Gcse Math Question Paper

Sp N ec e ifi w ca tio n

General Certificate of Secondary Education January 2012

Mathematics Unit T4 Higher Tier
[GMT41]
WEDNESDAY 11 JANUARY

9.15 am–11.15 am

MARK SCHEME

7280.01

GCSE MATHEMATICS Introduction The mark scheme normally provides the most popular solution to each question. Other solutions given by candidates are evaluated and credit given as appropriate; these alternative methods are not usually illustrated in the published mark scheme. The solution to a question gains marks for correct method and marks for accurate working based on this method. The marks awarded for each question are shown in the right hand column and they are prefixed by the letters M, A and MA as appropriate. The key to the mark scheme is
(ii) If the answer is missing, but the correct answer is seen in the body of the script, full marks should be awarded. (iii) If the correct answer is seen in working but a completely different answer is seen in the answer space, then some marks will be awarded depending on the severity of the error. (iv) Work crossed out but not replaced should be marked. (v) In general, if two or more methods are offered, mark only the method that leads to the answer on the answer line. If two (or more) answers are offered (with no solution offered on the answer line), mark the poorest answer. (vi) For methods not provided for in the mark scheme, give as far as possible equivalent marks for equivalent work. (vii) Where a follow through mark is indicated on the mark scheme for a particular part question, the marker must ensure that you refer back to the answer of the previous part of the question. (viii)Unless the question asks for an answer to a specific degree of accuracy, always mark at the greatest number of significant figures seen. E.g. the answer in the mark scheme is 4.65 and the candidate then correctly rounds to 4.7 or 5 on the answer line. Allow full marks for 4.65 seen in the working. (ix) Anything in the mark scheme which is in brackets (...) is not required for the mark to be earned, but if
1052 4 x = 10.6 13 (a) 70 and 20 (b) Two bars drawn to correct heights (6.8 and 9.6) (c) 7.5 + 52.5 60 (d) x # 20 or 144 = 3.6, 3.6 # 20 = 72 60 40 x h = x # 20 = x 3 60 3
6
2 2 2 2 2 2 2 2

AVAILABLE MARKS

MA1 A1 MA1

A2 MA1

5

A1, A1 units

MA1 MA1 A1 MA1 A1 MA1 MA2 MA1 A1, A1 A1, A1 MA1 A1 MA1 A1 8 6 6

7280.01

[Turn over

4 -3 3 14 a 8 k = a 27 k = d3 27 n = a 3 k = 81 27 8 8 2 16 -2 2 -2 0.25 = a 1 k = 4 = 16 4 81 # 16 = 81 16
4 4

4

MA2 MA1 A1 A1 MA1 MA1 A1 MA1 MA1 MA1 MA1 MA1

AVAILABLE MARKS