Abstract:
In this experiment, two object collided both elastically and in inelastically, the purpose of this experiment is to study the principle of conservation of momentum in collisions using two bodies. We also calculated the amount of kinetic energy in elastic and inelastic collisions before and after the collision. Introduction:

When bodies collide with each other, the total momentum p = mv, is always conserved regardless of the type of collision provided no external forces are present. There are two types of collisions. In an elastic collision, both the kinetic energy and the momentum are conserved. An inelastic collision is one in which only the momentum is conserved. Most collisions observed in nature are inelastic. A collision is completely inelastic when the bodies stick together after a collision. Materials and Methods:

For this experiment we used an air table that provided a frictionless motion of the pucks, Velcro tape for the inelastic collision, graph paper and a ruler. At first, we lunched the pucks without the Velcro tape to collide them elastically, and they drew on the graph paper their path before and after the collision. The same thing happened in the second part of the experiment, but this time with the Velcro tape. Result:

The elastic collision:
VAVB
Before2 X 10-2 m/s2.5 X 10-2 m/s
After1.44 X 10-2 m/s1.26 X 10-2 m/s

The inelastic collision:
VAVB
Before1.7 X 10-2 m/s1.74 X 10-2 m/s
After1.26 X 10-2 m/s

The calculation of the kinetic energy:
For the elastic collusion:
The kinetic energy should be conserved before and after the collusion. Kbefore = ½ VA2 + ½ VA’2 = 0.2425 mJ
Kafter = ½ VB2 + ½ VB’2 = 0.1583 mJ
For the inelastic:
Kbefore = ½ VA2 + ½ VA’2 = 0.1849 mJ
Kafter = ½ VB2 + ½ VB’2 = 0.099225 mJ

Discussion:

In this experiment the main goal was to verify the conservation of linear momentum during the collisions in an isolated system, and to investigate the conservation of kinetic energy during...

...Laboratory V: Conservation of Momentum
Problem #1: Perfectly Inelastic Collisions
John Greavu
April 17, 2013
Physics 1301W, Professor: Evan Frodermann, TA: Mark Pepin
Abstract
A cart was given an initial velocity toward another stationary cart down a track. The initial velocity of the first cart as well as the masses of both carts was varied throughout multiple trials. Velcro placed on the ends of the carts caused the cars to stick together after colliding. Videos of the collision and the seconds just before and after were taken. Data was then uploaded and plotted in MotionLab were it was used to create construct velocity vs. time graphs for each trial. After analyzing the data and the subsequent graphs the final velocity equation for two objects (each of known mass) that have collided directly head-on in a perfectly inelastic collision was determined as a function of the initial velocities and masses of the two objects.
Introduction
“You work for NASA with a group designing a docking mechanism that would allow two space shuttles to connect with each other. The mechanism is designed for one shuttle to move carefully into position and dock with a stationary shuttle. Since the shuttles may be carrying different payloads and different amounts of fuel, their masses may not be identical: the shuttles could be equally massive, the moving shuttle could be more massive, or the stationary shuttle could have a...

...Solving Momentum Problems
Momentum:
For lack of a better definition, momentum is a measure of the “oomph” that an object has due to its
motion. The more mass an object has and the more speed it has the more momentum it has. The
formula for momentum is simply:
p=mv
Where p is momentum, m is mass, and v is velocity
Note that momentum is a vector quantity, so it is possible to have negative momentum. Any object that
is moving in the direction opposite that defined as positive will have a negative momentum. You can
also break a momentum vector into components or resolve momentum vectors into a single resultant.
Momentum is a conserved quantity. The momentum of a system will not change unless an outside
impulse is applied to it. If the system remains isolated, its total momentum will not change. That does
not mean that individual parts of a system cannot interact with each other and exchange momentums.
Conservation of Momentum is a basic physics principle that allows us to solve many interesting
problems.
The unit of momentum is a kg•m/s
Impulse:
The only way to change momentum is through impulse. Impulse is an outside force applied for a
specific time. Obviously the harder you push and the longer...

...Physics G
Unit 6 – Momentum
Internet Lab – Momentum and Collisions
Name:
Date:
Period:
Website: http://phet.colorado.edu/
Play with the Sims Physics Motion Collision Lab
Introduction:
When objects move, they have momentum. Momentum, p, is the product of an object’s mass (kg) and its velocity (m/s). The unit for momentum, p, is kg·m/s. During a collision objects transfer momentum to each other, resulting in different motions than before the collision. In this activity you will study the motion colliding objects.
ELASTIC Collisions
1. What defines a collision as being elastic?
2. Simulate the four elastic collisions below. Complete the table using math formulas and the simulation.
BEFORE COLLISION
ptotal
AFTER COLLISION
#
m1
m2
v1
v2
v1
v2
1
2.0 kg
2.0 kg
1.5 m/s
0 kg·m/s
2
2.5 kg
5.0 kg
-1.0 m/s
0 kg·m/s
3
3.0 kg
6.0 kg
2.0 m/s
0.0 m/s
4
6.0 kg
2.0 m/s
-1.0 m/s
8.0 kg·m/s
3. Two objects with the same mass move toward each other with the same speed and experience an elastic collision. Compare the final velocities of each object to their initial velocities.
4. A less-massive moving object has an elastic collision with a more-massive object that is not moving. Compare the initial velocity...

...while the man is trying unsuccessfully to lift the crate?
Ans) P+C=W unit of force is Newton(N)
Test 3:
Question no.5)Jacques and George meet in the middle of a lake while paddling in their canoes. They come to a complete stop and talk for a while. When they are ready to leave, Jacques pushes George's canoe with a force F to separate the two canoes. What is correct to say about the final momentum and kinetic energy of the system if we can neglect any resistance due to the water?
The final momentum is in the direction opposite to F but the final kinetic energy is zero.
Question no. 10) A person pushes horizontally on a heavy box and slides it across the level floor at constant velocity. The person pushes with a 60.0 N force for the first 6.88M at which time he begins to tire. The force he exerts then starts to decrease linearly from 60.0 N to 0.00 N across the remaining 6.88M How much total work did the person do on the box?
619J(Joules)
Question no 12) In the figure, determine the character of the collision. The masses of the blocks, and the velocities before and after are given. The collision is
Ans) Perfectly Elastic
Question no 17)On a frictionless horizontal table, two blocks (A of mass 2.00 kg and B of mass 3.00 kg) are pressed together against an ideal massless spring that stores 75.0 J of elastic potential energy. The blocks are not attached to the spring and are free to move free of it once they are...

...Experiment 4
Inelastic Collisions, Conservation of Momentum and Non
Conservation of Kinetic Energy
Preparation
Prepare for this week's experiment by studying Newton's Laws, linear momentum, and kinetic
energy.
Principles
In this experiment you will study a collision where a moving object strikes and sticks to an
initially motionless object. When the colliding objects stick together thecollision is said to be
completely inelastic. The net momentum of the system should not change, but the net kinetic
energy of the system will decrease. The amount of kinetic energy left after the collision can be
predicted using conservation of momentum.
Linear momentum is defined as
p = mv .
It is a vector quantity; the momentum is always in the same direction as the linear velocity. As
long as the mass is constant, the time derivative of momentum is
dp
dv
=m .
dt
dt
Since the time derivative of the velocity is the acceleration, we see that
dp
dv
=m
= ma = ∑ F .
dt
dt
Force changes momentum. If no net force is applied to an object its momentum remains
constant.
Consider a collision between object 1 and object 2. If there is no other force on object 1 other
than the force from object 2, or if the other forces on object 1...

...Lab 5
Conservation of Momentum and Energy
Abstract
The physics laws governing conservation of momentum and mechanical energy were investigated by performing multiple experiments with differing conditions. Conservation laws state energy is to be conserved in systems with no net external forces. Two trials consisted of inelastic collisions and two trials consisted of elastic conditions. Photogate software helped decipher initial and final velocities in order to perform calculations applied to conservation law equations. In both cases of conservation of momentum and kinetic energy, low relative changes in total energy (less than 0.003) were observed indicating general conservation of energy. Percent discrepancies comparing the theoretical to experimental values allowed for more insight on what was truly going on. Conservation of momentum was seen in Trial 1 (5.56%), Trial (1.69%) and Trial 4 (6.89%) all showing low percent discrepancies from the theoretical outcome. Trial 2, having a percent discrepancy of 52.0%, showed error in the experiment possibly due to friction, the photogate software, or other inconclusive factors. Conservation of mechanical energy was demonstrated in cases of elastic collision since low percent discrepancies of...

...1) Introduction
This Lab is about conservation of momentum. It is to investigate the difference of momentum before and after collisions. Using the photo gates record the velocity of each cart, comparing momentum and kinetic energy to find the law. The experimental apparatus are two red carts in approximately same weight and a gold cart in lower weight than the red ones, a stable air track (blow a constant stream of air out through numerous tiny holes) with low friction and two photo gates.
2) Project description
2.1) Theory
We should have the concept of momentum to disassociate velocity and momentum. The linear momentum of an object is the product of the object’s mass and velocity. Linear momentum is a vector quantity that in the same direction as the velocity. P = m * v (kg. m/s) During a collision, it is usually straightforward to measure the mass and velocity of an object, so that its momentum just after the collision and just before the collision can be found. The collisions include elastic collision (one in which the total kinetic energy of the system after the collision is equal to the total kinetic energy before the collision, ideally with no loss of energy due to sound, heat, light, or deformation) and inelastic...

...What is momentum?
Momentum of a body is defined as the mass multiplied by the velocity of this object.
Momentum= m x v
Momentum and Newton’s second law of motion:
The resultant force is proportional to the change in momentum per a second.
We know that force = mass x acceleration. So F (mv-mu)/t
F m (v-u)/t = ma so F=kma
Momentum is a vector quantity:
Momentum has a direction as well as a magnitude
Momentum and Newton’s first law of motion:
An object remains at rest or in uniform motion unless acted upon by a force.
If an object had a constant momentum, it will have a constant amount of force needed to that will mean that no resultant force acting on it. So it will have a constant velocity unless the mass changes.
Momentum key points
Unit of momentum:
Kgms-1
Symbol of momentum:
P
But what is momentum as a physical quantity?
Momentum is the measure of how much force is needed to stop the moving object or change its velocity (speed or direction)
Momentum is found in lots of examples from our everyday lives. To understand what momentum is we look at two colliding objects. Each object is moving with a certain velocity and has a certain mass. To stop this object a certain force must be applied to counter the...

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