# Case 5-1 Let There Be Light Lamp

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• Published : February 29, 2012

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Givens:
12 inch = 1 feet.
Style (A) dimensions = 12 x12 x 12.
Package cost 60 cent.
Package weight 1 pound.
Style (A) Shade cost \$ 4.
Style (A) Shade weight 10 pounds.
Total Package + Shade (A) cost = \$ 4 + 60 cents = \$ 4.6.
Total Package + Shade (A) weight = 1 + 10 = 11 pounds.
Total Package + Shade (A) volume = 1728 inch3 = 1 foot3

Container dimensions:
8 x 8.5 x 40 = 2720 ft3
Maximum container weight = 44000
Container price = \$ 1000

Package style (B) Shade dimensions = 12 x12 x 48.
Package style (B) Shade cost = \$ 2.
Style (B) Shade cost = \$ 5.
No. of Shades (B) ÷ Package = 6
Package total cost = 6 x 5 + 2 = \$ 32
Package total weight = 62 pounds
Package total volume = 6912 inch3 = 4 ft3

Package style (C) Shade dimensions = 12 x12 x 50.
Package style (C) Shade cost = \$ 3
Style (C) Shade cost = \$ 6
No. of Shades (C) ÷ Package = 10
Package total cost = 10 x 6 + 3 = \$ 63
Package total weight = 101 pounds
Package total volume = 7200 inch3 = 4.17 ft3

Question1:
How many style A shades can be loaded into an intermodal container? The volume of the container ÷ the volume of one package = 2720 ÷ 1 = 2720 package Style (A) Shade. Package contains 1 shade = 2720 Style (A) Shade.

Total weight = 2720 x 11 p = 29920 < 44000 (total weight of container).

Question 2:
How many style B shades can be loaded into an intermodal container? The volume of the container ÷ the volume of one package = 2720 ÷ 4 = 680 package Style (B) Shade. Package contains 6 = total shades 680 x 6 = 4080 Style (B) Shade. Total weight = 680 x 62 p = 42160 < 44000 (total weight of container).

Question 3:
How many style C shades can be loaded into an intermodal container? The volume of the container ÷ the volume of one package = 2720 ÷ 4.17 = 652. 27 approximately 652 package Style (B) Shade. Total weight = 652 x 101 p = 65852 > 44000 (total weight of container). Maximum no. can fit in the container = 44000 ÷ 101 = 435.6 = 435...