Dpip Lab Report
Abstract:
In this Lab we used the chemical DPIP to detect the rate of succinate broken down by the mitochondrial solution. We detected the amount of DPIP in the solution with a spectrophotometer and measuring the absorbance of light at the 600nm range. DPIP is a useful chemical to use in this experiment because it goes from a blue color when oxidized to a colorless liquid (Ogura, 281), this is due to the hydrogen ions and electrons released during the transitional step between succinate and fumarate. The three solutions used contained the same amount of mitochondrial suspension and DPIP but varied in the amount of buffer solution and succinate used. It was predicted that the sample with the highest level of succinate would perform experience the most change and the solution with no succinate would experience very little change. These were proven correct in the experiment with the .2 ml succinate treated tube dropping .496 absorbance rate at 600nm from .650 to …show more content…
This makes it a much better process by aerobic organisms then relying on fermentation for energy. This reaction however requires a few key components, a macromolecule to break down, mitochondria (or dual layer membrane of bacteria, proper environment, the ability to expel excess carbon dioxide, and adequate oxygen supply. In each of the tubes we were provided there was adequate amounts of all of these except macromolecules. In tube one no succinate was added. Given the logical choice it would be assumed that the DPIP would not be reduced in tube one because it lacks the products to produce the hydrogen ions and electrons to reduce it. However the world is not quite so black and white in this regard and it can become reduced by light waves thus it will add a slight error in our data (Lee,
In this Lab we used the chemical DPIP to detect the rate of succinate broken down by the mitochondrial solution. We detected the amount of DPIP in the solution with a spectrophotometer and measuring the absorbance of light at the 600nm range. DPIP is a useful chemical to use in this experiment because it goes from a blue color when oxidized to a colorless liquid (Ogura, 281), this is due to the hydrogen ions and electrons released during the transitional step between succinate and fumarate. The three solutions used contained the same amount of mitochondrial suspension and DPIP but varied in the amount of buffer solution and succinate used. It was predicted that the sample with the highest level of succinate would perform experience the most change and the solution with no succinate would experience very little change. These were proven correct in the experiment with the .2 ml succinate treated tube dropping .496 absorbance rate at 600nm from .650 to …show more content…
This makes it a much better process by aerobic organisms then relying on fermentation for energy. This reaction however requires a few key components, a macromolecule to break down, mitochondria (or dual layer membrane of bacteria, proper environment, the ability to expel excess carbon dioxide, and adequate oxygen supply. In each of the tubes we were provided there was adequate amounts of all of these except macromolecules. In tube one no succinate was added. Given the logical choice it would be assumed that the DPIP would not be reduced in tube one because it lacks the products to produce the hydrogen ions and electrons to reduce it. However the world is not quite so black and white in this regard and it can become reduced by light waves thus it will add a slight error in our data (Lee,