Determination of heat of neutralization

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Determination of heat of neutralization

By | September 2010
Page 1 of 8
PRACTICAL 15:DETERMINATION OF HEAT OF NEUTRALIZATION

Data collection:

|Reaction |Initial Temperature/°C (±0.25) |Final Temperature of Mixture/°C (±0.25) | | |Acid |Base | | |HNO3 + NaOH |28.00 |28.25 |34.50 | |HNO3 + KOH |28.25 |28.25 |34.00 | |HCl + NaOH |28.25 |28.00 |34.75 | |HCl + KOH |28.25 |28.25 |34.00 | |H2SO4 + NaOH |28.00 |28.50 |36.50 | |H2SO4 + KOH |28.50 |28.00 |34.00 |

Volume of acid = 50 cm3 ± 0.25
Acid concentration = 1.0 M
Volume of base = 50cm3 ± 0.25
Base concentration = 1.0 M
Number of mole of solution used = [pic]
= [pic]
= 0.05 mole ± 0.5 %

Data Processing:

Calculation:

Temperature Change, [pic] = Final temperature – Average temperature of Acid and Base

|Reaction |Average Temperature of Acid and Base, °C|Final Temperature, °C |Change of Temperature, °C | | |(±0.5) |(±0.25) |(±0.75) | |HNO3 + NaOH |28.13 |34.50 |6.38 | |HNO3 + KOH |28.25 |34.00 |5.75 | |HCl + NaOH |28.13 |34.75 |6.63 | |HCl + KOH |28.25...