describe the sampling technique for the analysis of DO in water sample. In the Winkler method‚ or Iodometry‚ the dissolved oxygen is made to react with Iodide ion to yield Iodine which will be titrated afterwards with thiosulfate. Iodine is a moderately strong oxidizing agent making it useful for titrating strong reducing agents like dissolved oxygen. Iodide ion‚ on the other hand‚ is a weak reducing agent‚ and is the basis of determining the amount of the strong oxidizing agents like the oxygen in the
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reaction with respect to the Hydrogen Peroxide (H2O2)‚ Potassium Iodide (KI) and the Sulphuric Acid (H2SO4) by the use of an Iodine clock reaction. Calculate the rate constant‚ mechanism and equation Find the effects of temperature on the rate of reaction The effects of a catalyst on the rate of reaction Find the activation enthalpy (Ea) of the reaction‚ with and without a catalyst Background: Hydrogen Peroxide and Potassium Iodide equation: H2O2 + 2I - + 2H + I2 +
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Illustrating the Oxidation States of Mn & V © KCl http://hk.geocities.com/fatherofchemistry Procedure © KCl http://hk.geocities.com/fatherofchemistry Discussion Part A: Making Mn(VI) from Mn(VII) and Mn(IV) 1.> Explain why only one of the three mixtures reacted to give green Mn(VI). [ANS] By Le Chatelier’s Principle‚ only the alkaline medium will shift the equilibrium to right and yield green MnO42-. 2.> What happened when acid was added
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Process Module 1 19 Aug 1999 SRI Consulting Process Summary This Aspen Plus model simulates the production of acetic acid by low pressure methanol carbonylation in the presence of a heterogeneous rhodium (Rh) catalyst and the promoter methyl iodide. It is intended to resemble the Chiyoda/UOP Acetica™ process‚ a novel heterogeneous methanol process for the production of acetic acid. This technology is based on a heterogeneous Rh catalyst in which the active Rh complex is chemically immobilized
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out the effect of ethanol by carrying out the iodine clock reaction with and without ethanol present and the results will be compared to draw a conclusion. A2 AIMS: 4. Investigate the order of reaction with respect to hydrogen peroxide‚ iodide and acid. The goal of this aim is to find out what order of reaction each chemical produced by making a graph for each of the reactants and analysing the line of best fit. 5. Investigate the rate equation‚ rate constant and possible mechanism
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Top of Form Bottom of Form Chemical Compound Formulas Chemistry is the study of the composition of matter and its transformation. A substance can be considered matter with definite properties that establishes its identity. The tremendous number of chemical compounds has been categorized into numerous categories. A broad classification distinguishes between inorganic and organic compounds. Organic compounds are carbon based. Inorganic compounds exclude compounds exclude compounds based on carbon
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Peroxide by Potassium Iodide Brief Description: Two solutions are mixed resulting in an eruption of foam resembling a huge stream of toothpaste. This is the classic “Elephant Toothpaste” reaction. Purpose/Goal: Procedure presents an example of a catalyzed reaction. Explanation of Experiment: The rapid evolution of oxygen gas is produced by the following reaction: 2 H2O2 (aq) = 2 H2O (l) + O2 (g) + heat The decomposition of hydrogen peroxide in the presence of iodide ion occurs in two
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Iodine clock reaction This is the hydrogen peroxide/ potassium iodide ‘clock’ reaction. A solution of hydrogen peroxide is mixed with one containing potassium iodide‚ starch and sodium thiosulfate. After a few seconds the colourless mixture suddenly turns dark blue. This is one of a number of reactions loosely called the iodine clock. It can be used as an introduction to experiments on rates / kinetics. 63 Lesson organisation This demonstration can be used at secondary level as an introduction
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atoms in (NH4)2SO4? (1) 10 (2) 11 (3) 14 (4) 15 22. Write the correct formula for the following binary ionic compounds. (a) Lithium fluoride LiF (b) Calcium oxide CaO (c) Aluminum nitride AlN (d) Beryllium chloride BeCl2 (e) Potassium iodide KI (f) Aluminum oxide Al2O3 23. Write the correct formula for the following binary molecular compounds. (a) Carbon monoxide CO (b) Boron tribromide BBr3 (c) Sulfur hexafluoride SF6 (d) Carbon dioxide CO2 (e) Carbon tetrabromide CBr4
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double displacement reaction between the solutions Lead (II) Nitrate (PbNO3) and Potassium Iodide (KI). It is important to obtain amounts of Lead (II) Nitrate and Potassium Iodide as close to 1.44g as possible. This reaction creates Lead (II) Iodide and Potassium Nitrate. The precipitate during this reaction is Lead (II) Iodide. The balanced equation is Pb(NO3)2 + 2KI= PbI2 + 2KNO3. In this lab the Lead (II) Iodide is separated from the solution and collected so it can be weighed for a mass. Potassium
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