Nt1310 Unit 7

1) Identify the three IP address classes, the default subnet mask used with each, and the number of hosts for each.
The three IP address classes are class A, class B, and class C.
Default subnet mask for class A = 255.0.0.0
Default subnet mask for class B = 255.255.0.0
Default subnet mask for class C = 255.255.255.0
The number of hosts that class A can have is 16,777,214
The number of hosts that class B can have is 65,534
The number of hosts that class C can have is 254
2) What is the subnet ID of host 86.212.118.145, given a subnet mask of 255.0.0.0? Explain your answer.
Subnet ID = 86.0.0.0
The first 8 bits of the host address and set the rest of the numbers in the address to 0.
3) What is the subnet ID of host 192.168.18.145, given a subnet mask of
4) What is the broadcast address for IP address 123.45.67.89 with a subnet mask of 255.255.0.0? Show how you determined the broadcast address.
The broadcast address is 123.45.255.255
Since it’s a class B address. I took the first and second set of number from the IP address and added them to the first and second part of the subnet mask. Pushing the first 2 numbers of the subnet mask to the third and fourth spot.
5) You want to divide a class C network into 12 subnets. Which subnet mask will you use to get the most hosts on each network? How many hosts will be on each subnet? Explain your answer.
Use a subnet mask of 255.255.255.240 = 16 subnets and 14 hosts per.
Theres 4 bits for hosts and 4 for network numbers. Each set = 16 then just subtract one address for the network number and broadcast number for the hosts per.
6) You want to divide a class B network into 100 subnets. Which subnet mask will you use to get the most hosts on each subnet? How many hosts will be on each subnet? Explain your answer.
Use a subnet mask of 255.255.254.0 = 128 subnets and 510 hosts