find the dimensions of the room. (iv) A river 2m deep and 45m wide is flowing at the rate of 3 km per hour. Find the volume of water that runs into the sea per minute. (v) A closed cylinder has diameter 8cm and height 10cm. Find its total surface area and volume. (vi) The volume of a metallic cylinder pipe is 748cm3 . Its length is 14 cm and external diameter 18cm. Find its thickness. (vii) A cylindrical bucket‚ 28cm in diameter 72cm high is full of water. The water is emptied into
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Surface area / Volume ratio Experiment Introduction: The surface area to volume ratio in living organisms is very important. Nutrients and oxygen need to diffuse through the cell membrane and into the cells. Most cells are no longer than 1mm in diameter because small cells enable nutrients and oxygen to diffuse into the cell quickly and allow waste to diffuse out of the cell quickly. If the cells were any bigger than this then it would take too long for the nutrients and oxygen to diffuse into
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particles within the same body; adhesion is the interaction between the surfaces of different bodies. The force of cohesion in gases can be observed in the liquefaction (condensation) of a gas‚ which is the result of a number of molecules being pressed together to produce forces of attraction high enough to give a liquid structure. Cohesion in liquids is reflected in the surface tension caused by the unbalanced inward pull on the surface molecules‚ and also in the transformation of a liquid into a solid
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Alveolar Surface Tension and Surfactant in the Compliance of the Lungs Alveolar surface tension is important for the lungs to function efficiently. Surfactant is a lining in the alveoli made of lipids and proteins. Surface tension of the alveoli are important to keep the alveoli shape‚ but surfactant is needed to regulate surface tension. Also surface tension promotes movement of fluids across the alveolar membrane‚ therefore the surfactant also regulates the movement of fluids. Attraction of
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Does Soap Affect the Surface Tension of Water? Background: Surface tension refers to water’s ability to "stick to itself". Surface tensioncan be measured and observed by dropping water (drop by drop) onto a penny. Thenumber of water drops that can fit on a penny will surprise you. Question: How does soap affect the water’s surface tension? Hypothesis: I think that the surface tension of soapy water will be less than that of freshwater because H 2 0 has strong polar bonds‚ and when water is mixed
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[Type text] [Type text] [Type text] _An experiment on the effect of surface area to volume ratio on the rate of osmosis of Solanum tuberosum L._ BACKGROUND A cell needs to perform diffusion in order to survive. Substances‚ including water‚ ions‚ and molecules that are required for cellular activities‚ can enter and leave cells by a passive process such as diffusion. Diffusion is random movement of molecules in a net direction from a region of higher concentration to a region of lower concentration
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cut 3 potato cubes using the dimensions from above. 2. Obtain TEACHER’S SIGN-OFF BEFORE you proceed! 3. Submerge the potato cubes (cells) into the iodine solution for 20 minutes. 4. While you are waiting for 10 minutes‚ calculate the surface area‚ volume‚ and surface area to volume ratio for each of the 3 potato cubes (cells). AFTER 10 Minutes 5. Carefully remove the potato cubes (cells) from the iodine solution and place them on absorbent paper towels. 6. Cut each cell in half and observe
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Surface Area to Volume Ratio and the Relation to the Rate of Diffusion Aim and Background This is an experiment to examine how the Surface Area / Volume Ratio affects the rate of diffusion and how this relates to the size and shape of living organisms. The surface area to volume ratio in living organisms is very important. Nutrients and oxygen need to diffuse through the cell membrane and into the cells. Most cells are no longer than 1mm in diameter because small cells enable nutrients and oxygen
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To investigate the relationship between surface area : volume ratio and heat loss. INTRODUCTION: The aim of this experiment is to investigate and find the relationship between heat loss (of water) and surface area to volume ratio of animals. To investigate this‚ we are going to use three flasks of different volume (as the equivalent the animals) and thus different surface areas filled with water. BACKGROUND: Surface Area : Volume Ratios We will be using the following formula for calculating
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CHAPTER 1 INTRODUCTION 1.1 Background Urban centers‚ or sometimes simply cities‚ have higher population density along with various infrastructure features (Li‚ 2010). Such areas are supporting an increasing population growth rate which is posing a significant impact to the quality of infrastructures being provided (Department of Environment and Resource Management‚ 2010). As stormwater drainage system is one of the vital infrastructures in urban centers‚ it encounters degradation that brings
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