See the book “Optics” by Hecht sections 3.2 and 3.3 Speed of light: EM waves travel in a vacuum with speed c = c = 299,792,458 ms-1 exactly They are transverse waves with (vector) E and B field orthogonal to each other, for this section bold indicates vector quanties. When far from the source (many wavelengths) the E and B fields are in phase The vector E x B points in the direction of motion Travelling waves can be written as E = E 0 ⋅ ei ( kx −ωt ) and B = B 0 ⋅ ei ( kx −ωt )
1
µ 0ε 0
Magnitude of B and E In a travelling wave, by using Maxwell’s equations, you can show that the magnitudes of E (E) and B (B) are related (for example Hecht page 42 section 3.2) c= E B
Recall the units: E in V/m and B in Tesla So the magnitude of the B field in the vacuum is tiny compared to the E field Polarisation of an EM wave is defined as the direction of the E field Transport of energy The energy density in the electric field in a vacuum is
1 U E = ε 0 E 2 Jm-3 2
[6.1]
For a magnetic field the energy density is
1 B2 Jm-3 UB = 2 µ0
[6.2]
For an EM field in a vacuum we have B = E/c => E UB = 2µ0 c
1
1
2
=
E2 2µ0c 2
Using c =
µ 0ε 0
implies U B =
ε0E 2
2
=UE
The E and B fields carry the same energy in an EM wave in vacuum. EM energy flow in a vacuum Consider the energy flow in an EM wave in a vacuum: Let the energy density be U Jm-3 Let the energy flow per second across a unit area be S Watts
E
S Watts 1 m2 B
Energy flow for 1m2 in 1 second S = cU Joules (c = speed of light)
2 1 2 1B S = c ε0E + Jm-2s-1 2 2 µ0
Using c =
1
µ 0ε 0
implies S =
EB
µ0
[6.3]
Note: E = |E| and B = |B| In vector terms
S = (E × B) / µ 0 J m-2 s-1 ≡ c 2ε 0 E × B Watts m-2 [6.4]
This means the energy flow is perpendicular to both the E and B fields
The vector S is known as Poynting’s vector
If we write the E and B fields as: E = E0 cos(kx − ωt ) and B = B0 cos(kx − ωt ) we find: S = c 2ε 0 (E × B ) cos 2 (kx − ωt )
Averaged over time the mean