This is because the higher the voltage‚ the stronger the energy produced in the coil around the metal rod. EXPERIMENT (PROCEDURE): Materials used: 6 volt battery Coils Partner(s) to hold coil and metal rod/battery Metal rod Paperclips Worksheet to record data There are eight steps to the procedure: Get a 6 volt battery Get a long or short coil depending on your trial Get metal rod Get paperclips Wrap coil around metal rod (10‚ 20‚ 30‚ 40 or 50 times for
Premium Volt Voltage Scientific method
resistor board -Extech instruments (0-18 Volts) Power Supply Procedure: A circuit connecting the resistor board‚ the voltmeter and the milli-ammeter is assembled. The 20 milli-ampere range is selected on the ammeter and the 20V on the voltmeter. The power cord is then plugged into an electrical outlet and the unit is turned on. The experiment begins at 15 volts. The voltage and current are both recorded and these steps are repeated successively in two volt increments. A graph of I as a function of
Free Ohm's law Electric current Electrical resistance
applied to its ends. How much current flows in the wire depends on the voltage but also on the resistance (R) of the wire. A higher resistance yields a lower current for a given voltage. (I= V/R) This is known as Ohm’s Law‚ where V is measured in volts‚ I is measured in amperes‚ and R is measured in ohms. Electrical engineers have to build devices that control the flow of electrons. Changing the shape or choosing different materials with different resistance are ways that they do this. A resistor
Premium Ohm's law Electrical resistance Resistor
value) Calculated Measured Calculated Measured Calculated Measured vR1(t) vR2(t) vR3(t) vR4(t) vsursă(t) B) Construct the circuit shown in Fig.1. using the values below: R1=1kΩ‚ R2=2kΩ‚ R3=2kΩ‚ R4=1kΩ. a. Set the power supply (Vsource ) to 5 Volts. b. Accurately measure all voltages and currents in the circuits using a Digial Multi-Meter. c.
Premium Measurement Alternating current Voltage
An experiment to investigate the factors which affect Resistance in a wire What is resistance? A potential difference (V) applied across a wire of length (l)‚ there is in the conductor‚ an electric field (E). In this electric field the free electrons are not however under continuous acceleration (Ee/m). This is because they repeatedly collide with the moderately massive vibrating atoms losing their kinetic energy. The vibrating atoms having gained this kinetic energy now vibrate more. The resulting
Premium Electric charge Electricity Electron
ALL ABOUT AMPERE MACHINE ABEGAIL LALOMA CARLA DUMALE AMPERE Metric (SI) unit of electrical current. One ampere is the amount of current flowing with an electromotive force of one Volt in a circuit having a resistance of one Ohm. Named after the French mathematician and physicists Andre Marie Ampere who discovered the basic laws of electromagnetism. AMPERE’S FORCE LAW Ampere’s force law states that there is an attractive or repulsive force between two parallel wires carrying an electric
Premium Electromagnetism Volt Electric current
Potatoes May Power The Batteries Of The Future Friday‚ June 18‚ 2010 - by Ray Willington Oh‚ batteries. Can’t live with ’em‚ can’t live without ’em. It sounds like a power ballad‚ but it’s the story of our lives around here. We’ve been dealing with lofty promises and batteries that kick the bucket far too early‚ for years now. And the fact that we’re still dealing with lead-acid batteries is sort of a baffling thing to wrap one’s mind around. But all of that just might be changing. We won’t get
Premium Battery Electrochemistry Electrode
25 ohm resistor has an average power of 400 watts. Determine the maximum value of the current if it is a (a) sinusoidal‚ (b) triangular. 2. Determine the effective value Vrms of the voltage function given by v(t) = 100+25 sin 3wt + 10 sin 5wt volts. 3. What average power results in a 25 ohm resistor when it passes a current i(t) = 2+3 sin wt +2 sin2wt + 1 sin 3wt amperes. 4. Calculate Irms if i(t) = 50 + 40 sin wt amperes. 5. Calculate Irms if i(t) = 150 + 50 sin wt + 25 sin
Premium Phase Rectifier Alternating current
the first dial pointer (right hand). Rs = gear ratio = the number of revolution of the disk for one revolution of the first point CTR = current transformer ratio VTR = voltage transformer ratio Example #1: A G.E.‚ three phase‚ three wire‚ 120 volts‚ type VM-63-A‚ Form 5A‚ Class 20‚ KWh meter indicates Kh of 2.4 at its nameplate and register ratio of 166-2/3 was installed at 13.2 KV wye grounded system having a current transformer of 25:5 ratio. Determine the following; a). The internal multiplier
Premium Energy Trigraph Volt
Materials 5 meters of varnish insulated copper wire with diameter 0.5mm PVC pipe- 300mm length 3- 1.5 volt batteries with casing 3- jumper wires with crocodile clips Multimeter Scissors Infrared Thermometer 1 roll of insulation tape Procedure 1. Wind the wire around the PVC pipe. Fix the ends of the wires to the insulation tape. Remove about 3 cm. of insulation from the wire using the tips of the paper knife. Measure the resistance of the wire using the ohm
Premium Electric current Volt Copper