The Cold Equations This short story by Tom Godwin is a very sentimental and lesson learning story. Briefly, it is about a ship on a designated mission which encounters a problem because the pilot on the ship encounters a stowaway, a young girl, and every stowaway found on board must be jettisoned, it was the law and there was absolutely no appeal. Marilyn, the stowaway’s name, was simply a teen and all she wanted was to see her brother whom she hadn’t seen in over 10 years she really meant no harm but she chose to ignore the warning sign in front of the ship. The EDS ships were only equipped with a certain amount of fuel that would reach them only to their designated destination, h amount of fuel would not power an EDS with mass of m plus x safely to it’s destination. Although it was very saddening that the pilot had to kill Marilyn, there was nothing else that could be done. If he would have let her stay on board he would die along with the other 6 men waiting on the EDS for the cure to their survival. In my opinion, his decision was justified, it was the law and he had done all he could do to help the poor girl but it wasn’t merely enough. The first reason to believe that the pilot’s decision was justified was because it was very logical and ethical. He had not other choice it was the law to kill a stowaway on board, no matter if it was a beautiful girl, beauty had no partake in this scenario it wasn’t like Earth. The pilot really did care about Marilyn’s life and he really did not want to kill her but, if it wouldn’t have been done the lives of many others would also have been gone. Although he did not want, he would have had no other choice. Either way there really was no win because if he would have let Marilyn stay on board and not jettisoned her, in the long run she would still have died along with the pilot and the other men counting on the EDS with the fever serum it was carrying. The second reason to believe the pilot’s...

...portrayal of the setting and atmosphere in The ColdEquations, the reader undoubtedly experiences the lonesome and cold feeling occurring in the story. The authors brilliant use of figurative language and imagery illustrating Bartons occupation produces a character deficient of personality and feeling. This genius utilization of words forces the reader to experience a sense of urgency amidst the bitter conditions within the story. TheColdEquations is a fictional tale consumed with chilling imagery expertly depicted by the author, vividly generating a cold atmosphere lacking personality and emotion.
Goodwins effective delineation of the frontier, the setting of which the story takes place, initiates the lonesome and cold aspect experienced in the tragic tale. The ColdEquations occurs in a futuristic time period, resulting in a scientific feel and a lack of understanding by the reader. The Stardust had gone through the usual procedure, dropping into normal space to launch the EDS with the fever serum, then vanishing again in hyperspace. (Goodwin 3). The vast expanse of space cannot be comprehended by the human mind, resulting in the lonesome feeling previously stated. During the commencement of the story, much of the diction contains technical and scientific language. Science is free from emotion and personality, forming the cold...

...Be
The short story ColdEquations by Tom Godwin takes place on a ship called EDS. The space cruiser is piloted by a man named Barton. He has an order of killing the stowaway who snuck onto the ship because the weight on the EDS is too much for the ship to handle. In the process of hunting down the stowaway, he realizes it was a young innocent girl named Marilyn. Once Barton understands what kind of person Marilyn is, he doesn’t kill her immediately because he knows her reasons were pure. Marilyn only wanted to see her brother, Gerry, again after ten years of being apart and was ignorant to the fact that her life can end with the decision of sneaking onto the ship. Barton begins to feel compassion after being with her and tries to comfort her, but knows what her fate is. He lets Marilyn live long enough to let her speak with Gerry once more before he follows through with the command. After Gerry and Marilyn speak he ejects her out into space. The ending was logical and no other endings would be possible because one the equation that was calibrated delicately, and two Barton could not throw the out the fever serums because that is the main reason for going on the trip to Woden.
A theoretical ending of ColdEquations could have been that Barton sacrifices himself for Marilyn, but since she is lighter than him, the fragile calibrated equation would be disrupted due to the change in weight....

...
My Mathematical Equations
By Kathleen Rossi
MAT 222 Intermediate Algebra
Instructor: Mohamed Elseifieen
May 12, 2013
My Mathematical Equations
This paper will show two mathematical problems, the first is “To estimate the size of the bear population on the Keweenaw Peninsula, conservationists captured, tagged, and released 50 bears. One year later, a random sample of 100 bears included only 2 tagged bears. What is the conservationist's estimate of the size of the bear population?” (Dugopolski, 2013, pp. 437, probem 56). The second will be to complete problem 10 on page 444 of Elementary and Intermediate Algebra. Here all steps in solving the problem will be explained step by step.
The first problem is to estimate the size of the bear population located on the Keweenaw Peninsula conservation. In reading over the “Bear Population” method #56 on page 437you will notice we are to assume that the ratio of originally tagged bears to the whole population is equal to the ratio of recaptured bears to the size of the sample.
The ratio of the originally tagged bears to the whole population is 2100
The ration of the recaptured tagged bears to the sample size is 50x
2100=50x Since x is on the right-hand side of the equation, we need to switch the sides so it is on the left-hand side.
50x=2100 This is the proportion set up and ready to solve. I will cross multiply setting the extremes equal to the means.
100(50) = 2x Here 100...

...How Cold Affects The Body
B Y: G E N E S I S P O N C E
How Cold Affects The Body
The body tries to maintain body temperature by
vasoconstriction and shivering.
Shivering is the body’s main involuntary defense against the cold
producing body heat by forcing muscles to contract and relax
rapidly.
Vasoconstriction is the tightening of blood vessels
Vasoconstriction occurs in the uncovered skin when it is exposed
to cold temperatures.
The reduced blood flow in the skin conserves body heat but can
lead to discomfort, numbness, loss of dexterity in the hands and
fingers.
How The Body Produces Heat
Normal body temperature is maintained by a
balance of heat production and heat loss
Heat is produced by food metabolism and
muscle activity.
Shivering increases heat production up to 500%
lack of food limits the body’s ability to
produce heat.
Heat Loss From The Body
Body heat can be lost by four mechanisms.
1. Convection is the loss of heat from the body by air
blowing over the skin or through clothing.
2. Conduction, or direct contact with a colder object.
For example, lying in snow but with the exception of
being immersed in cold water; Heat is then lost 25
to 30 times faster.
3. Evaporation, or conversion of liquid on the skin to
vapor. This accounts to 20% of heat loss through
sweating and respiration.
4. Radiation is the primary method of heat loss,
accounting for about 65% of the...

...Quadratic Equation:
Quadratic equations have many applications in the arts and sciences, business, economics, medicine and engineering. Quadratic Equation is a second-order polynomial equation in a single variable x.
A general quadratic equation is:
ax2 + bx + c = 0,
Where,
x is an unknown variable
a, b, and c are constants (Not equal to zero)
Special Forms:
* x² = n if n < 0, then x has no real value
* x² = n if n > 0, then x = ± n
* ax² + bx = 0 x = 0, x = -b/a
WAYS TO SOLVE QUADRATIC EQUATION
The ways through which quadratic equation can be solved are:
* Factorizing
* Completing the square
* Derivation of the quadratic formula
* Graphing for real roots
Quadratic Formula:
Completing the square can be used to derive a general formula for solving quadratic equations, the quadratic formula. The quadratic formula is in these two forms separately:
Steps to derive the quadratic formula:
All Quadratic Equations have the general form, aX² + bX + c = 0
The steps to derive quadratic formula are as follows:
Quadratic equations and functions are very important in business mathematics. Questions related to quadratic equations and functions cover a wide range of business concepts that includes COST-REVENUE, BREAKEVEN ANALYSIS, SUPPLY/DEMAND & MARKET EQUILIBRIUM....

...Quadratic equation
In elementary algebra, a quadratic equation (from the Latin quadratus for "square") is any equation having the form
where x represents an unknown, and a, b, and c represent known numbers such that a is not equal to 0. If a = 0, then the equation is linear, not quadratic. The numbers a, b, and c are the coefficients of the equation, and may be distinguished by calling them, the quadratic coefficient, the linear coefficient and the constant or free term.
Solving the quadratic equation
A quadratic equation with real or complex coefficients has two solutions, called roots. These two solutions may or may not be distinct, and they may or may not be real.
Factoring by inspection
It may be possible to express a quadratic equation ax2 + bx + c = 0 as a product (px + q)(rx + s) = 0. In some cases, it is possible, by simple inspection, to determine values of p, q, r, and s that make the two forms equivalent to one another. If the quadratic equation is written in the second form, then the "Zero Factor Property" states that the quadratic equation is satisfied if px + q = 0 or rx + s = 0. Solving these two linear equations provides the roots of the quadratic.
Completing the square
The process of completing the square makes use of the algebraic identity...

...Summer 2010-3 CLASS NOTES CHAPTER 1
Section 1.1: Linear Equations
Learning Objectives:
1. Solve a linear equation
2. Solve equations that lead to linear equations
3. Solve applied problems involving linear equations
Examples:
1. [pic]
[pic]
3. A total of $51,000 is to be invested, some in bonds and some in certificates of deposit (CDs). If the amount invested in bonds is to exceed that in CDs by $3,000, how much will be invested in each type of investment?
4. Shannon, who is paid time-and-a-half for hours worked in excess of 40 hours, had gross weekly wages of $608 for 56 hours worked. What is her regular hourly wage?
Answers: 1. [pic]
2. [pic]
3. $24,000 in CDs, $27,000 in bonds 4. $9.50/hour
Section 1.2: Quadratic Equations
Learning Objectives:
1. Solve a quadratic equation by (a) factoring, (b) completing the square, (c) the
quadratic formula
2. Solve applied problems involving quadratic equations
Examples:
1. Find the real solutions by factoring: [pic]
2. Find the real solutions by using the square root method: [pic]
3. Find the real solutions by completing the square: [pic]
4. Find the real solutions by using the quadratic formula: [pic]
5. A ball is thrown vertically upward from the top of a...

...There are now two separate equations: 60 = 6b - 6c and 60 = 3b + 3c
Solve both equations for b: b = 10 + c b = 10 - c
Now make both equations equal each other and solve for c: 10 + c = 10 - c 2c = 0 c = 0
The speed of the current was 0 mph Now, plug the numbers into one of either the original equations to find the speed of the boat in still water.
I chose the first equation: b = 10 + c or b = 10 + 0 b = 10
The speed of the boat in still water must remain a consistent 10 mph or more in order for Wayne and his daughter to make it home in time or dinner.
My Solution: c = current of river b = rate of boat d = s(t) will represent (distance = speed X time) Upstream: 60 = 6(b-c)
Downstream: 60 = 3(b+c)
There are now two separate equations: 60 = 6b - 6c and 60 = 3b + 3c
Solve both equations for b: b = 10 + c b = 10 - c
Now make both equations equal each other and solve for c: 10 + c = 10 - c 2c = 0 c = 0
The speed of the current was 0 mph Now, plug the numbers into one of either the original equations to find the speed of the boat in still water.
I chose the first equation: b = 10 + c or b = 10 + 0 b = 10
The speed of the boat in still water must remain a consistent 10 mph or more in order for Wayne and his daughter to make it home in time or dinner.
My Solution: c = current of river b = rate of boat d = s(t) will...