any polygon on a geoboard. There are 3 different formulas you have to find. The first two are formulas that will combine together and help you find the best or “superformula”. In order to find the first two, you will make in and out tables. You will find the pattern and then come up with a formula for it. For the first part, you have to find a formula that works for polygons with one peg in the interior. For the second one you have to find the formula for the area of polygons with exactly four pegs on the boundary. Using both of these, you then find a formula that will work for any polygon. Process:

I started off by figuring out Freddie and Sally’s formulas. I had to find these two first in order to find the “superformula.” In | Out|
3| .5 |
4| 1|
5| 1.5 |
I completed Freddie’s first. Freddie’s was the easiest to find because it was a technique I had used, without really knowing it. I started out by drawing a simple in and out table. In or x was the number of pegs on the boundary of the polygon. The out or y was the area of the figure. Then I made multiple polygons on geoboard paper. I counted the pegs and calculated the area and added them to my in/out table. I used the numbers 3-5 in my table. I then looked at my table for a while and tried to find patterns in it. At first I thought it could possibly be something as simple as x plus 1 = y. Then I saw 3 was .5 and new that wouldn’t work. So I started looking at other patterns and tried out many things. Finally I came up with x/2-1=Y. I tried this for all 5 numbers and it worked for every single one of them. So, that was Freddie’s formula. In| Out|

0| 1|
1| 2|
2| 3|

Sarah’s formula was a lot more difficult for me because I was confused by what I...

...Justcount the Pegs
Freddie Short has a new shortcut to find the area of any polygon on the geoboard that has no pegs on the interior. His formula is like a rule for an In-Out in which the In is the number of pegs on the boundary and out is the area of the figure.
Sally Shorter has a shortcut for any geoboard polygon with exactly four pegs on the boundary. All you have to tell her is how manypegs are in the interior and she can use her formula to find the are immediately.
Frashy Shortest says she has the best formula in which you make any polygon on the geoboard and tell her both the number of pegs in the interior and the number of pegs on the boundary and her formula will give you the area immediately.
Your goal in this POW is to find Frashy’s super formula but tou might want to begin with her friends formulas.
1 Begin with Freddy’s formula
a. Find a formula for the area of polygons with no pegs in the interior. The number of boundaries is the In and the Out is the area in the In-Out table.
b. Find a different formula that works for polygons with one peg in the interior.
c. Pick a number bigger than one and find the area with that number of pegs in the interior.
d. Do more cases like question c
2.Find Sally’s formula and others like it, as described in 2a through...

...POW 8
Problem Statement-
For this POW, our task was to find the best formula for finding the area of any polygon that is formed on a geoboard. In order to do this, there are two formulas given to help you. One tells how to get the area of a polygon based on the number of pegs on the boundary. This works as an In-Out table, where In is the amount of pegs on the boundary, and Out is the area. The other formula tells how to get the area by having a polygon with exactly four pegs on the boundary. All you do is tell her how many pegs are on the inside. Using her formula, she can give you the area immediately. Using these two formulas for reference, we have to find a formula that anyone can use to find the area of any polygon by knowing the number of pegs on the boundary and interior.
Process-
The first two equations by Freddie and Sally were a preparation for the final, building up the information in order to find the "superformula".
For Freddie's equation, I drew an In-Out table, with the number of pegs on the boundary for the In/x value, and the area of the polygon for the Out/y value. With this table set up, I made some different polygons on geo-paper (attached), and plugged them into the table. I found the area for all of them by looking at the figure. However, just looking at the figure was not very accurate, so I looked for...

...Problem Statement
My task was to find 3 equations, that would give me an answer, if I had certain information. The first was to find one that if you knew that there were four pegs on the boundary, and none on the interior, you could get the area. The second was if you knew that there were 4 pegs on the boundary, and you knew how many were on the interior, you could get the area. And last, if you had the number on the interior, and the number on the boundary, you could get the area.
Process
The first two equations, were a preparation for the final, building up towards the complete idea. This helped, because I could complete the first two pretty quickly.
For Freddie I drew a 3 column T-Table, with a drawing of the figure, the number of Pegs (in), and the Area (out). I looked for a pattern between the in and the out, and quickly found one that made sense, and I worked it into a formula. I got X/2-1=Y. Where X is IN (number of pegs) and Y is OUT (Area). This works in all shapes with no interior pegs, like Freddie described. I attached this T-Table.
For Sally I followed my luck of the 3 column T-Table, and drew another with the same guidelines. The figure, the interior pegs (in), and the area (out). After I filled in a few figures, and their properties, I noticed a pattern, and not long after, a formula, which worked for them. It was X+1=Y. This T-Table is also attached.
Now...the...

...1) What is an Entity Manager?
1) It is the service object that manages entity life-cycle instances.
2) It is a set of entity instances.
3) It is a unique value used by the persistence provider.
4) It is a value that is used to map the entity instance to the corresponding table row in the database.
Solution : 1
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2) Which of the following properties of an entity specifies the propagation of the effect of an operation to associated entities?
1) Cascade
2) Ownership
3) Cardinality
4) Direction
Solution : 1
--------------------------------------------------------
3) Which of the following entity manager methods forces the synchronization of the database with entities in the persistence context?
1) flush
2) refresh
3) contains
4) merge
Solution : 1
--------------------------------------------------------
4) Which of the following options is true about mapped superclass? .i
1) It is a plain Java technology interface that is designated with the MappedSuperclass annotation.
2) It is created to provide state and the corresponding object/relational mapping information to child classes through the inheritance mechanism.
3) It can be passed as arguments to methods of the EntityManager or uery interfaces.
4) It is a target of a persistent relationship.
Solution : 2
--------------------------------------------------------
5) Which of the following options is a...

...Traffic Volume Counts
Prepare
Select Location
Complete Study
1.
2.
3.
4.
Communicate with other staff/departments
Review historical data trends
Review citizen input
Request traffic control
1. Select the proper location
2. Plan the data collection preparations
3. Complete the pre-study documentation
1. Collect the data
2. Evaluate the data
3. Calculate the traffic volume trends
Document
1. Finalize the report
2. File the report
3. Communicate the results
INTRODUCTION
Traffic volume studies are conducted to determine the number, movements, and classifications of roadway
vehicles at a given location. These data can help identify critical flow time periods, determine the influence
of large vehicles or pedestrians on vehicular traffic flow, or document traffic volume trends. The length of
the sampling period depends on the type of count being taken and the intended use of the data recorded.
For example, an intersection count may be conducted during the peak flow period. If so, manual count
with 15-minute intervals could be used to obtain the traffic volume data.
U S I N G C O U N T P E R I O D TO D E T E R M I N E S T U D Y M E T H O D
Two methods are available for conducting traffic volume counts: (1) manual and (2) automatic. Manual
counts are typically used to gather data for determination of vehicle classification, turning movements,...

...I didn’t prepare too much and was luckily got a satisfy mark. However, the last two secondary years were the hardest years. I studied Chinese, Use of English, Chinese History, Geography and Economics in AL.
In the summer before the AL exam, make-up classes and tests were full of my schedule. I have to say that it was so tired. The pressure was just pushing me away from the books and notes; I didn’t want to face it. I still used all my effort and time to prepare for the tests at school; finally, there was no extra time for me to seriously follow my AL study plan. The mock exam was prepared in a very short time. I tried to cover all the materials shortly before the mock. The result is worst. However, after going through all this, I realize the most important thing is not letting your school affect you too much.
To prepare for the public exam, planning is important. As a student with experience, I believe it is hard to get through the hard time without a timetable or a proposal. Believe me, the pressure and the load will make you want to stay away from everything. If you do not plan for it, the load in the following days will just accumulate, only getting more and being harder. I did not plan one in CE exam as CE is easier. However, I found out if I do not make one I do not know how to start the AL studying with the large amount of materials, for example, Chinese History has 5 books with 250 pages respectively and with box of notes. Thus, a...

...Abstract
Following the Paris Peace Accords, Operation Homecoming returned 591 American prisoners of war (POWs) to the US. At the time, over 1,300 prisoners were listed as missing in action (MIA). An additional 1,200 were killed in action (KIA) and body not recovered. In the ensuing 20 years, activist groups pushed the American government to look into the matter, and several investigations were launched. While no governmental investigation has determined that AmericanPOWs were left behind, there remains considerable evidence that the POW MIA issue contains validity.
The Agreement on Ending the War and Restoring Peace in Vietnam was signed on January 27, 1973. This document, finalized during the Paris Peace Accords, signaled the end of the United States’ involvement in the Vietnam War. The Democratic Republic of Vietnam (North Vietnam), the Republic of Vietnam (South Vietnam), and the Provisional Revolutionary Government (representing various South Vietnamese insurgents) joined the US in signing this historic treaty. The agreement called for the release of US prisoners of war, along with assistance in recovering and transporting home the remains of deceased soldiers. Due in large part to a lack of reliable intelligence in North Vietnam, the US government never knew truly how many prisoners of war were held.
In the years since the war ended, there has been substantial evidence to indicate that many prisoners were left...

...POW 15 Growth of rat populations Problem Statement This problem is composed of the growth of a rat population over the course of one year from 2 rats. Four assumptions for this problem were made: Each new liter is composed of 6 rats; 3 males, 3 females. The original pair give birth to 6 rats on the first day and then ever 40 days after. There is a 120 day "gestation" period before a newborn rat can reproduce. After this gestation period the rats will give birth every 40 days. Also over the course of a year no rats die. The key question is how many rats are there after one year. Process In order to solve this problem I first focused on getting an answer for the number of rats. Originally I had planned to use a large sheet of poster board paper to draw out the family tree. But quickly realized that this would be quite impractical. I then settled on a similar but more efficient method. In this method I focused on the 10 liters that the original parents produced. The 10 liters comes from the fact that there is 365.25 days in a year and the parent liter produce every 40 days from day zero. Meaning that they will have a liter on day 0, 40, 80, 120, 160, 200, 240, 280, 320, and 360. I started on the day 360 liter and worked backwards. After finishing this method I compiled the data in a spreadsheet. From which I was able to sum each interval of rat births. The data collected in family tree method is shown in the following data table:
Couple: Original D0 D40 D80...

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