Wire Coursework
GCSE Physics Coursework - Resistance of a Wire Coursework
Introduction (Theory)
In this piece of Coursework I am going to investigate the resistance in a piece of wire. Resistance is the force that slows down the flow of electrons; this can be due to electrons colliding. The total length of the wires will affect the amount of resistance. The longer the wire, the more resistance that there will be. This is also true for thickness of wire; the thinner the wire is the more resistance. Resistance is measured in ohms, the symbol is Ω. The equation for measuring resistance (Ω) is Voltage (V)/Current (I) =Resistance (Ω)
Aim
In this Investigation I am going to investigate how the length of a wire affects resistance. …show more content…
Also i will turn off the power supply before changing the length of the wire
Results
5 Volts wire nickel Chrome swg
Length amps Volts ResistanceΩ
50cm 0.46 1.77 3.85Ω
45cm 0.46 1.62 3.52Ω
40cm 0.46 1.43 3.11Ω
35cm 0.46 1.29 2.80Ω
30cm 0.46 1.21 2.63Ω
25cm 0.46 0.90 1.96Ω
20cm 0.46 0.80 1.74Ω
15cm 0.46 0.70 1.52Ω
10cm 0.46 0.40 0.87Ω
5cm 0.46 0.22 0.47Ω
Length amps volts ResistanceΩ
50cm 0.46 1.82 3.96 Ω
45cm 0.46 1.59 3.46 Ω
40cm 0.46 1.33 2.89 Ω
35cm 0.46 1.28 2.78 Ω
30cm 0.46 1.2 2.61 Ω
25cm 0.46 0.91 1.98 Ω
20cm 0.46 0.75 1.63 Ω
15cm 0.46 0.61 1.33 Ω
10cm 0.46 0.45 0.98 Ω
5cm 0.46 0.24 0.52 Ω
r average volts average resistance
1.61 3.5
1.29 2.80
0.95 2.07
0.83 1.80
0.73 1.59
0.41 0.89
0.3 0.65
0.21 0.46
0.09 0.2
0.03 0.07
Conclusion Having performed the investigation, the following conclusions are: As predicted, the longer in length the bigger the resistance for example at 5cm the resistance is 0.52 Ω and 50cm the resistance was 3.96 Ω. This can be clearly said for the 1st,2nd and average
Introduction (Theory)
In this piece of Coursework I am going to investigate the resistance in a piece of wire. Resistance is the force that slows down the flow of electrons; this can be due to electrons colliding. The total length of the wires will affect the amount of resistance. The longer the wire, the more resistance that there will be. This is also true for thickness of wire; the thinner the wire is the more resistance. Resistance is measured in ohms, the symbol is Ω. The equation for measuring resistance (Ω) is Voltage (V)/Current (I) =Resistance (Ω)
Aim
In this Investigation I am going to investigate how the length of a wire affects resistance. …show more content…
Also i will turn off the power supply before changing the length of the wire
Results
5 Volts wire nickel Chrome swg
Length amps Volts ResistanceΩ
50cm 0.46 1.77 3.85Ω
45cm 0.46 1.62 3.52Ω
40cm 0.46 1.43 3.11Ω
35cm 0.46 1.29 2.80Ω
30cm 0.46 1.21 2.63Ω
25cm 0.46 0.90 1.96Ω
20cm 0.46 0.80 1.74Ω
15cm 0.46 0.70 1.52Ω
10cm 0.46 0.40 0.87Ω
5cm 0.46 0.22 0.47Ω
Length amps volts ResistanceΩ
50cm 0.46 1.82 3.96 Ω
45cm 0.46 1.59 3.46 Ω
40cm 0.46 1.33 2.89 Ω
35cm 0.46 1.28 2.78 Ω
30cm 0.46 1.2 2.61 Ω
25cm 0.46 0.91 1.98 Ω
20cm 0.46 0.75 1.63 Ω
15cm 0.46 0.61 1.33 Ω
10cm 0.46 0.45 0.98 Ω
5cm 0.46 0.24 0.52 Ω
r average volts average resistance
1.61 3.5
1.29 2.80
0.95 2.07
0.83 1.80
0.73 1.59
0.41 0.89
0.3 0.65
0.21 0.46
0.09 0.2
0.03 0.07
Conclusion Having performed the investigation, the following conclusions are: As predicted, the longer in length the bigger the resistance for example at 5cm the resistance is 0.52 Ω and 50cm the resistance was 3.96 Ω. This can be clearly said for the 1st,2nd and average