Stoichiometry Lab Report
Stoichiometry lab 1
Purpose: The purpose of this lab is to find the limiting reactant, also to find the percentage yield and percentage purity of the reaction that happens between Calcium Chloride and Sodium Carbonate. The other purpose was to know how the reaction can be balanced and created.
Hypothesis: In this lab we are going to see a precipitation reaction. This is a reaction where two soluble salts Sodium Carbonate and Calcium Chloride are added together and the result is the precipitation of single Product while the other product remains in solution. This means by using the moles in this lab we could find the limiting reactant, percentage yield and the percent purity
Materials:
* Electronic Scale * Sodium Carbonate * Calcium Chloride * Wayne Paper …show more content…
Stir the reaction mixture for a few minutes.
10. Obtain a piece of filter paper, determine its mass. (Record mass)
11. Set up the apparatus (funnel, ring stand, filter paper) for filtration while the precipitate in the beaker settles.
12. Place the empty beaker under the funnel and transfer the reaction mixture to the filter paper. (Careful! Do not allow reaction mixture to rise above the rim of the filter paper)
13. Add approximately 10 mL of distilled water to the reaction mixture remaining in the beaker. Transfer the diluted reaction mixture to the filter paper. 14. Repeat step #13. (Observe the color of the filtrate)
15. Label a watch-glass with: your name, date, and CaCO3 .
16. When the filtration process is complete, place the filter paper and the solid CaCO3 product on the labeled watch-glass.
17. Leave your labeled watch glass out for drying overnight (low temperature).
18. Record the mass of the dry filter paper + CaCO3. Record mass
Questions and answers for Limiting Reactant
1. The mole of Na2CO3 used is n= m÷M
= 3.01g÷105.99 =0.028mol
2. The moles of CaCO3 n= m÷M
= 4g÷100.09g/mol =0.040 mol
3a: mass of CaCO3 produced is m=n×M = 0.028mol×100.09g/mol
Purpose: The purpose of this lab is to find the limiting reactant, also to find the percentage yield and percentage purity of the reaction that happens between Calcium Chloride and Sodium Carbonate. The other purpose was to know how the reaction can be balanced and created.
Hypothesis: In this lab we are going to see a precipitation reaction. This is a reaction where two soluble salts Sodium Carbonate and Calcium Chloride are added together and the result is the precipitation of single Product while the other product remains in solution. This means by using the moles in this lab we could find the limiting reactant, percentage yield and the percent purity
Materials:
* Electronic Scale * Sodium Carbonate * Calcium Chloride * Wayne Paper …show more content…
Stir the reaction mixture for a few minutes.
10. Obtain a piece of filter paper, determine its mass. (Record mass)
11. Set up the apparatus (funnel, ring stand, filter paper) for filtration while the precipitate in the beaker settles.
12. Place the empty beaker under the funnel and transfer the reaction mixture to the filter paper. (Careful! Do not allow reaction mixture to rise above the rim of the filter paper)
13. Add approximately 10 mL of distilled water to the reaction mixture remaining in the beaker. Transfer the diluted reaction mixture to the filter paper. 14. Repeat step #13. (Observe the color of the filtrate)
15. Label a watch-glass with: your name, date, and CaCO3 .
16. When the filtration process is complete, place the filter paper and the solid CaCO3 product on the labeled watch-glass.
17. Leave your labeled watch glass out for drying overnight (low temperature).
18. Record the mass of the dry filter paper + CaCO3. Record mass
Questions and answers for Limiting Reactant
1. The mole of Na2CO3 used is n= m÷M
= 3.01g÷105.99 =0.028mol
2. The moles of CaCO3 n= m÷M
= 4g÷100.09g/mol =0.040 mol
3a: mass of CaCO3 produced is m=n×M = 0.028mol×100.09g/mol