light intensity onto the leaf’s surface and the surface area of the leaf. Hypothesis I think the light intensity could affect the surface area in the following way: ·A higher light intensity could make the surface area of the leaf larger. The reason I think a higher light intensity could make the surface area larger is the fact that there would be a larger amount of chlorophyll‚ containing chloroplasts‚ for photosynthesis. By having leaves of a larger surface area‚ there would be a much more
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NFPA 255 Standard Method of Test of Surface Burning Characteristics of Building Materials 2000 Edition --```‚‚‚-`-`‚‚`‚‚`‚`‚‚`--- National Fire Protection Association‚ 1 Batterymarch Park‚ PO Box 9101‚ Quincy‚ MA 02269-9101 An International Codes and Standards Organization Copyright National Fire Protection Association Provided by IHS under license with NFPA No reproduction or networking permitted without license from IHS Not for Resale The Standard is downloaded from www.bzfxw.com Standard
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Table of results Surface area to volume ratio Time taken for HCL acid to diffuse (seconds) 14 38 9 90 7.3 139 6.5 178 6 185 3. Do your results support your hypothesis‚ use date from your table and graph to support your answer‚ you should also identify any anomalous results. My hypothesis was ‘as the surface-area-to-volume ratio decreases the diffusion rate increases’ my results support my hypothesis‚ because in my table of results when the surface area to volume ratio is at 14 the diffusion
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FHSC1014 Mechanics FOUNDATION IN SCIENCE PRACTICAL: Practical 3 TITLE: To investigate the trajectory of a small ball as it rolls off a surface which is inclined to the horizontal DATE: 25/6/2014 NAME: Yeoh Boon Khai ID: 1403449 GROUP: P8 LECTURER’S NAME: Mr Zoheir Title: Objective: To investigate the trajectory of a two dimensional motion. Apparatus and Materials: 1. Ramp 2. Wooden block 3. Pendulum bob 4. Plumb line 5. Steel
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INTERNATIONAL BACCALAUREATE BIOLOGY INTERNAL ASSESMENT DATA COLLECTION AND PROCESSING CONCLUSION AND EVALUATION RELATIONSHIP BETWEEN SURFACE AREA AND THE VOLUME OF A CELL‚ HOW IT AFFECTS THE RATE OF DIFFUSION Nazirul Ibrahim 04.10.2011 DATA COLLECTION AND PROCESSING We have determined the following variables: * dV- the time for the color indicator phenolphthalein to reach the center of the cube (diffusion) * iV- the size of the cube * cV- the amount of Sodium
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potatoes reacting with Hydrogen Peroxide. In particular I will investigate the effects of changing the surface area of a potato when added to Hydrogen Peroxide. This is because‚ when increasing the surface area of the potatoes it will increase the rate of reaction because there will be more surface area on which particles from the potato and the Hydrogen Peroxide will collide on‚ and with more surface area there would be more particles carrying kinetic energy‚ and by carrying more kinetic energy the
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DISTANCE CALCULATION Because of the near-spherical shape of the Earth (technically an oblate spheroid) ‚ calculating an accurate distance between two points requires the use of spherical geometry and trigonometric math functions. However‚ you can calculate an approximate distance using much simpler math functions. For many applications the approximate distance calculation provides sufficient accuracy with much less complexity. The following approximate distance calculations are relatively simple
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The atmosphere above the surface of Mars is about 100 times less dense than the atmosphere of Earth. The Martian atmosphere is dense enough to support a weather system that includes clouds and winds. According to experts‚ Mars ’ roller coaster-like weather is more chaotic and unpredictable than scientists first thought. At times‚ the sky can appear pink and cloudless‚ filled with windblown dust raised from the rusty Martian surface. Tremendous dust storms sometimes rage over the entire planet. Most
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Global NF3 and F2 market is expected to reach USD 1‚266.8 million and USD 17‚526.0 million respectively by 2020‚ according to a new study by Grand View research‚ Inc. Growing demand for LCD televisions‚ owing to their low power consumption‚ is expected to drive NF3 demand in silicon wafer cleaning applications. F2 demand for uranium enrichment is expected to surge in line with uranium production as a result of growth in nuclear power production. Semiconductor chips were the largest application
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Anna S BA 3103 Critical Analysis Paper Sharp Sharp’s third quarter results showed very disappointing performance. The company reported a ¥249.1 billion ($3.12 billion) loss. Moreover‚ it is forecasting a ¥450 billion‚ or $5.6 billion‚ loss for the fiscal year through 2013. Apparently‚ the company is burning through more cash than it is generating and having difficulty in securing short-term financing. Also‚ the company is considering selling some holding in other companies and office building
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