This article is about quadratic equations and solutions. For more general information about quadratic functions‚ see Quadratic function. For more information about quadratic polynomials‚ see Quadratic polynomial. A quartic equation is a fourth-order polynomial equation of the form. A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and (the first power of) a single variable. Monomial – is a polynomial with only one term. Binomial
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The Triathlon Equation Those who are interested in doing the triathlon often do not know how to do their training effectively. First you must build a base. This means you must start with endurance only a few times a week‚ progressing to 6 days a week with one rest day. You should only do 1 activity a day‚ with 1 brick workout a week. A brick workout simulates what it feels like to do two of the activities back to back so that it is easier come race day. Brick examples include: 1.) swim 300m
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Development of an Equation Maggie Purpose: Investigate a chemical reaction using lab procedures and observations. Then‚ find a pattern of reactivity and explain the findings using a chemical equation and particle diagram. Procedure: Refer to: Department of Chemistry‚ The Ohio State University. "Development of an Equation." General Chemistry 1210 Laboratory Manual. Vol. 2013-2014. Plymouth: Hayden-McNeil. 32-35. Data/Results: Part A: In the potassium iodide solution‚ I think there were potassium
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direction of the jetstream. The return trip against the jetstream took four hours. What was the jet’s speed in still air and the jetstream’s speed? 3 ) These circles are identical. What is the value of x ? 4 ) Solve for x using these two equations: 2x + 6 = y; y - x = 2 5 ) The perimeter and the area of this shape are equal. What is the value of x? 6) Shobo’s mother’s present age is six times Shobo’s present age . Shobo’s age five years from now will be one third of his mother’s present
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Kuta Software - Infinite Algebra 2 Name___________________________________ Writing Equations of Circles Date________________ Period____ Use the information provided to write the standard form equation of each circle. 1) 8 x + x 2 − 2 y = 64 − y 2 2) 137 + 6 y = − y 2 − x 2 − 24 x 3) x 2 + y 2 + 14 x − 12 y + 4 = 0 4) y 2 + 2 x + x 2 = 24 y − 120 5) x 2 + 2 x + y 2 = 55 + 10 y 6) 8 x + 32 y + y 2 = −263 − x 2 7) Center: (−11‚ −8) Radius: 4 8) Center: (−6‚ −15) Radius: 5 9) ( x − 16) 2
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Prefixes and Equations 1mL = -1x10 3 L = 0.001L 1 kilometers (1km) = 1000m (1x103 m) 1 kilometer (1KL) = 1000L (1x10 3 L) Prefixes Symbol Numerical Value Scientific Notation Equality Kilo | K | 1000 | 103 | 1km = 1x103m 1m = 1x10-3Km | Mega | M | 1 000 000 | 106 | 1Mg = 1x106g1g = 1x10-6Mg | Giga | G | 1 000 000 000 | 109 | 1Gm = 1x109m1m = 1x10-9Gm | Tera | T | 1 000 000 000 000 | 1012 | 1Ts = 1x1012s1s = 1x10-12Ts | Deci | d | 0.1 | 10-1 | 1dL = 1x10-1L1L = 1x101dL (10dL) | *These
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that is written first and negative half is written second. Subscripts are small numbers to the lower right of a symbol. They the number of atoms of that element in the compound. Coefficients are large numbers to the left of formulas in chemical equations. They represent the ratio of molecules of each substance involved in a chemical reaction. Weight Percentage is a percentage based on weights. Mole percentage is a percentage based on the numbers of atoms or moles. Formula units is the simplest
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Chapter 7: Intro to Sampling Distributions Sampling Error = x̄ - μ Z-Values for a sampling distribution of x̄ : Z = Z-Values adjusted with Finite Population Correction Applied if: the sample is large relative to the population (n is greater than 5% of N) and sampling Is without replacement Z = Using the Sampling Distribution for Means Compute the Sample Mean Define the sampling distribution μx̄ = Define the probability statement of interest P(z30 will give sampling distribution that
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Kinematics / Projectiles x =?vt ?v = (v + vo)/2 v = vo + at x = vot + ½at2 v2 = vo2 + 2ax y =?vt ?v ’ ½(vo + v) v = vo – gt y = vot – ½gt2 v2= vo2 – 2gy R = (v02/g)sin(2θ) Forces Fnet = ma Fgravity = mg Ffriction ≤ μsN Ffriction = μkN Circular Motion Fnet = mv2/r ac = v2/r v = 2πr/T f = 1/T T = 1/f Gravitation F = GM1M2/R2 g = GM/R2 T2/R3 = 4π2/GM = constant GM = Rv2 Energy W = Fdcosθ KE
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The Vector equation of a plane To find the vector equation of a plane a point on the plane and two different direction vectors are required. The equation is defined as: where a is the point on the plane and b and c are the vectors. This equation can then be written as: The Cartesian equation of a plane The cartesian equation of the plane is easier to use. The equation is defined as: One of the advantages to writing the equation in cartesian form is that we can easily find the normal
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