AP Chemistry Unit 2 Notes Stoichiometry You should understand all that is presented in chapter 3 of your text (Zumdahl: Chemistry‚ 8th edition). Some of the highlights are presented below. Atomic Masses (Section 3.1) Nearly every element is made up of atoms of more than one isotope for that element. A few‚ like Be‚ only have one isotope. Others can have a large number of isotopes. Tin (Sn) has ten isotopes. (No pun intended.) Isotopic abundance is determined by the use of
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For example‚ when completing this lab‚ you need to make 2 grams of a product. In this case‚ you need to make 2.00 grams of Copper Phosphate and in order find the grams need for each reactant‚ you need to use Stoichiometry. Stoichiometry is the relationship between the relative quantities of substances taking part in a reaction or forming a compound‚ typically a ratio of whole integers. You need to use numerous conversions‚ atomic weights‚ and mole calculations in order
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out 1.0 g of CaCl2·2H2O and put it into the 100-mL beaker. Add 25 mL of distilled water and stir to form the calcium chloride solution. Use only distilled water since tap water may have impurities that interfere with the experiment. 3. Use stoichiometry to determine how much Na2CO3 you will need for a full reaction. 4. Weigh the calculated amount of Na2CO3 and put it in a small paper cup. Add 25 mL of distilled water and stir to make a sodium carbonate solution. 5. Pour the sodium carbonate
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Stoichiometry Lab Name Questions A. From your balanced equation‚ what is the theoretical yield of your product? Theoretical yield of the CaCO3 is expected to be .69g. B. According to your data table‚ what is the actual yield of the product? The mass of the filter paper was 1.1g‚ and the total mass of the filter paper when dried with the CaCO3 was 1.8 total. Thus the actual yield of the product was .70g. C. What is the percent yield? Percentage yield is actual yield over the theoretical
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Chemistry 1: PROBLEM SET SY 2012/2013 CLASS #: _______________ NAME_________________________________________ SECTION: ______________________ Stoichiometry II - Mole Calculations/ Limiting and Excess Reagent – Lecture Notes 1. Given the balanced equation N2(g) + 3H2(g) 2NH3(g) How many moles of ammonia are produced when 0.60 mol of nitrogen reacts with hydrogen? 2. Given the equation: SiO2 + HF SiF4 + H2O a. Calculate the number of moles HF that would completely react with 2.5 moles of
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Stoichiometry lab By: James Stewart Purpose: To calculate mole ratios Introduction: There are two types of chemical analysis; qualitative analysis which is the identification of a substance present in a material‚ and qualitative analysis which measures the amount of the substance. In this lab‚ you will perform a quantitative analysis of a two-step reaction. Copper(II) oxide will be synthesized from a known mass of copper(II) sulfate pentahydrate. Using the relationship of the balanced equation
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moles-stoichiometry-practice-problems Now you’re ready to use what you know about conversion factors to solve some stoichiometric problems in chemistry. Almost all stoichiometric problems can be solved in just four simple steps: 1.Balance the equation. 2.Convert units of a given substance to moles. 3.Using the mole ratio‚ calculate the moles of substance yielded by the reaction. 4.Convert moles of wanted substance to desired units. These "simple" steps probably look complicated at first
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Name: Brian James|Date:3/10/13| Exp 9: Stoichiometry of a Precipitation Reaction|Lab Section: 73426| Data Tables: Step 3: Show the calculation of the needed amount of Na2CO3 CaCl2.H2O(aq)= m/M =1/147 =0.0068 mol CaCO3(s)=0.0068*1/1 =0.0068 mol CaCO3(s)= CaCO3 (s)= CaCO3 mol *CaCO3 g =0.0068 mol*100.01 g =.68 g Step 4: Mass of weighing dish _0.6_g Mass of weighing dish and Na2CO3 .72_g Net mass of the Na2CO3 .12_g Step 6: Mass of filter paper
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Chapter 4 — Intro—1 1 CHAPTER 3 Topic Scopes: Stoichiometry and Solution Concentration • Molarity‚ molality‚ parts per million & percentage (w/w‚ w/v and v/v) • Stoichiometry calculation • Limiting reactant • Theoretical yield‚ actual yield and percentage yield 1 2 Mole Concept No. of Moles = Molarity (M) • Molarity (molar concentration) is the number of moles of a solute that is contained in 1 liter of solution Mass (g) molar mass (g/mol) No. of Moles = Molarity (mol/L) volume (L) Molarity
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Stoichiometry I. Introduction/ Purpose: Stoichiometry is the study of the quantitative‚ or measurable‚ relationships that exist in chemical formulas and also chemical reactions. The calculations of a stoichiometry problem depend upon balanced chemical equations. The coefficients of the balanced equations indicate the molar ratio of the reactants and products taking part in the reaction. There are three major categories of stoichiometry problems such as mass-mass‚ mass-volume‚ and volume-volume
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