ECT122 W4 ILab 2

Topics: Resistor, Series and parallel circuits, Electric current Pages: 4 (475 words) Published: January 21, 2015
ECT 122 Week 4 iLab #2

Parts:
Breadboard
DC Power Supply
Hand Held DMM
Test leads
Wire
220 Ω resistor
560 Ω resistor
1.0kΩ resistor

1. State Kirchhoff’s Current Law.
The algebraic sum of the currents entering a node is equal to zero.

2. What is the equation for the total current in a parallel circuit? It= I1+I2+I3….

3. Determine the total current in the following nodes.
1) It= 2mA+4mA+6mA= 0.012x10^-3=12mA
2) I + I1+I3= I2
I= 2mA+4mA= 1mA
I= 1mA- 6mA
I= -5mA

4. Determine the total current in the following circuit.

It= I1+I2+I3= 10mA+20mA+40mA= 0.07 x 10^-3= 70mA

5. If VS = 10 V in the circuit above, what are the following voltages?

R1= V/I= 10V/10mA= 1000 x 10^3= 1kΩ
R2= V/I= 10V/20mA= 500kΩ
R3= V/I= 10V/40mA= 250kΩ

Vr1= IR= 10mA x 1kΩ= 10V
Vr2= IR= 10mA x 500kΩ= 10,000 x 10^3= 10V Vr3= IR= 10mA x 250kΩ= 10,000 x 10^3= 10V

6. Download the Multisim file “Parallel2” from Doc Sharing, Week 4. Calculate the values below.

IT1=__49.2mA____IR1=__10mA____IR2=__17.9mA___IR3=___21.3mA____

V1=___10V______VR1=__10V_____VR2=___10V______VR3=__10V_______

Ir1= Vs/R1= 10V/1000Ω= 0.01 x 10^-3= 10mA
Ir2= Vs/R2= 10V/560Ω= 0.01785 x 10^-3= 17.9mA
Ir3= Vs/R3= 10V/470Ω= 0.021276 x 10^-3= 21.3mA
It= Ir1+Ir2+Ir3=10mA+17.9mA+ 21.3mA= 0.0492 x 10^-3= 49.2mA
V=IR V1= 10mA(1000Ω)= 10V
V2= 17.9mA(560Ω)= 10V
V3= 21.3mA(470Ω)= 10V

7. Using Multisim, simulate the circuit. Use the appropriate test equipment and measure the following values.

IT1=__0.049A____IR1=__10mA__IR2=_17.85mA__IR3=_21.275mA__

V1=__10V______VR1=_10V______VR2=__10V_____VR3=__10V____

8. Prototype the circuit below on the breadboard. Connect the circuit’s input to the variable +12 V supply. Turn on the DC power supply and use the handheld DMM to...
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