Preview

Exercise Questions: Applied Statistics in Business and Economics by Doane and Seward

Good Essays
Open Document
Open Document
1591 Words
Grammar
Grammar
Plagiarism
Plagiarism
Writing
Writing
Score
Score
Exercise Questions: Applied Statistics in Business and Economics by Doane and Seward
Prepare answers to the following assignments from the e-text, _Applied Statistics in Business and Economics_, by Doane and Seward:

Chapter 12

CHAPTER REVIEW #1

Chapter Exercises 12.48 and 12.50

Chapter 13

Chapter Exercises 13.30 and 13.32

Chapter 14

Chapter Exercise 14.16

CHAPTER 12

CHAPTER REVIEW #1

LIST TWO LIMITATIONS OF BIVARIATE REGRESSION.

Often simplistic (multiple relationships usually exist.

Biased estimates, even if relevant predictors are omitted.

WHY IS ESTIMATING A MULTIPLE REGRESSION MODEL JUST AS EASY AS BIVARIATE REGRESSION?

Because a computer does all the calculations so there is no extra computational burden.

CHAPTER EXERCISES:

12.48

IN THE FOLLOWING REGRESSION, _X_ = WEEKLY PAY, _Y_ = INCOME TAX WITHHELD, AND _N_ = 35 MCDONALD'S EMPLOYEES. (A) WRITE THE FITTED REGRESSION EQUATION. (B) STATE THE DEGREES OF FREEDOM FOR A TWO-TAILED TEST FOR ZERO SLOPE, AND USE APPENDIX D TO FIND THE CRITICAL VALUE AT _Α_ = .05. (C) WHAT IS YOUR CONCLUSION ABOUT THE SLOPE? (D) INTERPRET THE 95 PERCENT CONFIDENCE LIMITS FOR THE SLOPE. (E) VERIFY THAT _F_ = _T_2 FOR THE SLOPE. (F) IN YOUR OWN WORDS, DESCRIBE THE FIT OF THIS REGRESSION.

R2 0.202

STD. ERROR 6.816

N 35

ANOVA TABLE

_SOURCE SS DF MS F P-VALUE_

REGRESSION 387.6959 1 387.6959 8.35 .0068

RESIDUAL 1,533.0614 33 46.4564

TOTAL 1,920.7573 34

REGRESSION OUTPUT _CONFIDENCE INTERVAL_

_VARIABLES COEFFICIENTS STD. ERROR T (DF_ = _33) P-VALUE 95% LOWER 95% UPPER_

INTERCEPT 30.7963 6.4078 4.806 .0000 17.7595 43.8331

SLOPE 0.0343 0.0119 2.889 .0068 0.0101 0.0584

(A) WRITE THE FITTED REGRESSION EQUATION.

y = 0.0343x + 30.7963

(B) STATE THE DEGREES OF FREEDOM FOR A TWO-TAILED TEST FOR ZERO SLOPE, AND USE APPENDIX D TO FIND THE CRITICAL VALUE AT _Α_ = .05.

Dof = 35 - 1 = 34, critical value of t corresponding to 34 dof at ( = 0.05 (two-tailed) is 2.032.

(C) WHAT IS YOUR CONCLUSION ABOUT THE SLOPE?

Since the t- value for the slope (2.889) is greater than the critical value (2.032), the null

You May Also Find These Documents Helpful

Related Topics