# Sahil

Good Essays
5638 Words
Grammar
Plagiarism
Writing
Score
Sahil
Question 1.1: What is the force between two small charged spheres having charges of 2 × 10−7 C and 3 × 10−7 C placed 30 cm apart in air? Answer

Repulsive force of magnitude 6 × 10−3 N Charge on the first sphere, q1 = 2 × 10−7 C Charge on the second sphere, q2 = 3 × 10−7 C econd Distance between the spheres, r = 30 cm = 0.3 m Electrostatic force between the spheres is given by the relation,

Where, ∈0 = Permittivity of free space

Hence, force between the two small charged spheres is 6 × 10−3 N. The charges are of same nature. Hence, force between them will be repulsive.

Question 1.2: The electrostatic force on a small sphere of charge 0.4 μC due to another small sphere of between charge − 0.8 μC in air is 0.2 N. (a) What is the distance between the two spheres? (b) What is the force on the second sphere due to the first? Answer

Electrostatic force on the first sphere, F = 0.2 N Charge on this sphere, q1 = 0.4 μC = 0.4 × 10−6 C Charge on the second sphere, q2 = − 0.8 μC = − 0.8 × 10−6 C Electrostatic force between the spheres is given by the relation,

Where, ∈0 = Permittivity of free space

The distance between the two spheres is 0.12 m. Both the spheres attract each other with the same force. Therefore, the force on the second sphere due to the first is 0.2 N.

Question 1.3: Check that the ratio ke2/G memp is dimensionless. Look up a Table of Physical Constants and determine the value of this ratio. What does the ratio signify? Answer

The given ratio is Where, G = Gravitational constant Its unit is N m2 kg−2.

.

me and mp = Masses of electron and proton. Their unit is kg. e = Electric charge. Its unit is C.

Its unit is N m2 C−2.

∈0 = Permittivity of free space

Hence, the given ratio is dimensionless. e = 1.6 × 10−19 C G = 6.67 × 10−11 N m2 kg-2 me= 9.1 × 10−31 kg mp = 1.66 × 10−27 kg Hence, the numerical value of the given ratio is

This is the ratio of electric force to the gravitational force between a proton and an electron, keeping distance between

## You May Also Find These Documents Helpful

• Satisfactory Essays

Part III PHYSICS HSE II Time:2Hours Max:60 Scores 1. Three identical charges each +q are placed at the corners of an equilateral triangle of side d cm. Calculate the force on a +ive charge +2q at the centroid of the triangle. 2 2.If the earth is supposed to be a metallic sphere,its capacity will be nearly (a) 700pf (b) 700 microfarad (c) 700f (d) 6.4 X10^6 f 1score 3. write the relation between dielectric constant and electric susceptibility. 1score 4. A box encloses an electric dipole consisting of charge 5micro C and -5micro C and of length 10cm. What is the total electric flux through the box? 2scores 5. Find the ratio of the p.d that must be applied across the (1)parallel (2) series combination of two identical capacitors so that the energy stored in the two cases becomes the same. 2 scores 6.(a)…

• 775 Words
• 4 Pages
Satisfactory Essays
• Good Essays

Q 10. Three charges, each equal to +2C are placed at the corners of an equilateral triangle. If the force between any two charges be F, then what will be the net force on either Charge? 11. A point charge q is placed at O as…

• 5747 Words
• 23 Pages
Good Essays
• Good Essays

The energy of attraction between two oppositely charged ions is directly proportional to the charges on the ions and inversely proportional to the distance of separation.…

• 823 Words
• 4 Pages
Good Essays
• Satisfactory Essays

Calculate the kinetic energy gained. Answer in units of J. 002 (part 2 of 2) 10.0 points Through how large a potential diﬀerence did the object fall? Answer in units of V. 003 (part 1 of 2) 10.0 points Consider three charges arranged as shown. 7 µC 1.8 µC + + 4 cm −1 µC − 2.4 cm What is the magnitude of the electric ﬁeld strength at a point 1.7 cm to the left of the middle charge? The value of the Coulomb constant is 8.98755 × 109 N · m2 /C2 .…

• 984 Words
• 4 Pages
Satisfactory Essays
• Powerful Essays

To explore the concepts of static electricity and to discover how many types of electrical charges exist and how they interact with each other…

• 740 Words
• 3 Pages
Powerful Essays
• Good Essays

Hypothesis: I fully believe that the charge of the pith ball will be positive. The formula I will use to prove this is Coulomb’s Law, (Fe=(k*q1*q2) / r²). ‘Fe’ is equal to the electrostatic force between the spheres, measured in Newton’s. It is also a vector quantity, and it’s in absolute value. Secondly, ‘k’ is equal to Coulomb’s law constant. The constant is equal to 8.99 * 10^9 N*m²/C². Thirdly, ‘q1’ is equal to the charge in Coulomb’s (C) of the first object. As well, ‘q2’ is equal to the charge of the second object in Coulomb’s (C). Finally, ‘r²’ is equal to the radius between the two centres of the objects measured in metres, squared. The manipulated variable in this lab is the radius at which we place the metal sphere away from the pith ball. The responding variable is the electrostatic force of the pith ball as a result of the radius from the metal sphere. The controlled variable is the charge of the metal sphere, which is -3.59e-7C.…

• 791 Words
• 4 Pages
Good Essays
• Good Essays

The sources of error could have been in measuring the angle o⁲敬杮桴漠⁦桴⁥瑳楲杮‮桔⁥瑳楲杮洠杩瑨栠癡⁥敢湥愠氠瑩汴⁥桳牯整r length of the string. The string might have been a little shorter or longer than measured. The angle could have varied based on the electrostatic they already had between them at the moment. The angle could have been slight smaller or larger than the measurement taken by the protractor.…

• 677 Words
• 3 Pages
Good Essays
• Satisfactory Essays

For all of these problems we want to make use of the standard electric force equation: ̂ So for this problem with K=9*109 Nm2/C2, Q1=-3.5μC, Q2=5.1 μC, and r=9.3 cm we get F=-18.57 N. It’s important to realize that getting a negative force value means the charges attract. The direction of that attraction is determined by which charge we’re looking at.…

• 1344 Words
• 6 Pages
Satisfactory Essays
• Satisfactory Essays

NEGATIVE CHARGE Think If a piece of gold is rubbed with a piece of wool, which object loses electrons Explain using the electrostatic series. The wool is at the top of the electrostatic series so will lose electrons and have a positive charge. The gold is lower on the electrostatic series so gold will gain electrons and have a negative charge. If a piece of gold is rubbed with a piece of wool, the wool loses electrons. The gold gains electrons. Wool is an electron giver and gold is an electron taker. Name one substance that will get a negative charge when rubbed on ebonite. Copper, rubber or gold Name one substance that will get a positive charge when rubbed on ebonite. acetate, glass, wool or human hair One piece of glass is rubbed with silk. A second piece of glass is rubbed with a rubber balloon. What will be the charge on both pieces of glass The glass will have a positive charge when rubbed with either silk or rubber. Which piece of glass will have a stronger charge and explain why. The glass rubbed with rubber will have a stronger positive charge because rubber and glass are further apart on the…

• 487 Words
• 2 Pages
Satisfactory Essays
• Good Essays

Purpose The purpose of this experiment is to test Coulomb's Law which states that the force between two spherically symmetric charged objects is directly proportional to the product of the charges, and inversely proportional to the square of the distance between the centers of the two charges. In mathematical vector notation Coulomb’s Law is expressed as…

• 1608 Words
• 7 Pages
Good Essays
• Good Essays

The effects of electric force can be summarized as the law of electric charge: Pieces of matter with the same kind of charge repel each other. Pieces of matter with the same kind of charge attract each other. 2 objects with a positive charge repel each other, as do 2 objects with a negative charge.…

• 605 Words
• 3 Pages
Good Essays
• Satisfactory Essays

Charges q and Q are placed on the x axis at x = 0 and x = 2.0 m, respectively. If q = –40 pC and Q = +30 pC, determine the net flux through a spherical surface (radius = 1.0 m) centered on the origin.…

• 5515 Words
• 23 Pages
Satisfactory Essays
• Satisfactory Essays

Charges of 6 and + 4 nC are 3 m apart. Determine the force they exert on each other, and the electric field at a point midway between them.…

• 1188 Words
• 5 Pages
Satisfactory Essays
• Good Essays

Where Q1 represents the quantity of charge on object 1 (in Coulombs), Q2 represents the quantity of charge on object 2 (in Coulombs), and d represents the distance of separation between the two objects (in meters). The symbol k is a proportionality constant known as the Coulomb's law constant. The value of this constant is dependent upon the medium that the charged objects are immersed in. In the case of air, the value is approximately 9.0 x 109 N • m2 / C2. If the charged objects are present in water, the value of k can be reduced by as much as a factor of 80. It is worthwhile to point out that the units on k are such that when substituted into the equation the units on charge (Coulombs) and the units on distance (meters) will be canceled, leaving a Newton as the unit of force.…

• 595 Words
• 3 Pages
Good Essays
• Satisfactory Essays

Unit –I Introduction to Electrostatics : Laws of electrostatics in vector notation coulomb’s law, Gauss’s law in integral and differential forms. Scalar potential. Surface distribution of charges and dipoles and discontinuity in the field and potential. Poisson’s and Laplace’s equations. Boundary conditions and uniquencess theorem. Potential energy and energy density of electrostatic field. Method of images, potential due to a point charge in presence of a grounded conducting sphere. Multipole expansion for potential, Multipole expansion of the energy in an external field. Dipole-dipole interaction.…

• 1270 Words
• 7 Pages
Satisfactory Essays