Experiment H: Identification of an Unknown Organic Compound
The objective of this lab was straightforward. We were given an unknown compound and we were to perform an IR spectroscopy and as well as NMR spectroscopy. With the IR spectroscopy, I was able to name the functional groups I have on my compound and further confirmed my assumptions by looking at the NMR spectroscopy after. The unknown number I was given was number 203. The molecular weight of the compound was 121. From the molecular weight, I calculated the molecular formula using the rule of 13. The hydrogen deficiency index was also calculated so help construct the structure of my compound. My initial step in figuring out my molecular formula was to use the rule of 13. The molecular weight of my unknown compound was 121. Since the molecular weight is an odd number, Nitrogen is present in the compound. By dividing the molecular weight by 13, we get 9 and remainder of 4. The maximum Carbons the compound had are 9 and 13 Hydrogens. Since Nitrogen was present, I had to add it to my formula and subtract a Carbon and two Hydrogens from the base formula. Hence the final molecular formula would be C8H11N with a HDI of 4. Looking at the IR spectroscopy, there is a sharp peak at around 3000 cm-1, which indicates C-H bonds. At around 1600 cm-1, we see a peak which tells us there are C=C that might corresponds to an aromatic benzene ring, which I proved using the NMR. The Nitrogen is also present on the IR spectroscopy leaving its mark with a peak at around 3200 – 3500 cm-1. Lastly, I finalized my structure using the NMR spectroscopy. With the information I have collected and calculated, the last thing I had to do was to figure out the arrangement of my structure. I knew that the molecular formula of my unknown compound is C8H11N, with 4 HDI. First, at around 1.2ppm, there was a high peak, which indicated my methyl group, and at 2.5ppm, my CH2 group was present. Moving down the spectrum at around 3.5ppm, my...
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