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6.03 Titration Lab

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6.03 Titration Lab
Vinegar Titration Lab
Procedure:
1.) Obtain ~100 mL of NaOH. Record the molarity on the data table.
2.) Set up a ring stand with a buret.
3.) Place 5mL of vinegar in a 125 mL Erlenmeyer flask. Dilute the vinegar with 25 mL of water and add two drops of phenolphthalein.
4.) Fill the buret with NaOH. Record the initial volume of the buret in your data table.
5.) Titrate the vinegar sample until the first faint pink color does not disappear.
6.) Record the final volume of the buret in your data table.
7.) Repeat steps 3 through 6 until you have three trials that agree within five percent.
Equipment:
Ring stand, goggles, buret, 125mL Erlenmeyer flask, 150mL beaker, excess vinegar and NaOH.
Data Table:

Trial 1
Trial 2
Trial 3
Trial 4
Trial 5
Trial 6
Trial 7
Vinitial
2.6
3.9
4.9
2.85
0
2.9
1.1
Vfinal
21.3
21.3
23.3
21.89
19.3
21.4
20.0
ΔV
18.7
17.4
18.4
19.04
19.3
18.5
18.9
(data chosen from best trials out of 13)
Average of the trials: = 18.6057
Percent agreement from the average of each trial:
Trial 1
Trial 2
Trial 3
Trial 4
…show more content…
The pH indicator, phenolphthalein, turned a light shade of pink when it was in a solution with a pH of 7. Neutralization reactions occur when an acid is mixed with a base. The product of this reaction is a salt and water. These reactions are double displacement reactions, because the cation of the base mixes with the anion from the acid, forming a base, and the hydrogen from the acid mixes with the anion from the base, forming water. In this reaction, the sodium ion from the sodium hydroxide attracts to the acetate ion from the acetic acid, and the extra hydride ion bonds with the negative hydroxide ion to form water. The water produced by the reaction had a pH of seven, and so when the whole solution was light pink, we knew the reaction had fully

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