Titration CalculationsBefore you go any further‚ check that you can do the following… Calculate: Relative molecular masses from a given chemical formula Calculate: Number of Moles from the mass/RMM equation Manipulate: The number of moles equation to get the form you require. When you are confronted by a Titration calculation the first rule is: DON’T PANIC! The Second rule is read through the question very carefully.The Third rule is read through the question carefully again! We are now going to
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hydrated copper (II) sulfate. Exactly this salt is used in the described experiment. RESEARCH QUESTIONWhat is the number of moles of water of crystallization associated with one mole of copper (II) sulfate‚ in the hydrate CuSO4 * xH2O (s)? The independent variable in this experiment is sample thermal treatment ( heating and cooling) and the dependent variable is the number of moles of water of crystallization. A number of other variables can affect the final result of the experiment: whether the crucible
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The lab in which we conducted last Tuesday was an analysis of a hydrate and what happens to it when it is heated. A hydrate is a crystalline compound which water molecules are chemically bound to it. In the lab‚ we were to analyze the difference in grams of the hydrate and the anhydrate. An anhydrate is the crystalline compound without the water molecules bound to it. During our lab‚ we were to heat up the crucible‚ the crucible with hydrate‚ and the crucible with an anhydrous and write down each
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the mass of water and dividing it by the total mass of the hydrate and then multiplying that answer by 100%. The number of moles of water in a hydrate was determined by taking the mass of the water released and dividing it by the molar mass of water. The number of moles of water and the number of moles of the hydrate was used to calculate the ratio of moles of water to moles of the sample. This ratio was then used to write the new and balanced equation of the dehydration process. The sample was then
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Thermodynamics- Enthalpy of Reaction and Hess’s Law Objectives: 1. To calculate the heat of reaction of a given reaction using the concepts derived from Hess’s Law. Pre-lab Questions: 1. Define Heat of Reaction. The enthalpy change associated with the completion of a chemical reaction. 2. Define Specific Heat. The energy it takes to raise the temperature of 1 gram of a substance by one degree Celsius. 3. Calculate the heat of reaction assuming no heat is lost to the calorimeter. Use correct
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Post-Lab Questions 1. Using the information provided in the Introduction and your observations from Part 1‚ hypothesize as to the type of electrolyte the following solutions would be. Justify the hypothesis from a chemical standpoint. a. Aqueous Sodium Hydroxide—NaOH (aq) is a very strong base‚ which will completely disassociate into Na+ and OH- ions‚ which would make it a very strong electrolyte. Chemical reaction of the disassociation of Sodium Hydroxide: NaOH (aq)Na+ (aq)+ OH-(aq)
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Purpose=The purpose of this lab was to combine reactants‚ which we would pick ourself‚ to make 2 grams of Copper Phosphate and another product. Background: Chemistry is the branch of science that deals with the identification of the substances of which matter is composed. Chemistry has to do with many things we use today. For example‚ fireworks are made by the chemical combining magnesium‚ titanium‚ copper‚ aluminum‚ strontium‚ or other periodical elements. Things also like making plastic‚ jewelry
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References 1. Potter and Perry 2. Nursing diagnosis cards by Taylor and Ralph 3. Mosby’s Nursing skills (website) 4. Clinical nursing skills (Smith) Diagnosis 2 (Maslow’s hierarchy of needs : safety) Impaired physical mobility related to Open Reduction‚ Internal Fixation (ORIF). As evidence by Pt. having intrameduillary interlocking rods in right and left bilateral femurs (3). Physician order pt. to remain in bed and catheter placed in patient’s bladder‚ which leads to and
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COMPUTER CONCEPTS NATIONAL ASSOCIATION FOR THE BLIND NEW DELHI Computer Concepts Hardware & software concepts explained for persons with low or no vision for the students of Intel Technology Training Lab at National Association for the Blind‚ New Delhi Produced and Published by National Association for the Blind Sector-5‚ R.K Puram‚ New Delhi E-mail: nab@vsnl.com First Edition October 2001 Reprint: February 2005 TABLE OF CONTENTS
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esterification reaction that was carried out in this lab is shown in figure 1. It worth mentioning that the by-product of such reaction is water. In organic chemistry‚ the reaction in which water molecule is released is known as condensation reaction (Hornback‚ 2006). Figure1 is drawn using Chem Sketch software. a) b) Figure 1: Typical Fischer esterification reaction (a) in comparison to the specific esterification reaction used in this lab (b) The reaction can also be categorized in terms of
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